ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ì¼Óë̼µÄ»¯ºÏÎïÔÚ¹¤Å©ÒµÉú²ú¼°ÈÕ³£Éú»îÖÐÓй㷺µÄÓÃ;¡£
£¨1£©¹Å´úÊ黼ÒÓÃÄ«»æÖƵÄ×Ö»ËäÄê¾ÃÈÔ²»±äÉ«£¬ËµÃ÷³£ÎÂÏÂ̼µÄ»¯Ñ§ÐÔÖÊ___________¡£
£¨2£©CO2ÄܲÎÓë¹âºÏ×÷ÓÃÍê³É´óÆøÖеġ°Ì¼Ñ»·¡±£¬µ«ÊÇ´óÆøÖÐCO2µÄº¬Á¿²»¶ÏÉÏÉý£¬»áʹȫÇòÆøºò±äů£¬´Ó¶ø¼Ó¾ç¡°______________¡±¡£µ¼Ö´óÆøÖжþÑõ»¯Ì¼º¬Á¿²»¶ÏÉÏÉýµÄÖ÷ÒªÒòËØÊÇ(ÌîÐòºÅ) ¡£
¢ÙÈ˺Ͷ¯ÎïµÄºôÎü ¢ÚÖ²ÎïµÄ¹âºÏ×÷Óà ¢Û»¯Ê¯È¼ÁϵĴóÁ¿Ê¹ÓúÍÉÁÖÔâµ½ÆÆ»µ
£¨3£©Ê߲˴óÅïÓÃ×÷Æø·ÊµÄCO2£¬¿ÉÒÔÓÃÏ¡ÁòËᣨH2SO4£© Óë̼ËáÇâï§(NH4HCO3)·´Ó¦ÖƵ㬷´Ó¦ºóÉú³ÉÁòËá李¢Ë®ºÍCO2£¬ÕâÒ»·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ______________
¡¾´ð°¸¡¿£¨1£©²»»îÆà £¨2£©ÎÂÊÒЧӦ ¢Û £¨3£©2NH4HCO3+H2SO4=(NH4)2SO4+H2O+CO2¡ü
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©¹Å´úÊ黼ÒÓÃÄ«»æÖƵÄ×Ö»ËäÄê¾ÃÈÔ²»±äÉ«£¬ËµÃ÷³£ÎÂÏÂ̼µÄ»¯Ñ§ÐÔÖʲ»»îÆÃ
£¨2£©¶þÑõ»¯Ì¼Êǵ¼ÖÂÎÂÊÒЧӦµÄÖ÷ÒªÆøÌ壬¹Ê´óÆøÖÐCO2µÄº¬Á¿²»¶ÏÉÏÉý£¬»áʹȫÇòÆøºò±äů£¬´Ó¶ø¼Ó¾çÎÂÊÒЧӦ£»µ¼Ö´óÆøÖжþÑõ»¯Ì¼º¬Á¿²»¶ÏÉÏÉýµÄÖ÷ÒªÒòËØÊÇ£º»¯Ê¯È¼ÁϵĴóÁ¿Ê¹ÓúÍÉÁÖÔâµ½ÆÆ»µ£¬¹ÊÑ¡¢Û
£¨3£©Ï¡ÁòËᣨH2SO4£©Óë̼ËáÇâï§(NH4HCO3)·´Ó¦Éú³ÉÁòËá李¢Ë®ºÍCO2£¬ÕâÒ»·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ£º2NH4HCO3+H2SO4=(NH4)2SO4+H2O+CO2¡ü