ÌâÄ¿ÄÚÈÝ

¡°Î÷Æø¶«Ê䡱¹¤³ÌµÄ¿ª·¢ÓëÔËÐлº½âÁËÎÒ¹ú¶«²¿Ñغ£µØÇøµÄÄÜԴΣ»ú£¬±£»¤ÁËÎÒÃǵĻ·¾³£®
£¨1£©ÌìÈ»ÆøÔÚµÚÒ»´Îͨ¹ý¹ÜÊäË͵½Óû§Ê±£¬±ØÐëÏȽ«¹ÜµÀÄÚ×¢ÂúµªÆø£®ÎÒÖªµÀÌî³äµªÆøµÄÄ¿µÄÊÇ______£®
£¨2£©ÌìÈ»Æø±¾ÉíÊÇÒ»ÖÖÎÞÉ«ÎÞζµÄÆøÌ壬µ«ÔÚʹÓÃʱ³£ÔÚÌìÈ»ÆøÖмÓÈëÉÙÁ¿ÓÐÌØÊâÆøζµÄÒÒÁò´¼£®¼ÓÈëÒÒÁò´¼µÄ×÷ÓÃÊÇ______£®
£¨3£©Ò»µ©·¢ÏÖÓÐÌìÈ»Æøй©£¬ÎÒÓ¦¸Ã______¿ÉÈ·±£°²È«£®
¡¾´ð°¸¡¿·ÖÎö£º£¨1£©¼×ÍéÊÇ¿ÉȼÐÔÆøÌåÓë¿ÕÆø»ìºÏµãȼÒ×±¬Õ¨£®
£¨2£©ÌìÈ»Æø±¾ÉíÎÞζ£¬Ð¹Â¶²»Òײì¾õ£¬Ðè¼ÓÈëÓÐζµÄÎïÖÊÒÔ·Àй©£®
£¨3£©¸ù¾ÝÌìÈ»ÆøÓöÃ÷»ð¿ÉÄÜ·¢Éú±¬Õ¨½øÐнâ´ð£®
½â´ð£º½â£º£¨1£©ÈκοÉȼÐÔÆøÌåÓë¿ÕÆø»ìºÏµãȼʱ¶¼ÓпÉÄÜ·¢Éú±¬Õ¨£¬µªÆøµÄ»¯Ñ§ÐÔÖʲ»»îÆã¬Æðµ½Åž¡¹ÜµÀÄڵĿÕÆø£¬ÓÃ×÷±£»¤ÆøµÄ×÷Óã®
¹Ê´ð°¸Îª£ºÅž¡¹ÜµÀÄڵĿÕÆø£¬·ÀÖ¹¼×ÍéÓë¿ÕÆø»ìºÏµã»ðʱ·¢Éú±¬Õ¨£®
£¨2£©ÌìÈ»Æø±¾ÉíÊÇÒ»ÖÖÎÞÉ«¡¢ÎÞζµÄÆøÌ壬й©ʱÄÑÓÚ²ì¾õ£®
¹Ê´ð°¸Îª£ºÌáÐÑÈËÃǼ°Ôç·¢ÏÖÌìÈ»Æøй©£¬·ÀÖ¹±¬Õ¨Ê¹ʵķ¢Éú£®
£¨3£©Ò»µ©·¢ÏÖÓÐÌìÈ»Æøй©£¬ÎÒÓ¦¸Ã¹Ø±Õ·§ÃÅ£¬¿ª´°Í¨·ç£¬¿ÉÈ·±£°²È«£®¹Ê´ð°¸Îª£º¹Ø±Õ·§ÃÅ£¬¿ª´°Í¨·ç£®
µãÆÀ£º±¾ÌâÖ÷Òª¿¼²éÁËÌìÈ»ÆøµÄÐÔÖʺÍÓÃ;µÈ·½ÃæµÄ֪ʶ£¬ÊôÓÚÉú»îʵ¼ÊµÄ¿¼²éÌ⣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÈËÃÇÒ»¿ÌÒ²Àë²»¿ª¿ÕÆø£¬´óÆøÎÛȾӰÏì×ÅÈËÃǵÄÕý³£Éú»î£®¸ÄÉÆ¿ÕÆøÖÊÁ¿£¬±£³Ö¿ÕÆøÇåУ¬ÓªÔ콡¿µÊæÊʵÄÉú´æ»·¾³£¬ÒѳÉΪȫÈËÀàµÄ¹²Ê¶£®
£¨1£©ÏÂÃæÊÇÎÒ¹úijµØÇøµÄÒ»·Ý¿ÕÆøÖÊÁ¿Ô¤±¨±í£®
Ö¸  ±ê ×òÈÕʵ¿ö ½ñÈÕÔ¤²â
API ¿ÕÆøÖÊÁ¿µÈ¼¶ API ¿ÕÆøÖÊÁ¿µÈ¼¶
×ÜÐü¸¡¿ÅÁ£Îï 26 ¢ñ 20-35 ¢ñ
¶þÑõ»¯Áò 38 ¢ñ 30-45 ¢ñ
µªÑõ»¯Îï 59 ¢ò 55-75 ¢ò
˵  Ã÷ Ô¤¼Æ½ñÈÕ¿ÕÆøÖÊÁ¿½ÏºÃ£¬¶ÔÈËÌåÎÞ²»ÀûÓ°Ï죬ÊÐÃñ¿ÉÕý³£»î¶¯£®
¢Ù´Ó±í¸ñ¿ÉÒÔÅжϣ¬¸ÃµØÇøµÄ×îÖ÷Òª¿ÕÆøÎÛȾÎïÊÇ
 
£»
¢Ú¶þÑõ»¯ÁòÊÇÎÛȾ´óÆøµÄÖ÷ÒªÓк¦ÎïÖÊÖ®Ò»£®³ýÈ¥¶þÑõ»¯ÁòµÄ·½·¨ÓжàÖÖ£¬ÆäÖÐÓÐÒ»ÖÖ·½·¨½Ð¡°Ê¯»ÒʯÍÑÁò¡±·¨£¬Ô­ÁÏΪʯ»Òʯ£¬²úƷΪʯ¸à£¨CaSO4£©£®Çëд³öÏà¹ØµÄ»¯Ñ§·½³Ìʽ£º
µÚÒ»²½£º·Ö½âʯ»Òʯ
 
£»
µÚ¶þ²½£ºÉúʯ»ÒÓë¶þÑõ»¯ÁòµÄ»¯ºÏ
 
£»
µÚÈý²½£ºÉÏÊö²úÎïÓëÑõÆø·´Ó¦Éú³Éʯ¸à
 
£®
£¨2£©Ò»Ñõ»¯Ì¼Ò²Êdz£¼ûµÄ´óÆøÎÛȾÎÆûÓÍÔÚÆû³µ·¢¶¯»úÖеIJ»ÍêȫȼÉտɱíʾΪ
2C8H18+23O2¡ú12CO2+4CO+18H2O
¢Ùij»·¾³¼à²âÐËȤС×éµÄͬѧÃè»æµÄÑïÖÝÊÐÎIJý¸ó¸½½ü¿ÕÆøÖÐCOº¬Á¿±ä»¯ÇúÏߣ¨ºá×ø±ê±íʾ±±¾©Ê±¼ä0µ½24Сʱ£¬×Ý×ø±ê±íʾCOº¬Á¿£©£¬ÄãÈÏΪ±È½Ï·ûºÏʵ¼ÊµÄÊÇÄÄÒ»·ùͼ
 

A¡¢¾«Ó¢¼Ò½ÌÍøB¡¢¾«Ó¢¼Ò½ÌÍø
C¡¢¾«Ó¢¼Ò½ÌÍø D¡¢¾«Ó¢¼Ò½ÌÍø                      

¢ÚÄ¿Ç°ÑïÖÝÊÐÇøÒÑÈ«ÃæʹÓá°Î÷Æø¶«Ê䡱¹¤³ÌÊäË͵ÄÌìÈ»Æø£¬ÔÚÖû»È˹¤ÃºÆøºÍÌìÈ»ÆøµÄ¹ý³ÌÖÐÒ»¶¨Òª¶ÔÔ­ÓеÄÔî¾ß½øÐиÄÔì»ò¸ü»»£¬·ñÔòÒ²»á²úÉú²»ÍêȫȼÉÕ£®ÍõÀÏʦ²É¼¯ÁË20.8gÌìÈ»ÆøȼÉյIJúÎͨ¹ýÎÞË®ÂÈ»¯¸Æ¹ÌÌ壨¸ÉÔï¼Á£©ºó£¬ÆøÌå¼õÉÙÁË10.8g£¬ÔòÔ­ÆøÌåÖÐÒ»Ñõ»¯Ì¼ºÍ¶þÑõ»¯Ì¼µÄÖÊÁ¿±ÈÊÇ
 
£®£¨¼ÙÉè²»°üº¬ÆäËüÆøÌ壩
£¨3£©¾ÝýÌ屨µÀ£¬Ä¿Ç°¼Ò¾Ó»·¾³µÄ¿ÕÆøÎÛȾÖ÷ÒªÊÇ×°ÐÞʱËùÓÃÓÍÆáÖк¬³¬Á¿µÄ¼×È©£¨CH2O£©ËùÖ£¬³¤ÆÚ½Ó´¥¼×È©µÄÈËȺ£¬¿Ú¡¢±Ç¡¢ºí²¿¼°·Î²¿Ö×ÁöµÄ·¢²¡ÂÊ»áÏÔÖøÔö¼Ó£®ÊÐÃæÉϳöÊÛµÄÒ»ÖÖ¡°¼×È©²¶×½¼Á¡±ÆäÖк¬ÓеĹýÑõ»¯Ç⣨H2O2£©¿ÉÒÔÓÐЧµØ½«¼×È©Ñõ»¯ÎªÎÞ¶¾ÆøÌ壬ͬʱÉú³ÉË®£®ÊÔд³ö¸Ã¹ý³ÌµÄ»¯Ñ§·½³Ìʽ£º
 
£®
ÈËÃǵÄÉú»îÉú²úÀë²»¿ªÈ¼ÁÏ£¬¸ù¾ÝËùѧ֪ʶ£¬»Ø´ðÒÔÏÂÎÊÌ⣺
ͼ1ÊÇ2008Äê±±¾©°ÂÔË»áµÄ»ð¾æͼƬ£®Ëü½«ÓÚ½ñÄêÎåÔÂÏÂÑ®½øÈëÎÒÊ¡ºÏ·Ê¡¢»´ÄÏ¡¢Îß
ºþ¡¢¼¨Ïª¡¢»ÆɽÎå¸ö³ÇÊУ®°ÂÔË»ð¾æËùÓÃȼÁϳÆΪ±ûÍ飨»¯Ñ§Ê½ÎªC3H8£©£¬±ûÍéÊôÓÚ
ÓлúÎï
ÓлúÎï
£¨Ìî¡°ÓлúÎ»ò¡°ÎÞ»úÎ£©£®ÆäȼÉÕ²úÎïÖÐ
¶þÑõ»¯Ì¼
¶þÑõ»¯Ì¼
ÊôÓÚ¡¶¾©¶¼Ò鶨Êé¡·ÖÐÏÞÅÅÎïÖÊ£®
£¨2£©Í¼2ÊÇ¡°Î÷Æø¶«Êä¡°-V³ÌµÄͼƬ£®¡°Î÷Æø¶«Ê䡱¹¤³ÌʹÎÒÊ¡²¿·Ö³ÇÊÐÓÃÉÏÁË
ÌìÈ»Æø
ÌìÈ»Æø
£¨ÌîȼÁÏÃû³Æ£©£¬ÆäÖ÷Òª³É·ÖÔÚ¿ÕÆøÖÐÍêȫȼÉյĻ¯Ñ§·½³ÌʽΪ
CH4+2O2
 µãȼ 
.
 
CO2+2H2O
CH4+2O2
 µãȼ 
.
 
CO2+2H2O
£®
£¨3£©ÓÉ̼ÇâÔªËØ×é³ÉµÄ»¯ºÏÎïÖУ¬ÓÐÒ»ÀàÎïÖʽÐ×öÍéÌþ£®ÆäÖÐCH4Ϊ¼×Í飬C2H6ΪÒÒÍ飬
C3H8Ϊ±ûÍ飬C4H10Ϊ¶¡Íé¡­£®Ôò·Ö×ÓÖк¬ÓÐ8¸ö̼ԭ×ÓµÄÍéÌþµÄ»¯Ñ§Ê½Îª
C8H18
C8H18
£®ÕâÀàÎïÖÊËæÇâÔ­×ÓÊýÔö¶à£¬ÆäÖк¬Ì¼ÔªËصÄÖÊÁ¿·ÖÊýÖð½¥
Ôö´ó
Ôö´ó
£¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±£©£®C3H8ºÍCH4·Ö±ðÍêȫȼÉÕ£¬Éú³ÉµÄC02ºÍH20µÄ·Ö×ÓÊýÖ®±È£¬Ç°Õß
СÓÚ
СÓÚ
ºóÕߣ¨Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø