题目内容
如右图,
平分
于点
,点
是射线
上的一个动点,若
,则
的最小值为
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A.1 | B.2 | C.3 | D.4 |
D
试题分析:作PD⊥OM于点D,由点到直线距离的定义可知线段PD的长就是点P到射线OM的最短距离,再根据角平分线的性质可知PQ=PA=4.
过点P作PD⊥OM于点D,则线段PD的长就是点P代射线OM的最短距离,
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∵OP平分∠MON,PA⊥ON于点A,PA=4,
∴PQ的最小值=PD=PA=4.
故选D.
点评:解题的关键是熟练掌握角平分线的性质:角平分线上的点到角的两边距离相等.
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