题目内容
(1)计算:
•
÷
(2)计算:
-
+(2-
)2
(3)计算:2a
-(
-2ab
)
6 |
2 |
3 |
(2)计算:
12 |
20 |
3 |
(3)计算:2a
3ab2 |
b |
6 |
27a3 |
|
(1)原式=
÷
=
=2;
(2)原式=2
-2
+4-4
+3
=7-2
-2
;
(3)原式=2ab
-
+ab
=
ab
.
12 |
3 |
=
12÷3 |
=2;
(2)原式=2
3 |
5 |
3 |
=7-2
3 |
5 |
(3)原式=2ab
3a |
ab |
2 |
3a |
3a |
=
5 |
2 |
3a |
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