ÌâÄ¿ÄÚÈÝ
½«Ê¢ÓÐ50gÏ¡ÑÎËáµÄÉÕ±·ÅÔÚÌìƽÉÏ£¬È»ºó°Ñ¹ýÁ¿µÄ̼ËáÄƼÓÈ뵽ʢÓÐÏ¡ÑÎËáµÄÉÕ±ÖУ¬ÒԲⶨϡÑÎËáÖÐHClµÄÖÊÁ¿·ÖÊý¡£ÒÑÖª·´Ó¦Ç°ÉÕ±ÄÚÏ¡ÑÎËáºÍ̼ËáÄƵÄ×ÜÖÊÁ¿Îª60.0g, ´Ó·´Ó¦¿ªÊ¼ÖÁÒÔºóµÄ6·ÖÖÓÄÚ£¬Ã¿1·ÖÖÓ¶Á1´ÎÊý²¢¼Ç¼¡£½á¹ûÈçÏ£º
ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©±íÖÐÓÐÒ»¸ö²â¶¨½á¹ûÎó²î½Ï´ó£¬ÕâµãËùÔÚµÄʱ¼äÊǵÚ_______min£»
£¨2£©ÔÚ¸ø³öµÄ×ø±êÖ½ÉÏ£¬»³ö±íʾ·´Ó¦¹ý³ÌµÄÖÊÁ¿Óëʱ¼äµÄÇúÏßͼ£»
£¨3£©ÊÔ¼ÆËã50gÏ¡ÑÎËáÖÐHClµÄÖÊÁ¿·ÖÊý£¨Ð´³ö¼ÆËã¹ý³Ì£©¡£
ʱ¼ä/min | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
ÖÊÁ¿/g | 60.0 | 58.0 | 57.0 | 56.8 | 56.7 | 57.2 | 56.7 |
£¨1£©±íÖÐÓÐÒ»¸ö²â¶¨½á¹ûÎó²î½Ï´ó£¬ÕâµãËùÔÚµÄʱ¼äÊǵÚ_______min£»
£¨2£©ÔÚ¸ø³öµÄ×ø±êÖ½ÉÏ£¬»³ö±íʾ·´Ó¦¹ý³ÌµÄÖÊÁ¿Óëʱ¼äµÄÇúÏßͼ£»
£¨3£©ÊÔ¼ÆËã50gÏ¡ÑÎËáÖÐHClµÄÖÊÁ¿·ÖÊý£¨Ð´³ö¼ÆËã¹ý³Ì£©¡£
£¨1£©5£»£¨2£©¼ûͼ£»£¨3£©11%£¨»ò10.95%£©¡£
£º£¨1£©¹ýÁ¿Ì¼ËáÄÆÓëÏ¡ÑÎËᷴӦʱ£¬ÉÕ±ÄÚÎïÖʵÄ×ÜÖÊÁ¿Ó¦ÏÈÖð½¥¼õС£¬×îºó±£³Ö²»±ä£®ÓÉÓÚµÚ5·ÖÖÓʱÉÕ±ÄÚÎïÖÊ×ÜÖÊÁ¿Ôö´ó£¬ËµÃ÷²â¶¨½á¹ûÎó²î½Ï´ó£®
£¨2£©¼ûͼ
£»
£¨3£©ÉèÏ¡ÑÎËáÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýΪx£®
Na2CO3+2HCl=2NaCl+H2O+CO2¡ü
73 44
50g¡Áx 60.0g-56.7g
=
£¬x=10.95%
´ð£º£¨3£©Ï¡ÑÎËáÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýΪ10.95%£®
£¨2£©¼ûͼ
£»
£¨3£©ÉèÏ¡ÑÎËáÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýΪx£®
Na2CO3+2HCl=2NaCl+H2O+CO2¡ü
73 44
50g¡Áx 60.0g-56.7g
73 |
44 |
50g¡Áx |
60.0g-56.7g |
´ð£º£¨3£©Ï¡ÑÎËáÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýΪ10.95%£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿