ÌâÄ¿ÄÚÈÝ
ÈËÌåÖеĸÆÔªËØÖ÷Òª´æÔÚÓÚ¹Ç÷ÀºÍÑÀ³ÝÖУ¬ÒÔôÇ»ùÁ×Ëá¸Æ¾§Ìå
[Ca10(PO4)6(OH)2]µÄÐÎʽ´æÔÚ£¬ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª1004£®Å£Ä̺¬¸Æ·á¸»ÓÖÒ×ÎüÊÕ£¬ÇÒÅ£ÄÌÖиƺÍÁ×±ÈÀýºÏÊÊ£¬Êǽ¡¹ÇµÄÀíÏëʳƷ£®ÏÂͼÊÇijÈéÒµ¹«Ë¾´¿Å£ÄÌ°ü×°±êÇ©µÄ²¿·ÖÎÄ×Ö£®Çë×ÐϸÔĶÁºó»Ø´ðÏÂÁÐÎÊÌ⣺(1)°ü×°±êÇ©ÉÏÖ¬·¾¡Ý3.3g£¬ÊÇÖ¸100mLÅ£ÄÌÖк¬Ö¬·¾µÄÖÊÁ¿ÖÁÉÙΪ3.3g£®ÄÇôһºÐÅ£Ä̺¬¸ÆÖÁÉÙΪ¶àÉÙ¿Ë(±£Áôµ½0.01g)£¿
(2)ÇóôÇ»ùÁ×Ëá¸ÆÖиÆÔªËصÄÖÊÁ¿·ÖÊý(±£Áôµ½0.1£¥)£®
(3)ÈôÈËÌåÿÌìÖÁÉÙÐèÒª0.6g¸Æ£¬ÇÒÕâЩ¸ÆÓÐ90£¥À´×ÔÅ£ÄÌ£¬ÔòÒ»¸öÈËÿÌìÖÁÉÙÒªºÈ¶àÉÙºÐÅ£ÄÌ£¿
´ð°¸£º
½âÎö£º
½âÎö£º
(1)0.28;(2)39.8£¥;(3)2ºÐ |
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÈËÌåÖеĸÆÔªËØÖ÷Òª´æÔÚÓÚ¹Ç÷ÀºÍÑÀ³ÝÖУ¬ÒÔôÇ»ùÁ×Ëá¸Æ¾§Ìå[Ca10£¨PO4£©6£¨OH£©2]ÐÎʽ´æÔÚ£¬ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª1004£®Å£Ä̺¬¸Æ·á¸»ÓÖÒ×ÎüÊÕ£¬ÇÒÅ£Ä̵ĸƺÍÁ×±ÈÀýºÏÊÊ£¬Êǽ¡¹ÇµÄÀíÏëʳƷ£®ÈçͼÊÇijÈéÒµ¹«Ë¾´¿Å£ÄÌ°ü×°±êÇ©µÄ²¿·ÖÎÄ×Ö£®Çë×ÐϸÔĶÁºó»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©°ü×°±êÇ©ÉÏÖ¬·¾¡Ý3.3g£¬ÊÇÖ¸100mLÅ£ÄÌÖУ¬º¬Ö¬·¾µÄÖÊÁ¿ÖÁÉÙΪ3.3g£®ÄÇôһºÐÅ£Ä̺¬¸ÆÖÁÉÙ g£¨±£Áôµ½0.01g£©£®
£¨1£©°ü×°±êÇ©ÉÏÖ¬·¾¡Ý3.3g£¬ÊÇÖ¸100mLÅ£ÄÌÖУ¬º¬Ö¬·¾µÄÖÊÁ¿ÖÁÉÙΪ3.3g£®ÄÇôһºÐÅ£Ä̺¬¸ÆÖÁÉÙ
´¿Å£ÄÌ ÅäÁÏ£ºÏÊÅ£ÄÌ ±£ÖÊÀÊ£º8¸öÔ ¾»º¬Á¿£º250mL/ºÐ ÓªÑø³É·Ö£º£¨Ã¿100mL£© ¸Æ¡Ý0.11g Ö¬·¾¡Ý3.3g µ°°×ÖÊ¡Ý2.9g£¨2£©ÇóôÇ»ùÁ×Ëá¸ÆÖиÆÔªËصÄÖÊÁ¿·ÖÊý£¨±£ÁôΪ0.1%£©£® £¨3£©ÈôÈËÌåÿÌìÖÁÉÙÐèÒª0.6g¸Æ£¬ÇÒÕâЩÓÐ90%À´×ÔÅ£ÄÌ£¬ÔòÒ»¸öÈËÿÌìÖÁÉÙÒªºÈ¶àÉÙºÐÅ£ÄÌ£¿ |