ÌâÄ¿ÄÚÈÝ

£¨18·Ö£©¹¤ÒµÉռNaOH£©¾ßÓнϺõÄɱ¾úÏû¶¾×÷ÓÃÇÒÁ®¼ÛÒ׵㬵«¹¤ÒµÉÕ¼îÖг£º¬ÓÐÔÓÖÊ̼ËáÄÆ¡£Ä³»¯Ñ§Ñ§Ï°Ð¡×éͬѧΧÈƹ¤ÒµÉÕ¼îÕ¹¿ªÏµÁÐÑо¿¡£
̽¾¿Ò»£º¹¤ÒµÉÕ¼îÖÐÊÇ·ñº¬ÓÐ̼ËáÄÆ
¡¾²éÔÄ×ÊÁÏ¡¿Ì¼ËáÄƺÍÂÈ»¯¸ÆÄÜ·¢Éú¸´·Ö½â·´Ó¦¡£
СºìÖ¸³ö¿ÉÑ¡ÓÃÏÂÁÐʵÑéÒ©Æ·À´Ì½¾¿£ºÏ¡ÑÎËá¡¢·Ó̪ÊÔÒº¡¢CaCl2ÈÜÒº¡£
£¨1£©Ð¡×éͬѧ¾­¹ýÌÖÂÛºó£¬Ò»ÖÂÈÏΪʹÓà                Ò©Æ·²»Äܴﵽ̽¾¿Ä¿µÄ£¬ÀíÓÉÊÇ                                                                  ¡£
£¨2£©Çë¸ù¾ÝÑ¡ÓõÄʵÑéÒ©Æ·Íê³ÉÏÂÁÐʵÑ鱨¸æ£º
ʵÑé²Ù×÷
ʵÑéÏÖÏó
ʵÑé½áÂÛ
È¡ÉÙÁ¿¹¤ÒµÉÕ¼îÑùÆ·Åä³ÉÈÜÒººó£¬µÎ¼Ó¹ýÁ¿          
 
             
¹¤ÒµÉÕ¼îÖк¬ÓÐ̼ËáÄÆ£¬²úÉúʵÑéÏÖÏóµÄ»¯Ñ§·½³Ìʽ£º                         ¡£
   Ì½¾¿¶þ£º²â¶¨¹¤ÒµÉÕ¼îÑùÆ·µÄ´¿¶È
С×éͬѧÀûÓÃÏÂͼËùʾװÖòⶨ¹¤ÒµÉÕ¼îÑùÆ·µÄ´¿¶È£¨¹Ì¶¨×°ÖÃÊ¡ÂÔ£©

¡¾ÊµÑé²½Öè¡¿
¢Ù°´Í¼Á¬½Ó×°Ö㬲¢¼ì²é×°ÖõÄÆøÃÜÐÔ£»
¢Ú³ÆÁ¿Ò»¶¨Á¿µÄÉÕ¼îÑùÆ·ºÍ¸ÉÔï¹ÜCµÄÖÊÁ¿£»
¢Û´ò¿ªµ¯»É¼ÐK£¬¹ÄÈëN2Ò»¶Îʱ¼ä£»
¢Ü½ÓÈë×°ÖÃC¡¢D£¬¹Ø±Õµ¯»É¼ÐK£¬×°ÖÃAÖмÓÈëÏ¡ÁòËᣬÖÁ²»ÔÙ²úÉúÆøÅÝΪֹ£»
¢ÝÖظ´²½Öè¢Û²Ù×÷£¬ÖÁ¸ÉÔï¹ÜCÖÊÁ¿²»ÔÙÔö¼Ó¡£
ÊԻشðÏÂÁÐÏà¹ØÎÊÌ⣺
£¨1£©×°ÖÃBÖÐŨÁòËáµÄ×÷ÓÃÊÇ                       £»ÒÑÖª¼îʯ»ÒµÄÖ÷Òª³É·ÖÊÇCaOºÍNaOH£¬Ôò×°ÖÃDµÄ×÷ÓÃÊÇ                                                    ¡£
£¨2£©²½Öè¢Û²Ù×÷µÄÄ¿µÄÊÇ                                 £»Èç¹û²½Öè¢ÝûÓÐÖظ´²½Öè¢ÛµÄ²Ù×÷£¬Ôò²â¶¨ÉÕ¼îÑùÆ·µÄ´¿¶È½«              £¨Ñ¡Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©¡£
£¨3£©²½Öè¢ÝÖиÉÔï¹ÜCÖÊÁ¿²»ÔÙÔö¼Ó£¬ËµÃ÷                           £¬Ð´³öNaOHÓëÉú³ÉµÄÆøÌå·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                                                ¡£
£¨4£©ÏÂÁвÙ×÷»áÓ°Ïìµ½²âÁ¿½á¹ûµÄÊÇ              £¨ÌîÐòºÅ£©¡£
A£®°ÑÏ¡ÁòËá¸ÄΪϡÑÎËá                  B£®Ï¡ÁòËá¹ýÁ¿
C£®¹ÄÈëN2ʱ¼ä½Ï³¤                      D£®Ê¡ÂÔ×°ÖÃD
̽¾¿»î¶¯Ò»£¨1£©·Ó̪ÊÔÒº£¨1·Ö£©  NaOHºÍNa2CO3µÄË®ÈÜÒº¶¼³Ê¼îÐÔ¶¼ÄÜʹÎÞÉ«·Ó̪±äºìÉ«(2·Ö)   £¨2£©Ï¡ÑÎËᣨ»òCaCl2ÈÜÒº£©  ²úÉúÆøÅÝ£¨»ò³Áµí£© Na2CO3 +2HCl =" 2NaCl" + H2O +CO2¡ü£¨»òCaCl2+ Na2CO3 = CaCO3¡ý+ 2NaCl£©£¨·½³Ìʽ3·Ö£¬ÆäÓà1·Ö£©
̽¾¿»î¶¯¶þ£¨1£©ÎüÊÕË®·Ö  ·ÀÖ¹¿ÕÆøÖеÄË®·ÖºÍ¶þÑõ»¯Ì¼½øÈë×°ÖÃCÖУ¬Ó°Ïì²âÁ¿½á¹û
£¨2£©°Ñ×°ÖÃA¡¢BÖк¬ÓжþÑõ»¯Ì¼µÄ¿ÕÆøÅž¡£¬ÒÔÃâÓ°Ïì²âÁ¿½á¹û   Æ«¸ß£¨¸÷1·Ö£©
£¨3£©Éú³ÉµÄ¶þÑõ»¯Ì¼ÒÑÍêÈ«±»ÎüÊÕ£¨1·Ö£©   2NaOH + CO2 = Na2CO3 + H2O £¨3·Ö£©
£¨4£©AD £¨2·Ö£©

ÊÔÌâ·ÖÎö£ºÌ½¾¿Ò»£º£¨1£©ÇâÑõ»¯ÄƺÍ̼ËáÄƵÄÈÜÒº¶¼³Ê¼îÐÔ£¬¶¼¿Éʹ·Ó̪ÊÔÒº±äºì¡£ËùÒÔ²»ÄÜÓ÷Ó̪ÊÔÒº¡£
£¨2£©Ì¼ËáÄÆ¿ÉÓëÑÎËá·´Ó¦Éú³É¶þÑõ»¯Ì¼ÆøÌ壬»á¹Û²ìµ½ÓÐÆøÅÝÉú³É¡£·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºNa2CO3 +2HCl =" 2NaCl" + H2O +CO2¡ü£¨ÇâÑõ»¯ÄÆÓëÑÎËá·´Ó¦ÎÞÏÖÏó£©
ÂÈ»¯¸Æ¿ÉÓë̼ËáÄÆ·´Ó¦Éú³É̼Ëá¸Æ³Áµí£¬»á¹Û²ìµ½Óа×É«³ÁµíÉú³É£»·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCl2+ Na2CO3 = CaCO3¡ý+ 2NaCl£¨ÇâÑõ»¯ÄƲ»ÓëÂÈ»¯¸Æ·´Ó¦£©  ¿É¾Ý´Ë»Ø´ð¡£
̽¾¿¶þ£º²â¶¨¹¤ÒµÉÕ¼îÑùÆ·µÄ´¿¶È
£¨1£©ÑùÆ·ÖеÄ̼ËáÄÆÓëÏ¡ÁòËá·´Ó¦Éú³ÉµÄ¶þÑõ»¯Ì¼ÆøÌ壬C×°ÖÃÖеÄÒ©Æ·¿ÉÓëÉú³ÉµÄ¶þÑõ»¯Ì¼ÆøÌå·´Ó¦£¬½øÒ»²½²â³öÆäÖÊÁ¿¡£ÔÙÀûÓöþÑõ»¯Ì¼µÄÖÊÁ¿¼ÆËã³öÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿¡£AÖÐÉú³ÉµÄ¶þÑõ»¯Ì¼ÆøÌå»á´ÓÈÜÒºÖдø³öÒ»²¿·ÖË®ÕôÆø£¬Èç½øÈëC×°Öûáʹ²âµÃµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿±ä´ó£»Òò´Ë×°ÖÃBÖÐŨÁòËáµÄ×÷ÓÃÊÇÎüÊÕÆøÌåÖеÄË®ÕôÆø£»Ôò×°ÖÃDµÄ×÷ÓÃÊÇ·ÀÖ¹¿ÕÆøÖеĶþÑõ»¯Ì¼ÆøÌåºÍË®ÕôÆø½øÈë×°ÖÃCÖУ¬Ó°Ïì²âÁ¿½á¹û¡£
£¨2£©²½Öè¢Û²Ù×÷µÄÄ¿µÄÊÇÓÃͨÈëµÄµªÆø°Ñ×°ÖÃA¡¢BÖк¬ÓжþÑõ»¯Ì¼µÄ¿ÕÆøÅž¡£¬ÒÔÃâÓ°Ïì²âÁ¿½á¹û£»Èç¹û²½Öè¢ÝûÓÐÖظ´²½Öè¢ÛµÄ²Ù×÷£¬Ôò¿ÉÄÜ»áʹһ²¿·Ö¶þÑõ»¯Ì¼ÆøÌåûÓнøÈëD×°Öã¬Ê¹¼ÆËã³öµÄ̼ËáÄƵÄÖÊÁ¿¼õС£¬´Ó¶øʹ²â¶¨ÉÕ¼îÑùÆ·µÄ´¿¶È½«Æ«¸ß¡£
£¨3£©²½Öè¢ÝÖиÉÔï¹ÜCÖÊÁ¿²»ÔÙÔö¼Ó£¬ËµÃ÷Éú³ÉµÄ¶þÑõ»¯Ì¼ÒÑÍêÈ«±»ÎüÊÕ£¬Ð´³öNaOHÓëÉú³ÉµÄÆøÌå¶þÑõ»¯Ì¼·´Ó¦»áÉú³É̼ËáºÍË®£¬»¯Ñ§·½³ÌʽΪ£º2NaOH + CO2 = Na2CO3 + H2O¡£
£¨4£©A£®ÑÎËáÓÐÒ»¶¨µÄ»Ó·¢ÐÔ£¬Èç½øÈëC×°ÖûᷢÉú·´Ó¦£¬´Ó¶øʹ²â¶¨µÄ̼ËáµÄÖÊÁ¿·ÖÊý±ä´ó£¬¼´ÇâÑõ»¯ÄƵÄÖÊÁ¿·ÖÊý±äС¡£B£®Ï¡ÁòËá¹ýÁ¿ÄÜÈÃÑùÆ·ÖеÄ̼ËáÈ«²¿·´Ó¦£¬¶Ô½á¹ûÎÞÓ°Ïì¡£C£®¹ÄÈëN2ʱ¼ä½Ï³¤¿ÉʹÉú³ÉµÄ¶þÑõ»¯Ì¼ÆøÌåÈ«²¿½øÈëC×°Öã¬ÄÜʹ½á¹û¸ü׼ȷ¡£D£®Ê¡ÂÔ×°ÖÃD»áʹһ²¿·Ö¿ÕÆø½øÈë×°ÖÃC£¬Ôòʹ²â¶¨µÄ̼ËáÄƵÄÖÊÁ¿·ÖÊý±ä´ó£¬ÇâÑõ»¯ÄƵÄÖÊÁ¿·ÖÊý±äС¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨13·Ö£©¸âµãÊèËɼÁµÄÖ÷Òª³É·ÖÖÐÓÐ̼ËáÇâÄÆ¡£Ä³»¯Ñ§ÐËȤС×éµÄͬѧ¶Ô̼ËáÇâÄƵÄÐÔÖʽøÐÐÁË̽¾¿¡£
¢ñ£®¶¨ÐÔ̽¾¿
ʵÑéÒ»£ºÌ½¾¿Ì¼ËáÇâÄÆÈÜÒºµÄËá¼îÐÔ
ÓÃpHÊÔÖ½²âµÃ̼ËáÇâÄÆÈÜÒºµÄpHԼΪ10£¬¿É֪̼ËáÇâÄÆÈÜÒº³Ê       ÐÔ¡£
ʵÑé¶þ£ºÌ½¾¿Ì¼ËáÇâÄƵÄÈÈÎȶ¨ÐÔ
¡¾²éÔÄ×ÊÁÏ¡¿Ì¼ËáÇâÄÆÊÜÈÈÈÝÒ׷ֽ⣬Éú³ÉË®¡¢¶þÑõ»¯Ì¼ºÍÒ»ÖÖ³£
¼ûµÄ¹ÌÌåÎïÖÊ¡£
¡¾ÊµÑé1¡¿È¡Ò»¶¨ÖÊÁ¿µÄ̼ËáÇâÄƷŵ½Í­Æ¬ÉϼÓÈÈ£¬ÈçͼËùʾ¡£

£¨1£©¼ÓÈÈÒ»¶Îʱ¼äºó£¬¹Û²ìµ½ÉÕ±­ÄÚ±ÚÓÐË®Öé¡£
£¨2£©³ä·Ö¼ÓÈÈºó£¬ ½«ÉÕ±­Ñ¸ËÙµ¹×ª¹ýÀ´£¬µ¹ÈëÊÊÁ¿µÄ³ÎÇåʯ»ÒË®£¬
Õñµ´£¬¹Û²ìµ½Ê¯»ÒË®±ä»ë×Ç¡£
£¨3£©Óûͨ¹ý½øÒ»²½µÄʵÑé̽¾¿À´È·¶¨³ä·Ö¼ÓÈȺóµÄ¹ÌÌå²úÎïµÄ³É·Ö¡£
¡¾Ìá³ö¼ÙÉè¡¿¢Ù¿ÉÄÜÊÇNa2CO3  ¢Ú¿ÉÄÜÊÇNaOH  ¢Û¿ÉÄÜÊÇNaOHºÍNa2CO3 
¡¾ÊµÑé2¡¿
ʵÑé²Ù×÷
ʵÑéÏÖÏó
ʵÑé½áÂÛ
A£®½«¸Ã¹ÌÌåÈÜÓÚÕôÁóË®ÅäÖƳÉÈÜÒº£¬È¡ÉÙÁ¿ÈÜÒºÓÚÊÔ
¹ÜÖУ¬µÎ¼Ó×ãÁ¿Ï¡ÑÎËá
ÓÐÆøÌå²úÉú
¼ÙÉè £¨ÌîÐòºÅ£©²»³ÉÁ¢
B£®ÁíÈ¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬µÎ¼Ó×ãÁ¿ÂÈ»¯±µÈÜÒº
      
¹ÌÌå²úÎïÖÐÓÐ
Na2CO3
C£®È¡ÉÏÊöB²½Öè¾²ÖúóËùµÃÉϲãÇåÒº£¬µÎÈëÉÙÁ¿·Ó̪
ÈÜÒº
ÎÞÃ÷ÏÔÏÖÏó
¹ÌÌå²úÎïÖР 
¡¾ÊµÑé½áÂÛ¡¿NaHCO3ÊÜÈÈ·Ö½âµÄ»¯Ñ§·½³ÌʽΪ                                 ¡£
¢ò£®¶¨Á¿Ì½¾¿
Ϊ²â¶¨Ä³ÊèËɼÁÖÐ̼ËáÇâÄƵÄÖÊÁ¿·ÖÊý£¬Éè¼ÆÁËÈçÏÂʵÑ飬ÆäÖ÷ҪʵÑé²½ÖèÈçÏ£º
¢Ù°´ÏÂͼ×é×°ÒÇÆ÷£¬È¡50.0gÑùÆ··ÅÈë׶ÐÎÆ¿ÖУ¬¼ÓÈë×ãÁ¿Ï¡ÁòËáÈÜÒº£»¢Ú²âÁ¿Ò»¶¨Ê±¼äÄÚ¸ÉÔï¹ÜÄÚ¼îʯ»Ò£¨Ñõ»¯¸ÆºÍÇâÑõ»¯ÄƹÌÌåµÄ»ìºÏÎÔö¼ÓµÄÖÊÁ¿£¨¼ûÏÂͼÇúÏߣ©£»¢Û´ý׶ÐÎÆ¿Öв»ÔÙ²úÉúÆøÅÝʱ£¬¹Ø±Õ»îÈûb£¬´ò¿ª»îÈûa£¬´Óµ¼¹ÜA´¦»º»º¹ÄÈëÒ»¶¨Á¿µÄ¿ÕÆø£»¢ÜÔٴγÆÁ¿¸ÉÔï¹ÜÄÚÎïÖÊÔö¼ÓµÄÖÊÁ¿£»¢ÝÖظ´²½Öè¢ÛºÍ¢ÜµÄ²Ù×÷£¬Ö±ÖÁ¸ÉÔï¹ÜÄÚÎïÖÊÖÊÁ¿²»±ä¡£

£¨1£©²½Öè¢Ù¼ÓÈëÑùÆ·Ç°»¹Ó¦                     ¡£
£¨2£©×°ÖÃÒÒµÄ×÷ÓÃÊÇ         £»ÊµÑé²½Öè¢ÛÖУ¬¼××°ÖõÄ×÷ÓÃÊÇ          ¡£
£¨3£©ÇëÀûÓÃÏà¹ØÊý¾Ý¼ÆËãÑùÆ·ÖÐ̼ËáÇâÄƵÄÖÊÁ¿·ÖÊý¡££¨Ð´³ö¼ÆËã¹ý³Ì£©
(13·Ö)´Ó2013Ä꿪ʼ£¬Ñ§ÉúʵÑé²Ù×÷³É¼¨¼ÆÈëÖп¼£¬Ä³Ð£½øÐÐʵÑ鿼²é£¬¸ø³öÒÔÏÂÈý¸ö¿¼Ì⣺¢Ù´ÖÑÎÌá´¿£»¢Ú¶þÑõ»¯Ì¼µÄÖÆÈ¡£»¢ÛÑõÆøµÄÖÆÈ¡¡£¿¼²é¹æ¶¨ÓÉѧÉú³éÇ©È·¶¨¿¼Ìâ¡£

¢ñ. ¼×ͬѧ³éÇ©ºó±»¼à¿¼ÀÏʦÒýµ¼ÖÁ×¼±¸ÁËÉÏͼÒÇÆ÷ºÍÒ©Æ·µÄʵÑę́ǰ£º
(1)ÉÏͼÖÐÒÇÆ÷AµÄÃû³ÆÊÇ        £»¼×ͬѧ³éµ½µÄ¿¼ÌâÊÇ         £¨ÌîÐòºÅ£©£»ÊµÑéÇ°¼×ͬѧ·¢ÏÖÆäÖÐȱÉÙÁËÒ»ÖÖÒ©Æ·£¬¸ÃÒ©Æ·ÊÇ     £»Ð´³ö¸ÃʵÑé·´Ó¦µÄ»¯Ñ§·½³Ìʽ                         ¡£
£¨2£©ÏÂͼÊǼ×ͬѧʵÑéʱµÄÖ÷Òª²½Ö裬ÆäÖÐ×°ÖÃÓÐÎóµÄÊÇ £¨Ìî×Öĸ±êºÅ£©£¬¸ÄÕýµÄ·½·¨ÊÇ         ¡£

£¨3£©µ±¹Û²ìµ½                          ÏÖÏóʱ£¬¼×ͬѧ¿ÉÒÔ¿ªÊ¼b²Ù×÷¡£
¢ò.ÒÒͬѧ³éÇ©ºó£¬¼à¿¼ÀÏʦ¸æËßËû£ºÊ³ÑÎÑùÆ·Öк¬ÓÐÉÙÁ¿É³ÍÁ¡¢ÂÈ»¯¸ÆºÍÂÈ»¯Ã¾¡£ÒÒͬѧ˼¿¼ºó°´ÒÔÏÂÁ÷³Ì³ýȥʳÑÎÑùÆ·ÖÐɳÍÁ¡¢ÂÈ»¯¸ÆºÍÂÈ»¯Ã¾£º

Çë¸ù¾ÝÁ÷³Ìͼ»Ø´ð£º
£¨1£©²Ù×÷¢ñµÄÃû³ÆÊÇ        £»¼ÓÈëµÄÊÔ¼ÁAÊÇ          
£¨2£©Ð´³öNaOHÓëÔÓÖÊ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                     £»
£¨3£©¼ÓÈëÊÔ¼ÁBºó·¢ÉúµÄÓйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                              ¡£
ijÑо¿ÐÔѧϰС×éµÄͬѧÔÚÒ»´Î̽¾¿»î¶¯ÖУ¬¶ÔÒ»·Ý´¿¼îÑùÆ·£¨º¬ÓÐÉÙÁ¿ÂÈ»¯ÄÆ£©µÄ´¿¶È½øÐвⶨ£¬ÇëÄã²ÎÓë²¢»Ø´ðÓйØÎÊÌâ¡£

¢Å ¼×ͬѧ½øÐÐÈçϲÙ×÷£º
¢Ù ×é×°ºÃÈçͼÒÇÆ÷£¬²¢¼ì²é___________ £»
¢Ú È¡6.0gÊÔÑù·ÅÈë׶ÐÎÆ¿ÖУ¬¼ÓÈëÉÙÁ¿ÕôÁóË®Èܽ⣬²¢ÔÚÆäËû×°ÖÃÖмÓÈëÏàÓ¦µÄÒ©Æ·£»
¢Û ³ÆÁ¿Ê¢ÓÐÐÂÖƳÎÇåʯ»ÒË®µÄ×°ÖÃCµÄÖÊÁ¿£»
¢Ü ´ò¿ª·ÖҺ©¶·ÐýÈûµÎÈëÑÎËᣬֱµ½²»ÔÙ²úÉúÆøÅÝΪֹ£»
¢Ý ÔٴγÆÁ¿×°ÖÃC µÄ×ÜÖÊÁ¿£»
¢Þ ¼ÆËã³öÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊý¡£
¢Æ ÉÏͼB×°ÖõÄ×÷ÓÃÊÇ______________£» D×°ÖõÄ×÷ÓÃÊÇ__________________________¡£
¡¾ÒâÍâ·¢ÏÖ¡¿CÆ¿ÖÐʯ»ÒˮûÓбä»ë×Ç£¬Í¬Ñ§ÃǸе½¾ªÆæ²¢²úÉúÁË̽¾¿µÄÓûÍû¡£
¡¾Ìá³ö²ÂÏë¡¿Ô­Òò²ÂÏ룺
¢ÙÊÇÉú³ÉµÄÆøÌåÖлìÓÐÑÎËá»Ó·¢³öÀ´µÄHCl£»
¢ÚÊÇÉú³ÉµÄÆøÌåÁ÷ËÙÌ«¿ì£¬Óëʯ»ÒË®·´Ó¦²úÉúÁË¿ÉÈÜÐÔÎïÖÊ[¾­²é×ÊÁÏ·ÖÎö¿ÉÈÜÐÔÎïÖÊÊÇCa(HCO3)2£¬ËüÄÜÓëËá·´Ó¦Éú³ÉCO2µÈÎïÖÊ]¡£
¡¾ÊµÑé̽¾¿¡¿
¼×ͬѧȡÉÙÁ¿ÊµÑéºóCÆ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÆäÖÐÒÀ´ÎµÎ¼Ó×ãÁ¿Ï¡HNO3ºÍAgNO3ÈÜÒº£¬ÎÞÆøÅݵ«ÓгÁµí²úÉú¡£¾Ý´ËÅжÏÖ»ÓвÂÏë  __£¨Ìî¡°¢Ù¡±»ò¡°¢Ú¡±£©³ÉÁ¢¡£
¡¾½»Á÷ÌÖÂÛ¡¿
¶ÔÓÚÈçºÎ¸Ä½øʵÑ飬ÒÒͬѧÈÏΪ£ºÓ¦½«ÑÎËá»»³ÉÏ¡ÁòËᣬÐÂÖƵijÎÇåʯ»ÒË®»»³É×ãÁ¿NaOHÈÜÒº£»±ûͬѧÈÏΪ£ºÓ¦ÔÚ×°ÖÃAºÍBÖмä²åÈëÒ»¸öÊ¢Óб¥ºÍNaHCO3ÈÜÒºµÄÏ´Æø×°ÖÃÒÔÎüÊÕHCl£¨CO2²»ÈÜÓÚ±¥ºÍNaHCO3ÈÜÒº£¬Ò²²»ÓëÆä·´Ó¦£©£¬²¢½«ÐÂÖƵijÎÇåʯ»ÒË®»»³É×ãÁ¿NaOHÈÜÒº ¡£
´ó¼ÒÌÖÂÛºóÈÏΪ£ºÒÒͬѧµÄ·½°¸¿ÉÐжø±ûͬѧµÄ·½°¸²»¿ÉÐС£
¡¾ÇëÄãÆÀ¼Û¡¿
±ûͬѧ·½°¸²»¿ÉÐеÄÔ­ÒòÊÇ                                               ¡£
¡¾½Ìʦµã²¦¡¿
¼´±ã»»³ÉÏ¡ÁòËáºÍNaOHÈÜÒº£¬·´Ó¦Ç°ºó×°ÖÃÖдæÔÚµÄCO2Ò²»áʹ²â¶¨³öµÄÑùÆ·´¿¶È²»×¼È·¡£
¡¾ÇëÄã¸Ä½ø¡¿
ÔÚÉÏÊö»ù´¡ÉÏ£¬ÄãµÄ´ëÊ©ÊÇ                                                ¡£
ͬѧÃÇÈÔ³ÆÈ¡6.0gÊÔÑù£¬ÓøĽøÍêÉƺóµÄ·½°¸ÖØÐÂʵÑé¡£
¡¾Êý¾Ý´¦Àí¡¿
×°ÖÃCʵÑéÇ°ºóÁ½´Î³ÆÁ¿µÄÖÊÁ¿²îΪ2.2g£¬ÔòÑùÆ·µÄ´¿¶ÈΪ           _¡££¨Áгö¼ÆËã¹ý³Ì£©
¡¾ÊµÑ鷴˼¡¿
Èô²»ÓÃÉÏÊö·½·¨£¬¶øÓÃÉú³É³ÁµíµÄ·½·¨À´²â¶¨ÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊý£¬¿ÉÑ¡ÓõÄÊÔ¼ÁÊÇ                    ¡£
(5.5·Ö)ΪÑéÖ¤¶þÑõ»¯Ì¼ºÍÇâÑõ»¯ÄÆÈÜҺȷʵÄÜ·¢Éú»¯Ñ§·´Ó¦£¬Á½¸ö»¯Ñ§ÐËȤС×éµÄͬѧ½øÐÐÁËÈçÏÂ̽¾¿»î¶¯¡£
¢ÅµÚһС×飺СÀòͬѧÉè¼ÆÁËÈçÏÂͼËùʾʵÑé×°Ö㬼¯ÆøÆ¿ÖгäÂú¶þÑõ»¯Ì¼ÆøÌ壬µÎ¹ÜÖÐÎüÈëÁËÇâÑõ»¯ÄÆÈÜÒº£¬¼¯ÆøÆ¿ÖеÄÆøÇòͨ¹ýµ¼Æø¹ÜÓëÍâ½ç¿ÕÆøÏàͨ¡£

ʵÑé²½Öè
ʵÑéÏÖÏó
ʵÑé½áÂÛ
¼·Ñ¹µÎ¹ÜÏ𽺽ºÃ±£¬Ê¹ÇâÑõ»¯ÄÆÈÜÒºµÎÈ뼯ÆøÆ¿ÖС£
ÆøÇòÖð½¥±ä´ó
¶þÑõ»¯Ì¼ºÍÇâÑõ»¯ÄÆÈÜҺȷʵ·¢ÉúÁË»¯Ñ§·´Ó¦
ͬ×éµÄС»ªÍ¬Ñ§¶Ô´ËÌá³öÖÊÒÉ£¬Ëû½«ÉÏÊöʵÑéµÎ¹ÜÖеÄÇâÑõ»¯ÄÆÈÜÒº»»³É        £¬È»ºóÔÙÖظ´Íê³ÉʵÑ飬¹Û²ìµ½ÏÖÏóÊÇ        ¡£Ð¡»ª²¹³äÕâһʵÑéµÄÔ­ÒòÊÇ        ¡£
¢ÆµÚ¶þС×飺СÇØͬѧ¶ÔʵÑé×°ÖÃ×öÁËÈçͼ¸Ä½ø¡£¼¯ÆøÆ¿ÖгäÂú¶þÑõ»¯Ì¼ÆøÌ壬ÆøÇòͨ¹ýµ¼Æø¹ÜÓëÍâ½ç¿ÕÆøÏàͨ£¬·ÖҺ©¶·AÖÐ×°ÓÐÇâÑõ»¯ÄÆÈÜÒº¡£·ÖҺ©¶·BÖÐ×°ÓÐÁíÒ»ÖÖÊÔ¼Á¡£

²½ÖèÒ»£º´ò¿ª·ÖҺ©¶·AµÄ»îÈû£¬Ê¹ÇâÑõ»¯ÄÆÈÜÒºÁ÷È뼯ÆøÆ¿ÖС£
ÏÖÏó£ºÆøÇòÖð½¥±ä´ó¡£
²½Öè¶þ£º´ò¿ª·ÖҺ©¶·BµÄ»îÈû£¬Ê¹       ÈÜÒºÁ÷È뼯ÆøÆ¿ÖС£
ÏÖÏ󣺠                            £¬²úÉúÕâÒ»ÏÖÏóµÄ»¯Ñ§·´Ó¦·½³ÌʽÊÇ                                 ¡£
½áÂÛ£º¶þÑõ»¯Ì¼ºÍÇâÑõ»¯ÄÆÈÜÒº¿ÉÒÔ·´Ó¦£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                               ¡£
¢Ç¶ÔÓÚÏÖÏó²»Ã÷ÏԵĻ¯Ñ§·´Ó¦£¬ÉÏÊöÁ½×éͬѧµÄʵÑéÊÇ·Ö±ð´Ó·´Ó¦ÎïºÍÉú³ÉÎïÁ½¸ö·½Ãæ½øÐеÄ̽¾¿ÑéÖ¤£¬ÆäËùÀûÓõÄÔ­ÀíÊDz»Í¬µÄ¡£
¢ÙµÚÒ»×éÊÇͨ¹ýʵÑéÖ¤Ã÷                  ÑéÖ¤»¯Ñ§·´Ó¦·¢ÉúÁË£»
¢ÚµÚ¶þ×éÊÇͨ¹ýʵÑéÖ¤Ã÷                  ÑéÖ¤»¯Ñ§·´Ó¦·¢ÉúÁË¡£
£¨8·Ö£©¹¤ÒµÉÕ¼î¾ßÓнϺõÄɱ¾úÏû¶¾×÷ÓÃÇÒÁ®¼ÛÒ׵㬵«¹¤ÒµÉÕ¼îÖг£º¬ÓÐÔÓÖÊ̼ËáÄÆ¡£Ä³¿ÆѧѧϰС×éͬѧΧÈƹ¤ÒµÉÕ¼îÑùÆ·´¿¶È²â¶¨ÎÊÌ⣬չ¿ªÁËÌÖÂÛÓë̽¾¿¡£
¡¾Ô­Àí˼·¡¿ÀûÓÃNa2CO3ÓëÏ¡H2SO4·´Ó¦²úÉúCO2£¬Í¨¹ýCO2 ÖÊÁ¿µÄ²â¶¨£¬È·¶¨ÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿£¬´Ó¶ø¼ÆËãÑùÆ·´¿¶È¡£
¡¾ÊµÑé·½°¸¡¿Ð¡¿Æͬѧ¸ù¾ÝÒÔÉÏ˼·£¬Éè¼ÆÁËÈçͼ¼×µÄʵÑé·½°¸£¨¹Ì¶¨×°ÖÃÊ¡ÂÔ£©¡£

£¨1£©AÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ___________________¡£
£¨2£©Å¨ÁòËáµÄ×÷ÓÃΪ______¡£
¡¾½»Á÷ÌÖÂÛ¡¿Ð¡Ã÷ÈÏΪͼ¼×ʵÑé·½°¸µÄÉè¼ÆÓÐȱÏÝ£¬Èô°´¸Ã·½°¸½øÐвⶨ»áµ¼ÖÂÄÑÒÔ±ÜÃâµÄÎó²î¡£ÄãÈÏΪÏÂÁÐÄÄЩÒòËػᵼÖÂÄÑÒÔ±ÜÃâµÄÎó²î ___________________£¨ÌîÐòºÅ£©¡£
¢Ù¼ÓÈëµÄÏ¡ÁòËáÁ¿²»×ã           ¢Ú×°ÖÃÄÚ¿ÕÆøÖеÄCO2ûÓÐÅųö
¢Û·´Ó¦²úÉúµÄCO2δ±»ÍêÈ«ÎüÊÕ   ¢Ü¸ÉÔï¹ÜÓë¿ÕÆøÖ±½ÓÏàͨ
¡¾·½°¸¸Ä½ø¡¿Îª¼õÉÙÎó²î£¬Ê¹CO2ÖÊÁ¿µÄ²â¶¨¸ü׼ȷ£¬¸ÃС×éͬѧ¸ù¾ÝÒÔÉÏÌÖÂÛ£¬¶Ôͼ¼×·½°¸½øÐиĽø£¬Éè¼ÆÁËÈçͼÒÒµÄʵÑé·½°¸£¨¹Ì¶¨×°ÖÃÊ¡ÂÔ£©¡£
ͼÒÒB×°ÖÃÖÐÑùÆ·ÔÚÓëÏ¡ÁòËᷴӦǰºÍÍ£Ö¹·´Ó¦ºó£¬¶¼ÒªÍ¨¹ýÁ¿µÄ¿ÕÆø£¬·´Ó¦Ç°Í¨¿ÕÆøʱa¡¢b¡¢cÈý¸öµ¯»É¼ÐµÄ¿ØÖÆ·½·¨ÊÇ___________________¡£
¡¾Êý¾Ý·ÖÎö¡¿Èô³·È¥Í¼ÒÒÖеÄC×°Öã¬Ôò²âµÃ¹¤ÒµÉÕ¼îµÄ´¿¶È½«___________________£¨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©¡£
¡¾ÍØÕ¹Ìá¸ß¡¿ÒÑÖªNa2CO3ÈÜÒºµÎ¼ÓÏ¡ÁòËá²¢²»¶ÏÕñµ´£¬ÏÈÉú³ÉNaHCO3£¬µ±Na2CO3È«²¿×ª»¯ÎªNaHCO3ºó£¬Éú³ÉµÄNaHCO3ÄܼÌÐøÓëÏ¡ÁòËá·´Ó¦Éú³ÉCO2¡£ÏÖÏòÑùÆ·ÖмÓÒ»¶¨Á¿µÄÏ¡ÁòËᣬ·´Ó¦ºó²úÉúÎÞÉ«ÆøÌå²¢µÃµ½XÈÜÒº¡£Çë·ÖÎöÍƶϷ´Ó¦ºóËùµÃXÈÜÒºµÄÈÜÖÊ£¬ÆäËùÓеĿÉÄÜ×é³ÉΪ___________________¡£
ijѧϰС×éÔÚÕûÀí»¯Ñ§ÊÔ¼Áʱ£¬·¢ÏÖһƿʢÓа×É«¹ÌÌåµÄÊÔ¼ÁÆ¿£¬±êÇ©ÆÆËð(Èçͼ)¡£

¡¾Ìá³öÎÊÌâ¡¿¸Ã°×É«¹ÌÌåµÄ³É·ÖÊÇʲô£¿
¡¾ËѼ¯×ÊÁÏ¡¿¢Ù¾­ÀÏʦ»ØÒ䣬¸ÃÊÔ¼ÁµÄËá¸ùÀë×Ó¿ÉÄÜÊÇCO32£­¡¢SO32£­¡¢SO42£­¡¢
NO3£­ÖеÄÒ»ÖÖ ¢ÚSO2ÊÇÒ»ÖÖÎÞÉ«Óд̼¤ÐÔÆøζµÄÆøÌ壬ÃܶȱȿÕÆø´ó£¬Ò×ÈÜÓÚË®£¬ÄÜʹ³ÎÇåµÄʯ»ÒË®±ä»ë×Ç£¬Ò²ÄÜʹƷºìÈÜÒºÍÊÉ«£¬¶øCO2²»ÄÜʹƷºìÈÜÒºÍÊÉ«¡£
¡¾²ÂÏë¼ÙÉè¡¿¸ÃÊÔ¼ÁÒ»¶¨²»ÊÇ       £¬¿ÉÄÜÊÇNa2CO3£¬Ò²¿ÉÄÜÊÇ       »ò       ¡£
¡¾ÊµÑé̽¾¿¡¿
ʵÑé²Ù×÷
ÏÖ Ïó
½á ÂÛ
È¡ÉÙÁ¿°×É«¹ÌÌå¼ÓÈëÊÊÁ¿ÑÎËá
²úÉúÆøÅÝ
¸Ã°×É«¹ÌÌå²»¿ÉÄÜÊÇ       
²úÉúµÄÆøÌåͨÈë³ÎÇåʯ»ÒË®
ʯ»ÒË®±ä»ë×Ç
¸Ã°×É«¹ÌÌå²»¿ÉÄÜÊÇ       
²úÉúµÄÆøÌåͨÈëÆ·ºìÈÜÒº
ÈÜÒºÍÊÉ«
 
¡¾»ñµÃ½áÂÛ¡¿¸Ã°×É«¹ÌÌåÊÇ       ¡£
¡¾½»Á÷·´Ë¼¡¿
(1)SO2ºÍCO2¾ùÊôÓڷǽðÊôÑõ»¯ÎijЩÐÔÖÊÏàËÆ¡£Çëд³öÏÂÁл¯Ñ§·´Ó¦·½³Ìʽ£º
SO2ͨÈë³ÎÇåʯ»ÒË®                                                £»
SO2ͨÈë×ÏɫʯÈïÊÔÒº£¬ÊÔÒº±äºìÉ«                                  ¡£
(2)ÑÇÁòËáÄÆÓëÑÎËá·´Ó¦ÄÜÉú³ÉSO2£¬ÊµÑéÊÒÖÐÊÕ¼¯SO2µÄ·½·¨Îª                             £¬
¼ìÑéSO2µÄÊÔ¼ÁΪ       ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø