ÌâÄ¿ÄÚÈÝ

¿ÎÍâ»î¶¯Ð¡×éµÄͬѧÔڲⶨÓÉNaClºÍNa2CO3ÐγɵĹÌÌå»ìºÏÎï×é³Éʱ£¬½øÐÐÁËÒÔÏÂʵÑ飺ȡ40 g¹ÌÌå»ìºÏÎïÅä³ÉÈÜÒº£¬Æ½¾ù·ÖΪËÄ·Ý£¬È»ºó·Ö±ð¼ÓÈëÒ»¶¨ÖÊÁ¿·ÖÊýµÄCaCl2ÈÜÒº£¬ÊµÑéÊý¾Ý¼ûÏÂ±í£º

ʵÑéÒ»

ʵÑé¶þ

ʵÑéÈý

ʵÑéËÄ

Ô­¹ÌÌå»ìºÏÎïÖÊÁ¿

£±£°g

£±£°g

£±£°g

£±£°g

¼ÓÈëCaCl2ÈÜÒºÖÊÁ¿

£±£°g

£²£°g

£³£°g

£´£°g

Éú³ÉµÄ³ÁµíµÄÖÊÁ¿

£²g

£í

£µg

£µg

Çë·ÖÎö±íÖÐÊý¾Ý»Ø´ð²¢¼ÆËã[£¨4£©ÒªÇóд¼ÆËã¹ý³Ì ]
£¨1£©Éú³ÉµÄ³ÁµíÊÇ£¨Ìîд»¯Ñ§Ê½£©        ¡£  £¨2£©10gÔ­¹ÌÌå»ìºÏÎïÅä³ÉµÄÈÜÒººÍ×ãÁ¿CaCl2ÈÜÒº·´Ó¦£¬×î¶àÉú³É³ÁµíÖÊÁ¿Îª        g¡£
£¨3£©£í=          g¡£
£¨4£©Ô­¹ÌÌå»ìºÏÎïÖÐNaClµÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿

(1)CaCO3    £¨1·Ö£©         (2)5  £¨1·Ö£©     (3) 4  £¨1·Ö£©
£¨4£©CaCl2  +  Na2CO3  =  CaCO3¡ý + 2NaCl
106      100
x        5g    ¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­ £¨1·Ö£©
¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­ £¨1·Ö£©
x = 5.3g       ¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­ £¨1·Ö£©
¹ÌÌå»ìºÏÎïÖÐNaClµÄÖÊÁ¿·ÖÊýÊÇ:¡Á 100%  = 47%
¡­¡­¡­¡­¡­¡­¡­ £¨2·Ö £¬ÁÐʽºÍ½á¹û¸÷1·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø