ÌâÄ¿ÄÚÈÝ

£¨5·Ö£©Çë¹Û²ìÏÂÁÐ×°Öò¢»Ø´ðÏà¹ØÎÊÌ⣮

£¨1£©ÆäÖÐÒÇÆ÷c µÄÃû³ÆÊÇ¡¡           ¡¡¡£
£¨2£©A ×°ÖÃÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ¡¡                                  ¡¡¡£
£¨3£©ÈôÓøßÃÌËá¼ØÖÆÈ¡ÑõÆø£¬Æ仯ѧ·½³ÌʽΪ¡¡                          ¡¡£¬ÈôÓÃD×°ÖÃÊÕ¼¯ÑõÆø£¬ÑéÂúµÄ·½·¨ÊÇ¡¡                                       ¡¡¡£
£¨4£©F ×°ÖôÓa¡¢b ÖÐijһ¸ö½Ó¿Ú½øÆø£¬¿ÉÒÔ´úÌæD¡¢E ×°ÖÃÊÕ¼¯ÆøÌ壬²¢ÇÒ¿ÉÒÔ¼õÉÙÆøÌåÏò¿ÕÆøÖеÄÒݳö£®ÏÖÓÃB¡¢F×°ÖÃÀ´ÖÆÈ¡²¢ÊÕ¼¯¶þÑõ»¯Ì¼ÆøÌ壬Á¬½ÓB ×°ÖõÄÓ¦ÊÇ¡¡ ¡¡£¨Ñ¡Ìî¡°a¡±»ò¡°b¡±£©¡£

£¨1£©³¤¾±Â©¶·  £¨2£©CaCO3+2HCl=CaCl2+H2O+CO2¡ü  £¨3£©2KMnO4¡÷K2MnO4+MnO2+O2¡ü  ½«Ò»¸ù´ø»ðÐǵÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú£¬ÈôľÌõ¸´È¼£¬ÔòÊÕ¼¯Âú £¨4£©a

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨7 ·Ö£©ÈçÏÂͼËùʾΪʵÑéÊÒÖг£¼ûÆøÌåÖƱ¸¡¢¾»»¯¡¢¸ÉÔï¡¢ÊÕ¼¯ºÍÐÔÖÊʵÑéµÄ²¿·ÖÒÇÆ÷¡£Ä³Ñ§Ð£Á½¸ö»¯Ñ§ÊµÑé̽¾¿»î¶¯Ð¡×éµÄͬѧÓûÓÃËüÃÇÍê³É¸÷×ÔµÄ̽¾¿ÊµÑé¡£

£¨1£©µÚÒ»×éµÄͬѧÒÔ¹ýÑõ»¯ÇâÈÜҺΪԭÁÏ£¨MnO2Ϊ´ß»¯¼Á£© £¬ÔÚʵÑéÊÒÖÐÖƱ¸²¢ÊÕ¼¯Ò»Æ¿¸ÉÔï´¿¾»µÄÑõÆø£¬°´ÕÕÒªÇóÉè¼ÆʵÑé×°Öà ¡¢Á¬½ÓÒÇÆ÷£¬²¢¼ìÑé×°ÖõÄÆøÃÜÐÔ¡£
¢ÙËùÑ¡ÒÇÆ÷µÄÁ¬½Ó˳ÐòΪ       ¡ú          ¡ú£¨ÌîдÒÇÆ÷ÐòºÅ×Öĸ£©¡£
¢ÚÒÇÆ÷ A ÖÐËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                            ¡£
¢ÛÑéÖ¤ÑõÆøÊÕ¼¯ÂúµÄ·½·¨ÊÇ                                 ¡£
£¨2£©µÚ¶þ×éµÄͬѧΪ̽¾¿¶þÑõ»¯Ì¼µÄÐÔÖÊ£¬½øÐÐÁËÈçÏÂʵÑé¡£
¢Ù¼ìÑéÆøÌåΪCO2ӦѡÔñÉÏÊöÒÇÆ÷ÖеĠ      £¨Ìî¡°B¡±»ò¡°D¡± £©¡£ Ëù·¢ÉúµÄ»¯Ñ§·´Ó¦·½³ÌʽΪ                                    ¡£
¢Ú½«¶þÑõ»¯Ì¼Í¨ÈëÇâÑõ»¯ÄÆÈÜÒºÖУ¬²¢ÎÞÃ÷ÏÔ·´Ó¦ÏÖÏó£¬ÇëÄãд³öÒ»ÖÖ»¯Ñ§·½·¨£¬Ö¤Ã÷ CO2ºÍ NaOH ÈÜҺȷʵ·¢ÉúÁË»¯Ñ§·´Ó¦¡£·½·¨ÊÇ£¨Ð´³öÊÔ¼Á¡¢ÏÖÏó¡¢½áÂÛ£©£º                                        ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø