ÌâÄ¿ÄÚÈÝ
¿ÕÆøÖÐÑõÆøº¬Á¿µÄʵÑé̽¾¿£¬ÊÇÀûÓÿÉȼÎïȼÉÕÏûºÄÑõÆøÀ´´ÖÂԲⶨÆäÌå»ý·ÖÊýµÄ£®¿Î±¾ÖÐÊÇÓÃȼÉÕºìÁ׵ķ½·¨À´½øÐеÄʵÑé̽¾¿£¨Èçͼ1£©£®Ìá³öÎÊÌ⣺ÄÜÓÃȼÉÕÁò»Ç£¨µ¥ÖÊÁò£©À´²â¶¨¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊýÂð£¿
²ÂÏëÓë¼ÙÉè1£º¼×ͬѧÈÏΪ²»ÄÜ£®¼ÙÉèÓÃÁòȼÉÕ£¬È¼ÉÕºóµÄ²úÎïΪ______£¬ÊÇÆø̬ÎïÖÊ£¬²»ÊÊÒËÓøÃʵÑé·½·¨²â¶¨£®
²ÂÏëÓë¼ÙÉè2£ºÒÒͬѧÈÏΪÄÜ£®¼ÙÉèÓÃÁòȼÉÕ£¬¸ù¾ÝÏÖÓл¯Ñ§ÖªÊ¶£¬Ö»ÒªÏûºÄÁòȼÉÕºóµÄ²úÎï¾ÍͬÑùÄÜ´ÖÂԲⶨ¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý£®
Éè¼ÆÓëʵÑ飺½«Ô×°ÖøÄΪÈçͼ2µÄʵÑé×°Öã¬ÉÕ±ºÍµÎ¹ÜÖеÄÒºÌåΪ______£®µ±Áò»ÇȼÉÕÖÁ»ðÑæϨÃð²¢ÀäÈ´ºó£¬´ò¿ªÖ¹Ë®¼Ð£¬¼·Ñ¹µÎ¹Ü£¬µÎÈ뼸µÎÒºÌ壬´Ëʱ¿É¹Û²ìµ½ÉÕ±ÖеÄÒºÌåÎüÈ뼯ÆøÆ¿ÖУ¬Á÷ÈëÒºÌåµÄÌå»ý´óÔ¼ÔÚ¼¯ÆøÆ¿µÄÏðƤ½î´¦£®ÒºÌåÁ÷È뼯ÆøÆ¿Öкó·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º______£®
½áÂÛ£º______£®
ÆÀ¼ÛÓ뷴˼£º¢ÙȼÉÕºìÁ×Óë¢ÚȼÉÕÁò»ÇÁ½Öֲⶨ¿ÕÆøÖÐÑõÆøº¬Á¿µÄ·½·¨£¬×îºÃÑ¡Óã¨Ñ¡Ìî·½·¨´úºÅ£©______µÄ·½·¨£»ÔÒòÊÇ______£®![¾«Ó¢¼Ò½ÌÍø](http://thumb.1010pic.com/pic2/upload/papers/20130925/2013092521035332610184.png)
²ÂÏëÓë¼ÙÉè1£º¼×ͬѧÈÏΪ²»ÄÜ£®¼ÙÉèÓÃÁòȼÉÕ£¬È¼ÉÕºóµÄ²úÎïΪ______£¬ÊÇÆø̬ÎïÖÊ£¬²»ÊÊÒËÓøÃʵÑé·½·¨²â¶¨£®
²ÂÏëÓë¼ÙÉè2£ºÒÒͬѧÈÏΪÄÜ£®¼ÙÉèÓÃÁòȼÉÕ£¬¸ù¾ÝÏÖÓл¯Ñ§ÖªÊ¶£¬Ö»ÒªÏûºÄÁòȼÉÕºóµÄ²úÎï¾ÍͬÑùÄÜ´ÖÂԲⶨ¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý£®
Éè¼ÆÓëʵÑ飺½«Ô×°ÖøÄΪÈçͼ2µÄʵÑé×°Öã¬ÉÕ±ºÍµÎ¹ÜÖеÄÒºÌåΪ______£®µ±Áò»ÇȼÉÕÖÁ»ðÑæϨÃð²¢ÀäÈ´ºó£¬´ò¿ªÖ¹Ë®¼Ð£¬¼·Ñ¹µÎ¹Ü£¬µÎÈ뼸µÎÒºÌ壬´Ëʱ¿É¹Û²ìµ½ÉÕ±ÖеÄÒºÌåÎüÈ뼯ÆøÆ¿ÖУ¬Á÷ÈëÒºÌåµÄÌå»ý´óÔ¼ÔÚ¼¯ÆøÆ¿µÄÏðƤ½î´¦£®ÒºÌåÁ÷È뼯ÆøÆ¿Öкó·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º______£®
½áÂÛ£º______£®
ÆÀ¼ÛÓ뷴˼£º¢ÙȼÉÕºìÁ×Óë¢ÚȼÉÕÁò»ÇÁ½Öֲⶨ¿ÕÆøÖÐÑõÆøº¬Á¿µÄ·½·¨£¬×îºÃÑ¡Óã¨Ñ¡Ìî·½·¨´úºÅ£©______µÄ·½·¨£»ÔÒòÊÇ______£®
![¾«Ó¢¼Ò½ÌÍø](http://thumb.1010pic.com/pic2/upload/papers/20130925/2013092521035332610184.png)
²ÂÏëÓë¼ÙÉè1£ºÁòÔÚ¿ÕÆøÖÐȼÉÕÉú³É¶þÑõ»¯ÁòÆøÌ壻
Éè¼ÆÓëʵÑ飺ÇâÑõ»¯ÄÆÈÜÒº¿ÉÒÔÎüÊÕ¶þÑõ»¯Áò£¬ÕâÑùÒºÌå¾ÍÄܹ»¸üѸËÙ½øÈë×°ÖÃÄÚÈ¥ÎüÊÕ¶þÑõ»¯Áò£¬¶þÑõ»¯ÁòÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºSO2+2NaOH=Na2SO3+H2O£»
½áÂÛ£ºÄÜÓÃȼÉÕÁò»Ç£¨µ¥ÖÊÁò£©À´²â¶¨¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý£»
ÆÀ¼ÛÓ뷴˼£º×îºÃÑ¡Ôñ¢ÙÀ´²â¶¨¿ÕÆøÖÐÑõÆøµÄº¬Á¿£¬ÒòΪʹÓÃÁòµÄ²â¶¨×°Öýϸ´ÔÓÇÒʹÓõÄÇâÑõ»¯ÄÆÈÜÒºÓи¯Ê´ÐԵȣ®
¹Ê´ð°¸Îª£º¶þÑõ»¯Áò£»ÇâÑõ»¯ÄÆÈÜÒº£»SO2+2NaOH=Na2SO3+H2O£»ÄÜÓÃȼÉÕÁò»Ç£¨µ¥ÖÊÁò£©À´²â¶¨¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý£»¢Ù£»Ê¹ÓÃÁòµÄ²â¶¨×°Öýϸ´ÔÓÇÒʹÓõÄÇâÑõ»¯ÄÆÈÜÒºÓи¯Ê´ÐԵȣ®
Éè¼ÆÓëʵÑ飺ÇâÑõ»¯ÄÆÈÜÒº¿ÉÒÔÎüÊÕ¶þÑõ»¯Áò£¬ÕâÑùÒºÌå¾ÍÄܹ»¸üѸËÙ½øÈë×°ÖÃÄÚÈ¥ÎüÊÕ¶þÑõ»¯Áò£¬¶þÑõ»¯ÁòÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºSO2+2NaOH=Na2SO3+H2O£»
½áÂÛ£ºÄÜÓÃȼÉÕÁò»Ç£¨µ¥ÖÊÁò£©À´²â¶¨¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý£»
ÆÀ¼ÛÓ뷴˼£º×îºÃÑ¡Ôñ¢ÙÀ´²â¶¨¿ÕÆøÖÐÑõÆøµÄº¬Á¿£¬ÒòΪʹÓÃÁòµÄ²â¶¨×°Öýϸ´ÔÓÇÒʹÓõÄÇâÑõ»¯ÄÆÈÜÒºÓи¯Ê´ÐԵȣ®
¹Ê´ð°¸Îª£º¶þÑõ»¯Áò£»ÇâÑõ»¯ÄÆÈÜÒº£»SO2+2NaOH=Na2SO3+H2O£»ÄÜÓÃȼÉÕÁò»Ç£¨µ¥ÖÊÁò£©À´²â¶¨¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý£»¢Ù£»Ê¹ÓÃÁòµÄ²â¶¨×°Öýϸ´ÔÓÇÒʹÓõÄÇâÑõ»¯ÄÆÈÜÒºÓи¯Ê´ÐԵȣ®
![](http://thumb2018.1010pic.com/images/loading.gif)
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿