题目内容

(本题10分)(1)如图1,已知∠AOB,OA=OB,点E在OB边上,四边形AEBF 是平行四边形,请你只用无刻度的直尺在图中画出∠AOB的平分线.(保留作图痕迹,不要求写作法)

(2)如图2,在10×10的正方形网格中,点A(0,0)、B(5,0)、C(3,6)、D(-1,3),

①依次连结A、B、C、D四点得到四边形ABCD,四边形ABCD的形状是     ▲     .

②在x轴上找一点P,使得△PCD的周长最短(直接画出图形,不要求写作法);

此时,点P的坐标为     ▲     ,最短周长为     ▲     .

 

解:(1)如图所示;················································································· 2分

(2)①等腰梯形;·············································································· 4分

②P(,0)·············································································· 6分

(其中画图正确得2分)··················································· 10分

 

 

 

 

 

 

 

 

 


解析:略

 

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