ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿»¯Ñ§ÓëÉú»î¡¢Éú²úϢϢÏà¹Ø£¬ÇëÔËÓû¯Ñ§ÖªÊ¶»Ø´ðÒÔÏÂÎÊÌâ¡£
£¨1£©ÊªÒ·þÔÚÑô¹âϱÈÔÚÒõÁ¹´¦¸ÉµÃ¿ì£¬ÕâÊÇÒòΪ_____¡£
£¨2£©³µÓÃÒÒ´¼ÆûÓÍÖУ¬ÒÒ´¼µÄ×÷ÓÃÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©_____¡£
£¨3£©ÃºÂ¯È¼ÉÕ¹ý³ÌÖз¢ÉúÎüÈÈ·´Ó¦µÄÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©_____¡£
£¨4£©ÊµÑéÊÒʯ»ÒË®µÄ±íÃæ³£ÓÐÒ»²ã°×Ĥ£¬ÔÒòÊÇ£¨»¯Ñ§·½³Ìʽ£©_____¡£
£¨5£©´ß»¯×ª»¯Æ÷¿ÉÓÐЧ½µµÍβÆøÖеÄCO¡¢NO¡¢NO2ºÍ̼Ç⻯ºÏÎïµÈÓк¦ÎïÖÊÏò´óÆøÖÐÅÅ·Å¡£´ß»¯×ª»¯Æ÷ÖÐͨ³£²ÉÓò¬µÈ¹óÖؽðÊô×÷´ß»¯¼Á¡£Çëд³öCOºÍNOÔÚ´ß»¯¼ÁµÄ×÷ÓÃÏ·¢Éú·´Ó¦Éú³ÉCO2ºÍN2µÄ»¯Ñ§·½³Ìʽ_____¡£
¡¾´ð°¸¡¿Î¶ÈÔ½¸ß£¬·Ö×ÓµÄÔ˶¯ËÙÂÊÔ½¿ì£¨»òζÈÔ½¸ß,Ë®·ÖÕô·¢Ô½¿ì£© C2H5OH+3O22CO2+3H2O C+CO22CO Ca£¨OH£©2+CO2=CaCO3¡ý+H2O 2CO+2NO£½2CO2+N2£¨Ð´´ß»¯¼ÁÒ²¸ø·Ö£©
¡¾½âÎö¡¿
£¨1£©ÊªÒ·þÔÚÑô¹âϱÈÔÚÒõÁ¹´¦¸ÉµÃ¿ì£¬ÊÇÒòΪ£ºÑô¹âÏÂζȸߣ¬Î¶ÈÉý¸ß£¬·Ö×ÓµÄÔ˶¯ËÙÂʼӿ죻
£¨2£©³µÓÃÒÒ´¼ÆûÓÍÖУ¬ÒÒ´¼È¼ÉÕÉú³É¶þÑõ»¯Ì¼ºÍË®£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºC2H5OH+3O22CO2+3H2O£»
£¨3£©ÃºÂ¯È¼ÉÕ¹ý³ÌÖз¢ÉúÎüÈÈ·´Ó¦µÄÊÇ̼ºÍ¶þÑõ»¯Ì¼ÔÚ¸ßÎÂÏ·´Ó¦Éú³ÉÒ»Ñõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºC+CO22CO£»
£¨4£©ÊµÑéÊÒʯ»ÒË®µÄ±íÃæ³£ÓÐÒ»²ã°×Ĥ£¬ÔÒòÊÇÇâÑõ»¯¸ÆÓë¶þÑõ»¯Ì¼·´Ó¦Éú³ÉÁË̼Ëá¸Æ£¬»¯Ñ§·½³Ìʽ±íʾΪ£ºCa£¨OH£©2+CO2¨TCaCO3¡ý+H2O£»
£¨5£©COºÍNOÔÚ´ß»¯¼ÁµÄ×÷ÓÃÏ·¢Éú·´Ó¦Éú³ÉCO2ºÍN2£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ£º2CO+2NO2CO2+N2¡£
¡¾ÌâÄ¿¡¿Îª²â¶¨»ìÓÐNa2CO3µÄʳÑδ¿¶È£¬×öÁË4´Î²â¶¨£¬Ã¿´Î¶¼È¡Ò»¶¨ÖÊÁ¿µÄÑùÆ·ºÍ200gÈÜÖÊÖÊÁ¿·ÖÊýΪ3.65%µÄÑÎËᣨÈÜÖÊΪHCl£©£¬½«ÑùÆ·ÅäÖƳÉÈÜÒººóÖðµÎµÎ¼Óµ½ËùÈ¡ÑÎËáÖз¢Éú·´Ó¦Na2CO3 +HCl¡úNaCl+H2O+CO2¡ü£¨Î´Åäƽ£©£¬²úÉúµÄÆøÌåÖÊÁ¿ÓëËùÓõÄÑùÆ·ÖÊÁ¿¹ØϵÈçϱíËùʾ£º
ʵÑé´ÎÊý | µÚ1´Î | µÚ2´Î | µÚ3´Î | µÚ4´Î |
ÑÎËáÖÊÁ¿£¨g£© | 200 | 200 | 200 | 200 |
ÑùÆ·ÖÊÁ¿£¨g£© | 10.6 | 53 | 265 | 300 |
ÆøÌåÖÊÁ¿£¨g£© | 0.44 | 2.2 | 4.4 | 4.4 |
ÇóÑùÆ·ÖÐNa2CO3µÄ´¿¶È£¨±£ÁôһλСÊý£¬Ð´³ö½âÌâ¹ý³Ì£©¡£__________
¡¾ÌâÄ¿¡¿Ì¼»¹ÔÑõ»¯ÍµÄʵÑéÈçͼËùʾ¡£Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ________________¡£
£¨Ìá³öÎÊÌ⣩̼ȼÉÕʱ¿ÉÄÜÉú³ÉCO2Ò²¿ÉÄÜÉú³ÉCO£¬ÄÇô̼ÓëÑõ»¯Í·´Ó¦Éú³ÉµÄÆøÌåÊÇ·ñÒ²ÓжàÖÖ¿ÉÄÜ?
£¨×÷³ö²ÂÏ룩²ÂÏë¢Ù¡ÃCO ²ÂÏë¢Ú¡ÃCO2 ²ÂÏë¢Û¡Ã________________¡£
£¨Éè¼Æ·½°¸£©ÊµÑé×°ÖÃÈçͼ£¨Å¨ÁòËá¾ßÓÐÎüË®×÷Óã©¡£´ò¿ªK£¬»º»ºÍ¨Èë¸ÉÔïµÄµªÆøÒ»¶Îʱ¼ä£¬¹Ø±ÕK£¬µãȼ¾Æ¾«ÅçµÆºÍ¾Æ¾«µÆ£¬³ä·Ö·´Ó¦ºó£¬Ï¨Ãð¾Æ¾«ÅçµÆºÍ¾Æ¾«µÆ£¬´ò¿ªK£¬ÔÙͨһ¶Îʱ¼äµªÆø¡Ã
£¨1£©ÊµÑéʱA´¦µÄÏÖÏóÊÇ___________________¡£
£¨2£©Èô²ÂÏë¢Ù³ÉÁ¢£¬B¡¢D´¦µÄÏÖÏóÊÇ________________£¨ÌîÐòºÅ£©¡£
aBÖбä»ë×Ç£¬D´¦Äܵãȼ bBÖбä»ë×Ç£¬D´¦²»Äܵãȼ
cBÖÐÎÞÃ÷ÏÔʵÑéÏÖÏó£¬D´¦Äܵãȼ dBÖÐÎÞÃ÷ÏÔʵÑéÏÖÏó£¬D´¦²»Äܵãȼ
·½°¸¶þ¡Ã´Ó¶¨Á¿¼ÆËã½Ç¶ÈÅжÏ
È¡Ò»¶¨Á¿Ì¿·ÛºÍ4gÑõ»¯ÍµÄ»ìºÏÎï½øÐÐʵÑ飬²¢²â¶¨±í¸ñÖеÄËĸöÊý¾Ý¡Ã
·´Ó¦Ç°µÄÖÊÁ¿ | ·´Ó¦ºóµÄÖÊÁ¿ | |
A£¨²£Á§¹Ü+¹ÌÌ壩 | m1 | m2 |
B+C£¨¹ã¿ÚÆ¿+»ìºÏÒº£© | m3 | m4 |
£¨3£©Èô²ÂÏë¢Ú³ÉÁ¢£¬ÔòÀíÂÛÉÏ£¨m4Ò»m3£©__________£¨m1£m2£©£¨Ñ¡Ìî¡°<¡±¡¢¡°>¡±»ò¡°=¡±£©¡£
£¨½»Á÷·´Ë¼£©ÊµÑ鿪ʼǰ»º»ºÍ¨È뵪ÆøµÄÄ¿µÄÊÇ_____________________¡£