ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿»·¾³ÓëÄÜÔ´ÎÊÌâÊǵ±½ñÉç»á±¸ÊܹØ×¢µÄÈȵ㡣

£¨1£©Ä¿Ç°ÈËÀàÒÔ»¯Ê¯È¼ÁÏΪÖ÷ÒªÄÜÔ´,³£¼ûµÄ»¯Ê¯È¼ÁÏ°üÀ¨Ãº¡¢______ºÍÌìÈ»Æø£»

£¨2£©ÏÖÔÚÌᳫ¡°µÍ̼Éú»î¡±£¬Ö÷ÒªÊÇΪÁ˼õÉÙº¬Ì¼ÄÜÔ´ÏûºÄ£¬´Ó¶ø¼õÉÙ̼Ñõ»¯ÎïµÄÅÅ·Å¡£Òò´ËÎÒÃÇҪעÖØ¿ª·¢ºÍʹÓÃÐÂÄÜÔ´£¬Óдý¿ª·¢µÄÐÂÄÜÔ´ÓÐ_____£¨Ð´Ò»ÖÖ¼´¿É£©£»

£¨3£©»¯Ê¯È¼ÁÏȼÉÕ²úÉú´óÁ¿CO2¡£È¥ÄêÎÒ¹ú´ó·¶Î§ÄÚ³öÏÖÁËÎíö²ÌìÆø£¬PM2.5ÊÇÔì³ÉÕâÖÖÌìÆøµÄ¡°ÔªÐס±Ö®Ò»¡£PM 2.5ÊÇÖ¸´óÆøÖÐÖ±¾¶Ð¡ÓÚ»òµÈÓÚ2.5΢Ã׵ĿÅÁ£ÎҲ³Æ¿ÉÈë·Î¿ÅÁ£Îï¡£ÏÂÁÐÐÐΪÄܲúÉúPM2.5µÄÊÇ________ £»

A½¨Öþ¹¤µØ¶¨Ê±È÷Ë®³ý³¾ B½ÚÈÕÀïȼ·Å±ÞÅÚ

C½«Ð£Ô°µÄÀ¬»ø¶Ñ»ýÆðÀ´£¬¾ÍµØ·ÙÉÕ DΪ·½±ã³öÐУ¬Ìᳫ´óÁ¿¹ºÂòºÍʹÓÃ˽¼Ò³µ

£¨4£©´óÆøÖÐCO2º¬Á¿¹ý¸ßÊǵ¼ÖÂÎÂÊÒЧӦµÄ×îÖ÷ÒªÔ­Òò£¬×ÔÈ»½çÖÐÏûºÄCO2µÄÖ÷Ҫ;¾¶ÊÇ____________________£»

£¨5£©¼ÆËã1 g CH4ÍêȫȼÉÕ²úÉúCO2µÄÖÊÁ¿m = ___________ g£¨½á¹û¾«È·µ½0.01 g£©£»

£¨6£©´ÓϱíÊý¾Ý·ÖÎö£¬ÓëúÏà±È£¬ÓÃÌìÈ»Æø×÷ȼÁϵÄÓŵãÊÇ_____________£¨Ð´Ò»µã¼´¿É£©

1gÎïÖÊÍêȫȼÉÕ²úÉúCO2µÄÖÊÁ¿

1gÎïÖÊÍêȫȼÉշųöµÄÈÈÁ¿

CH4

m

56 kJ

C

3.67 g

32 kJ

¡¾´ð°¸¡¿Ê¯ÓÍ ÇâÄÜ £¨·çÄÜ¡¢Ì«ÑôÄÜ¡¢µØÈÈÄÜ¡¢³±Ï«ÄܵȺÏÀí¼´¿É£© B C D Ö²ÎïµÄ¹âºÏ×÷Óà 2.75 ÏàͬÖÊÁ¿£¬CH4ÍêȫȼÉÕ²úÉúµÄCO2±ÈúµÄÉÙ£¨»òÏàͬÖÊÁ¿£¬CH4ÍêȫȼÉÕ³öµÄÈÈÁ¿±ÈúµÄ¶à£©

¡¾½âÎö¡¿

£¨1£©Èý´ó»¯Ê¯È¼ÁÏ£ºÃº¡¢Ê¯ÓÍ¡¢ÌìÈ»Æø£»

£¨2£©Óдý¿ª·¢µÄÐÂÄÜÔ´ÓУºÇâÄÜ¡¢·çÄÜ¡¢Ì«ÑôÄÜ¡¢µØÈÈÄÜ¡¢³±Ï«ÄܵÈ

£¨3£©A ½¨Öþ¹¤µØ¶¨Ê±È÷Ë®³ý³¾¿ÉÒÔ¼õС²úÉúPM2.5

B ½ÚÈÕÀïȼ·Å±ÞÅÚ²úÉú´óÁ¿µÄÑÌÎí£¬Ôö¼ÓPM2.5Ũ¶È£»

C ½«Ð£Ô°µÄÀ¬»ø¶Ñ»ýÆðÀ´£¬¾ÍµØ·ÙÉÕ£¬²úÉú´óÁ¿ÑÌÎí£¬Ôö¼ÓPM2.5Ũ¶È£»

D Ϊ·½±ã³öÐУ¬Ìᳫ´óÁ¿¹ºÂòºÍʹÓÃ˽¼Ò³µ£¬²úÉú´óÁ¿µÄβÆøÅÅ·Å£¬Ôö¼ÓPM2.5Ũ¶È£»

£¨4£©Ö²ÎïµÄ¹âºÏ×÷ÓÿÉÒÔÎüÊÕ¶þÑõ»¯Ì¼²úÉúÑõÆø£»

£¨5£©½â£ºÉè²úÉú¶þÑõ»¯Ì¼µÄÖÊÁ¿Îªx¡£

= ½âÖ®µÃ£ºx=2.75g

£¨6£©ÏàͬÖÊÁ¿£¬CH4ÍêȫȼÉÕ²úÉúµÄCO2±ÈúµÄÉÙ£»ÏàͬÖÊÁ¿£¬CH4ÍêȫȼÉÕ³öµÄÈÈÁ¿±ÈúµÄ¶à

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø