ÌâÄ¿ÄÚÈÝ
»¯Ñ§¾ÍÔÚÎÒÃÇÉí±ß£¬ÎÒÃǾ³£»áÓöµ½ÏÂÁÐÎÊÌ⣺
£¨1£©ÌúÐâµÄÖ÷Òª³É·ÖΪ Fe2O3£¬Çëд³öÓÃÏ¡ÑÎËá³ýÌúÐâµÄ»¯Ñ§·½³Ìʽ______£»
£¨2£©³¤ÆÚÊ¢·Å³ÎÇåʯ»ÒË®µÄÊÔ¼ÁÆ¿£¬ÆäÆ¿¿Ú¼°Æ¿±Ú³£ÓÐÒ»²ã°×É«¹ÌÌåÎïÖÊ£¬Çëд³öËüÐγɵÄÔÒò______£¨Óû¯Ñ§·½³Ìʽ±íʾ£©
£¨3£©Êг¡ÉÏʳÑÎµÄÆ·Öַḻ£¬ÓеâÑΡ¢Ð¿ÑΡ¢¸ÆÑΡ¢ÎøÑεȣ®ÕâЩʳÑÎÖк¬µÄµâ¡¢Ð¿¡¢¸Æ¡¢ÎøµÈÊÇÖ¸______£¨Ìî¡°Ô×Ó¡±¡°Àë×Ó¡±¡°ÔªËØ¡±»ò¡°µ¥ÖÊ¡±£©
£¨4£©Ä³Ð©Ê³Æ·°ü×°ÖÐÓÐһС´ü¸ÉÔï¼Á£¨³É·ÖΪÉúʯ»Ò£©£¬ËüÎüÊÕË®ÕôÆøµÄ»¯Ñ§·½³ÌʽΪ______£»Èô½«ÆäͶÈëË®Öв¢µÎ¼Ó×ÏɫʯÈïÊÔÒº£¬ÈÜÒº±ä______É«£®
£¨1£©ÌúÐâµÄÖ÷Òª³É·ÖΪ Fe2O3£¬Çëд³öÓÃÏ¡ÑÎËá³ýÌúÐâµÄ»¯Ñ§·½³Ìʽ______£»
£¨2£©³¤ÆÚÊ¢·Å³ÎÇåʯ»ÒË®µÄÊÔ¼ÁÆ¿£¬ÆäÆ¿¿Ú¼°Æ¿±Ú³£ÓÐÒ»²ã°×É«¹ÌÌåÎïÖÊ£¬Çëд³öËüÐγɵÄÔÒò______£¨Óû¯Ñ§·½³Ìʽ±íʾ£©
£¨3£©Êг¡ÉÏʳÑÎµÄÆ·Öַḻ£¬ÓеâÑΡ¢Ð¿ÑΡ¢¸ÆÑΡ¢ÎøÑεȣ®ÕâЩʳÑÎÖк¬µÄµâ¡¢Ð¿¡¢¸Æ¡¢ÎøµÈÊÇÖ¸______£¨Ìî¡°Ô×Ó¡±¡°Àë×Ó¡±¡°ÔªËØ¡±»ò¡°µ¥ÖÊ¡±£©
£¨4£©Ä³Ð©Ê³Æ·°ü×°ÖÐÓÐһС´ü¸ÉÔï¼Á£¨³É·ÖΪÉúʯ»Ò£©£¬ËüÎüÊÕË®ÕôÆøµÄ»¯Ñ§·½³ÌʽΪ______£»Èô½«ÆäͶÈëË®Öв¢µÎ¼Ó×ÏɫʯÈïÊÔÒº£¬ÈÜÒº±ä______É«£®
£¨1£©ÌúÐâµÄÖ÷Òª³É·ÖΪ Fe2O3£¬ÓëÑÎËá·´Ó¦Éú³ÉÂÈ»¯ÌúºÍË®£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇΪ£ºFe2O3+6HCl=2FeCl3+3H2O£®
£¨2£©Ê¯»ÒË®ÖеÄÈÜÖÊÊÇÇâÑõ»¯¸Æ£¬ÄÜÓë¿ÕÆøÖеĶþÑõ»¯Ì¼·´Ó¦Éú³É̼Ëá¸ÆºÍË®£»Ì¼Ëá¸ÆÊÇÒ»ÖÖ²»ÈÜÓÚË®µÄ°×É«ÎïÖÊ£¬¹ÊÆ¿¿Ú¼°Æ¿±Ú³£ÓÐÒ»²ã°×É«¹ÌÌåÎïÖÊ£»·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCO2+Ca£¨OH£©2¨TCaCO3¡ý+H2O£®
£¨3£©Ê³ÑÎÖеġ°µâ¡¢Ð¿¡¢¸Æ¡¢Îø¡±µÈ²»ÊÇÒÔµ¥ÖÊ¡¢·Ö×Ó¡¢Ô×Ó¡¢Àë×ÓµÈÐÎʽ´æÔÚ£¬ÕâÀïËùÖ¸µÄ¡°µâ¡¢Ð¿¡¢¸Æ¡¢Îø¡±ÊÇÇ¿µ÷´æÔÚµÄÔªËØ£¬Óë¾ßÌåÐÎ̬Î޹أ®
£¨4£©Éúʯ»ÒÓëË®·´Ó¦Éú³ÉÇâÑõ»¯¸Æ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaO+H2O=Ca£¨OH£©2£»Éú³ÉµÄÇâÑõ»¯¸ÆÏÔ¼îÐÔ£¬¹ÊÈô½«ÆäͶÈëË®Öв¢µÎ¼Ó×ÏɫʯÈïÊÔÒº£¬ÈÜÒº±äÀ¶É«£®
¹Ê´ð°¸Îª£º£¨1£©Fe2O3+6HCl=2FeCl3+3H2O£»£¨2£©Ca£¨OH£©2+CO2=CaCO3¡ý+H2O£»£¨3£©ÔªËØ£»£¨4£©CaO+H2O=Ca£¨OH£©2£»À¶£®
£¨2£©Ê¯»ÒË®ÖеÄÈÜÖÊÊÇÇâÑõ»¯¸Æ£¬ÄÜÓë¿ÕÆøÖеĶþÑõ»¯Ì¼·´Ó¦Éú³É̼Ëá¸ÆºÍË®£»Ì¼Ëá¸ÆÊÇÒ»ÖÖ²»ÈÜÓÚË®µÄ°×É«ÎïÖÊ£¬¹ÊÆ¿¿Ú¼°Æ¿±Ú³£ÓÐÒ»²ã°×É«¹ÌÌåÎïÖÊ£»·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCO2+Ca£¨OH£©2¨TCaCO3¡ý+H2O£®
£¨3£©Ê³ÑÎÖеġ°µâ¡¢Ð¿¡¢¸Æ¡¢Îø¡±µÈ²»ÊÇÒÔµ¥ÖÊ¡¢·Ö×Ó¡¢Ô×Ó¡¢Àë×ÓµÈÐÎʽ´æÔÚ£¬ÕâÀïËùÖ¸µÄ¡°µâ¡¢Ð¿¡¢¸Æ¡¢Îø¡±ÊÇÇ¿µ÷´æÔÚµÄÔªËØ£¬Óë¾ßÌåÐÎ̬Î޹أ®
£¨4£©Éúʯ»ÒÓëË®·´Ó¦Éú³ÉÇâÑõ»¯¸Æ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaO+H2O=Ca£¨OH£©2£»Éú³ÉµÄÇâÑõ»¯¸ÆÏÔ¼îÐÔ£¬¹ÊÈô½«ÆäͶÈëË®Öв¢µÎ¼Ó×ÏɫʯÈïÊÔÒº£¬ÈÜÒº±äÀ¶É«£®
¹Ê´ð°¸Îª£º£¨1£©Fe2O3+6HCl=2FeCl3+3H2O£»£¨2£©Ca£¨OH£©2+CO2=CaCO3¡ý+H2O£»£¨3£©ÔªËØ£»£¨4£©CaO+H2O=Ca£¨OH£©2£»À¶£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿