题目内容
(2013•苏州一模)先化简,再求值:(
-
)÷
,其中x=
.
| x2 |
| x+1 |
| 1 |
| x+1 |
| x2-x |
| 2 |
| 2 |
分析:先将括号内的部分通分,再将分式分子、分母因式分解,化简后将x=
代入即可求解.
| 2 |
解答:解:原式=
•
=
•
=
,
当x=
时,原式=
=
.
| x2-1 |
| x+1 |
| 2 |
| x2-x |
=
| (x-1)(x+1) |
| x+1 |
| 2 |
| x(x-1) |
=
| 2 |
| x |
当x=
| 2 |
| 2 | ||
|
| 2 |
点评:本题考查了分式的化简求值,熟悉通分、约分和分母有理化是解题的关键.
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