ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿£¨10·Ö£©Ì¼ÔªËØÊÇ×é³ÉÐí¶àÎïÖʵĻù±¾ÔªËØ¡£
£¨1£©¼×Í飨CH4£©ÊÇÒ»ÖÖÇå½àÄÜÔ´¡£ÔÚ¼×ÍéÖÐ̼ÇâÔªËØÖÊÁ¿±È £¬0.1molº¬ÓÐ ¸ö¼×Íé·Ö×Ó£¬ÖÊÁ¿Îª g¡£Ð´³ö¼×ÍéÍêȫȼÉյĻ¯Ñ§·½³Ìʽ ¡£
£¨2£©·ÖÎöÏÂ±í£¬ÓëúÏà±È£¬ÓÃÌìÈ»Æø×÷ȼÁϵÄÓŵãÓÐ ¡£
1gÎïÖÊÍêȫȼÉÕ | ||
²úÉú¶þÑõ»¯Ì¼µÄÖÊÁ¿/g | ·Å³öµÄÈÈÁ¿/kJ | |
¼×Íé | 2.75 | 56 |
̼ | 3.67 | 32 |
£¨3£©ÎªÌá¸ßúµÄÀûÓÃÂÊ£¬¿É½«Æäת»¯Îª¿ÉȼÐÔÆøÌ壬¸Ã·´Ó¦µÄ΢¹ÛʾÒâͼÈçÏ£¬ÔòÉú³ÉÎïµÄ·Ö×Ó¸öÊý±ÈΪ ¡£
£¨4£©»¯Ê¯È¼ÁÏÖ÷Òª°üÀ¨Ãº¡¢ ºÍÌìÈ»Æø¡£
£¨5£©ºÜ¶àÌìÈ»¿óʯÖк¬ÓÐ̼ԪËØ£¬ÁâÃÌ¿óµÄÖ÷Òª³É·ÖÊÇ̼ËáÃÌ(MnCO3)£¬ÆäÖÐÃÌÔªËصĻ¯ºÏ¼ÛΪ ¡£
£¨6£©ÒºÌ¬¶þÑõ»¯Ì¼¿ÉÓÃÓÚÆ˾ȵµ°¸ÊÒ·¢ÉúµÄ»ðÔÖ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ £¨Ìî×ÖĸÐòºÅ£©¡£
A£®ÒºÌ¬¶þÑõ»¯Ì¼Æû»¯ºó²»»áÎÛȾµµ°¸
B£®¶þÑõ»¯Ì¼¿É¸²¸ÇÔÚ¿ÉȼÎï±íÃ棬¸ô¾ø¿ÕÆø
C£®ÒºÌ¬¶þÑõ»¯Ì¼Æû»¯Ê±ÎüÈÈ£¬½µµÍ¿ÉȼÎïµÄ×Å»ðµã
¡¾´ð°¸¡¿£¨1£©3¡Ã1 6.02¡Á1022 1.6 CH4 + 2O2µãȼCO2 + 2H2O
£¨2£©µÈÖÊÁ¿µÄÌìÈ»ÆøºÍúÍêȫȼÉÕ£¬ÌìÈ»ÆøȼÉÕ²úÉú¶þÑõ»¯Ì¼µÄÖÊÁ¿ÉÙÓÚú£¬·Å³öµÄÈÈÁ¿¶àÓÚú
£¨3£©1:1 £¨4£©Ê¯ÓÍ £¨5£©+ 2 £¨6£©AB
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©¼×Í飨CH4£©ÖÐ̼ÇâÔªËØÖÊÁ¿±È=12:1¡Á4=3¡Ã1£»1molº¬ÓÐÎïÖÊÖк¬ÓеķÖ×ÓÊý6.02¡Á1023£¬¹Ê0.1molº¬ÓÐ6.02¡Á1022£¬ÖÊÁ¿=0.1mol¡Á16g/ mol=1.6 g£»¼×ÍéÍêȫȼÉյĻ¯Ñ§·½³ÌʽΪ£ºCH4 + 2O2µãȼCO2 + 2H2O
£¨2£©¸ù¾Ý±íÖÐÊý¾Ý·ÖÎö£¬ÓëúÏà±È£¬ÓÃÌìÈ»Æø×÷ȼÁϵÄÓŵãÓеÈÖÊÁ¿µÄÌìÈ»ÆøºÍúÍêȫȼÉÕ£¬ÌìÈ»ÆøȼÉÕ²úÉú¶þÑõ»¯Ì¼µÄÖÊÁ¿ÉÙÓÚú£¬·Å³öµÄÈÈÁ¿¶àÓÚú
£¨3£©¸ù¾Ý·´Ó¦µÄ΢¹ÛʾÒâͼ£¬¿Éд³ö»¯Ñ§·½³Ìʽ£ºH2O + C ¸ßΠH2 + CO£¬¹ÊÉú³ÉÎïµÄ·Ö×Ó¸öÊý±È1:1 £¨4£©»¯Ê¯È¼ÁÏÖ÷Òª°üÀ¨Ãº¡¢Ê¯ÓͺÍÌìÈ»Æø
£¨5£©¸ù¾ÝÔªËØ»¯ºÏ¼ÛµÄÒ»°ã¹æÂÉ£ºÔÚ»¯ºÏÎïÖУ¬Õý¸º»¯ºÏ¼ÛµÄ´úÊýºÍΪ0£¬ÔÚ̼ËáÃÌ(MnCO3)ÖУ¬CO3µÄ»¯ºÏ¼ÛΪ-2£¬¹ÊÃÌÔªËصĻ¯ºÏ¼Û+ 2
£¨6£©A¡¢ÒºÌ¬¶þÑõ»¯Ì¼Æû»¯ºó²»»áÎÛȾµµ°¸£¬ÕýÈ·£¬B¡¢¶þÑõ»¯Ì¼¿É¸²¸ÇÔÚ¿ÉȼÎï±íÃ棬¸ô¾ø¿ÕÆø£¬ÕýÈ·£¬C¡¢ÒºÌ¬¶þÑõ»¯Ì¼Æû»¯Ê±ÎüÈÈ£¬½µµÍζȣ¬Ê¹Î¶ȵÍÓÚ¿ÉȼÎïµÄ×Å»ðµã£¬¶ø²»ÊǽµµÍ×Å»ðµã£¬¹ÊÑ¡°ÎAB