ÌâÄ¿ÄÚÈÝ

ijÑо¿ÐÔѧϰС×é¶ÔijÕäÖé·Û½øÐÐÁËÈçÏÂ̽¾¿¡£
¡¾²éÔÄ×ÊÁÏ¡¿¢ÙÕäÖéµÄ»¯Ñ§³É·ÖÖ÷ÒªÊÇ£ºÌ¼Ëá¸Æ¼°ÉÙÁ¿Ì¼ËáþºÍ¿Ç½Çµ°°×(µ°°×ÖʵÄÒ»ÖÖ)£»
¢Ú¿Ç½Çµ°°×²»ÈÜÓÚË®£¬¼ÓÈëŨÏõËá¼ÓÈȺó»á±ä»ÆÉ«£»
¢Û¼ÙÕäÖé·ÛÆäʵ¾ÍÊÇ¡°±´¿Ç·Û¡±£¬Ö÷Òª³É·Ö¾ÍÊÇ̼Ëá¸Æ¡£
¡¾·ÖÎöÌÖÂÛ¡¿¢ÙÕæÕäÖéÖÐËùº¬¿Ç½Çµ°°×ÔÚÎïÖÊÀà±ðÉÏÊôÓÚ       £¨Ìî ¡°Óлú¡±»ò¡°ÎÞ»ú¡±£©»¯ºÏÎï¡£
¢Ú¼ÙÕäÖé·ÛÖеÄ̼Ëá¸Æº¬Á¿Òª±ÈÕæÕäÖé·Û´ó¡£
¡¾ÊµÑé̽¾¿¡¿Ñо¿ÐÔѧϰС×éÉè¼ÆÁËÈçÏÂÁ½¸ö·½°¸£º
·½°¸Ò» ¼ìÑéÕäÖé·ÛµÄÕæ¼Ù
È¡ÉÙÁ¿ÕäÖé·ÛÑùÆ·ÓÚÊÔ¹ÜÖУ¬                 £¬Èô¹Û²ìµ½        £¬Ôò¸ÃÕäÖé·ÛÊÇÕæÕäÖé·Û¡£
·½°¸¶þ ¼ìÑé¸ÃÕäÖé·ÛÖеÄ̼Ëá¸Æº¬Á¿
²½Öè¢ñ£ºÁ¬½ÓÒÇÆ÷×é³ÉÈçͼËùʾʵÑé×°Öá£Ä³Ñ§Éú¼ÐסC×ó²àµÄÏ𽺹ܣ¬ÔÚAÖÐ×°ÈëÉÙÁ¿Ë®²¢È¡ÏÂÉϲ¿Èû×Ó£¬´ò¿ª²£Á§»îÈû£¬AÖÐË®²»ÄÜÈ«²¿µÎÏ£¬ÄãÈÏΪ¸Ã×°ÖÃÊÇ·ñ©Æø£¿              ¡£

²½Öè¢ò£º×¼È·³ÆÈ¡6.000 gÕäÖé·ÛÑùÆ·×°ÈëÒÇÆ÷BÖУ¬ÔÚAÖÐ×°ÈëÏ¡ÑÎËá¡£
²½Öè¢ó£ºÏòBÖÐÕäÖé·ÛÑùÆ·ÖеμÓ×ãÁ¿µÄÏ¡ÑÎËá¡£ÔÚÒÇÆ÷B¡¢CÖпɹ۲쵽µÄÏÖÏóΪ     ¡¢         ¡£
²½Öè¢ô£ºÍêÈ«·´Ó¦ºóCÖеÄ×ÇÒº¾­      ¡¢       ¡¢¸ÉÔ³ÆµÃ°×É«¹ÌÌåµÄÖÊÁ¿Îª11.820g£¬ÔòÕäÖé·ÛÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýΪ100%¡£
¡¾ÊµÑ鷴˼¡¿»ñµÃ´Ë²â¶¨½á¹û£¬¿ÉÄܵÄÔ­ÒòÓР           ¡££¨ÌîÊý×ÖÐòºÅ£©
¢ÙÑùÆ·Öк¬ÓÐ̼Ëáþ   
¢ÚÑÎËáδµÎ¼Ó×ãÁ¿  
¢ÛCO2ÆøÁ÷ËÙ¶ÈÌ«¿ìµ¼ÖÂδ±»Ba(OH)2ÍêÈ«ÎüÊÕ 
¢Ü×°ÖÃBÖÐË®ÕôÆø¡¢HClµÈ½øÈë×°ÖÃCÖР 
¡¾ÍØÕ¹ÑÓÉì¡¿ÓÐͬѧÌá³öÔÚ·½°¸¶þÖв»ÐèҪװÖÃC£¬Ö»ÒªÓõç×ÓÌìƽ׼ȷ³ÆÁ¿×°ÖÃA¡¢B·´Ó¦Ç°ºóµÄÖÊÁ¿£¬¾Í¿ÉÒԵõ½ÕäÖé·ÛÑùÆ·ÖÐ̼Ëá¸ÆµÄº¬Á¿¡£ÄãÈÏΪÊÇ·ñ¿ÉÐР   £¬Çë˵Ã÷ÀíÓÉ          ¡£

¡¾·ÖÎöÌÖÂÛ¡¿ Óлú 
¡¾ÊµÑé̽¾¿¡¿¼ÓÈëŨÏõËá²¢¼ÓÈÈ  ±ä»ÆÉ«  ²»Â©Æø    BÖйÌÌåÈܽⲢ²úÉúÆøÅÝ£¬ CÖвúÉú³Áµí  ¹ýÂË Ï´µÓ  
¡¾ÊµÑ鷴˼¡¿¢Ù
¡¾ÍØÕ¹ÑÓÉì¡¿²»¿ÉÐР¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬×°ÖÃA¡¢B·´Ó¦Ç°ºóµÄÖÊÁ¿²î¾ÍÊÇ̼Ëá¸ÆÒÔ¼°Ì¼ËáþºÍÑÎËá·´Ó¦Éú³ÉµÄCO2µÄ×ÜÖÊÁ¿£¬¶øÒòΪ²»ÖªµÀ̼Ëá¸ÆºÍ̼ËáþµÄ×ÜÖÊÁ¿£¬ËùÒÔÎÞ·¨Çó³öÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿¼°º¬Á¿¡£

½âÎöÊÔÌâ·ÖÎö£º¡¾·ÖÎöÌÖÂÛ¡¿¿Ç½Çµ°°×ÊôÓÚµ°°×ÖÊ£¬ÔÚÎïÖÊÀà±ðÉÏÊôÓÚÓлúÎ·½°¸Ò»ÏòÕäÖéÖмÓÈëŨÏõËá²¢¼ÓÈÈÈç¹û±äΪ»ÆÉ«£¬ËµÃ÷Óпǽǵ°°×£¬ÎªÕæÕäÖ飻·½°¸¶þÈçͼËùʾ£¬¼ÐסC×ó²àµÄÏ𽺹ܷÖҺ©¶·ÖеÄË®²»ÄÜÍêÈ«µÎÏÂ˵Ã÷×°Öò»Â©Æø£¬ÆøÃÜÐÔÁ¼ºÃ£»²½Öè¢ó£º×°ÖÃBÖеķ´Ó¦ÎªÑÎËáºÍ̼Ëá¸Æ·¢Éú¸´·Ö½â·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢Ë®ºÍ¶þÑõ»¯Ì¼µÄ·´Ó¦£¬ÏÖÏóΪÓÐÆøÅÝð³ö£¬AÖÐÇâÑõ»¯±µºÍ¶þÑõ»¯Ì¼·´Ó¦Éú³É̼Ëá±µ³Áµí£¬ËùÒÔÓа×É«³ÁµíÉú³É£»²½Öè¢ô×ÇÒº¾­¹ý¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔïºóµÃµ½´¿¾»µÄ̼Ëá±µµÄÖÊÁ¿£¬¿ÉÒÔËã³ö¶þÑõ»¯Ì¼µÄÖÊÁ¿£¬½ø¶øͨ¹ý¶þÑõ»¯Ì¼¿ÉÒÔÇó³öÕäÖéÖÐ̼Ëá¸ÆµÄÖÊÁ¿£»¡¾ÊµÑ鷴˼¡¿¿ÉÄÜÊǺ¬ÓÐ̼Ëáþµ¼Öµģ¬µ¥Î»ÖÊÁ¿µÄ̼Ëáþ²úÉúµÄ¶þÑõ»¯Ì¼½Ï¶à£»¡¾ÍØÕ¹ÑÓÉì¡¿²»¿ÉÐУ¬ÒòΪ¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬×°ÖÃA¡¢B·´Ó¦Ç°ºóµÄÖÊÁ¿²î¾ÍÊÇ̼Ëá¸ÆÒÔ¼°Ì¼ËáþºÍÑÎËá·´Ó¦Éú³ÉµÄCO2µÄ×ÜÖÊÁ¿£¬¶øÒòΪ²»ÖªµÀ̼Ëá¸ÆºÍ̼ËáþµÄ×ÜÖÊÁ¿£¬ËùÒÔÎÞ·¨Çó³öÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿¼°º¬Á¿¡£
¿¼µã£ºÌ½¾¿ÕäÖé³É·Ö
µãÆÀ£ºÕâÊÇÒ»µÀ·Ç³£µäÐ͵Ä̽¾¿Ì⣬ÌâÄ¿¸øµÄ֪ʶµãûÓÐѧ¹ý£¬½ÏΪİÉú£¬µ«ÊÇÖص㿼²ìµÄ·´Ó¦µÄ˼Ï룬װÖõȣ¬ËùÒÔÕâÖÖÌâÄ¿²»Òªº¦Å£¬×ÐϸÉóÌâ¼´¿É¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2013?³¤ÇåÇø¶þÄ££©ÑÀ¸àÊÇÒ»ÖÖÈÕÓñØÐèÆ·£®Ä³Ñо¿ÐÔѧϰС×é¶ÔijһƷÅÆÑÀ¸àÖÐËùº¬Ä¦²Á¼ÁµÄ³É·Ö½øÐÐÁËÈçÏÂ̽¾¿£®
[²éÔÄ×ÊÁÏ]
£¨1£©ÑÀ¸à³£ÓÃÇâÑõ»¯ÂÁ¡¢Ì¼Ëá¸Æ¡¢¶þÑõ»¯¹èµÈÎïÖÊ×÷Ħ²Á¼Á£¬ÑÀ¸àÖÐÆäËü³É·ÖÓöµ½ÑÎËáʱÎÞÆøÌåÉú³É£»
£¨2£©ÇâÑõ»¯ÂÁÊÇÁ½ÐÔÇâÑõ»¯ÎÔÚ³£ÎÂÏÂËü¼ÈÄÜÓëÇ¿ËᣬÓÖÄÜÓëÇ¿¼î·´Ó¦£®ÈçÓëÇâÑõ»¯ÄÆ¿É·¢ÉúÈçÏ·´Ó¦£ºAl£¨OH£©3+NaOH=NaAlO2+2H2O£®£¨NaAlO2ÈÜÓÚË®£©
[Ìá³öÎÊÌâ]¸ÃÆ·ÅÆÑÀ¸àµÄËá¼îÐÔÈçºÎ£¿ÆäÖк¬ÓÐʲôĦ²Á¼Á£¿
[ʵÑéÓë²ÂÏë]
£¨1£©È¡ÉÙÁ¿ÑÀ¸à¸àÌåÓÚСÉÕ±­ÖУ¬¼ÓÈë10ºÁÉýÕôÁóË®£¬³ä·Ö½Á°è£¬¾²ÖÃÒ»¶Îʱ¼ä£¬·ÖÀëÉϲãÇåÒººÍ³Áµí£¬´ýÓã»
£¨2£©ÓÃpHÊÔÖ½²â¶¨ËùµÃÈÜÒºµÄpH´óÓÚ7£¬ÕýÈ·µÄ²Ù×÷·½·¨ÊÇ
ÓøÉÔï¡¢½à¾»µÄ²£Á§°ôպȡÈÜÒº£¬µÎÔÚpHÊÔÖ½ÉÏ£¬ÔÙÓë±ê×¼±ÈÉ«¿¨¶ÔÕÕ£¬¿ÉÖªÈÜÒºµÄpH´óÓÚ7
ÓøÉÔï¡¢½à¾»µÄ²£Á§°ôպȡÈÜÒº£¬µÎÔÚpHÊÔÖ½ÉÏ£¬ÔÙÓë±ê×¼±ÈÉ«¿¨¶ÔÕÕ£¬¿ÉÖªÈÜÒºµÄpH´óÓÚ7
£®
£¨3£©È¡ÉÙÁ¿³ÁµíÎï¼ÓÈë¹ýÁ¿µÄÏ¡ÑÎËᣬ³ÁµíÎïÈ«²¿ÈܽⲢÓдóÁ¿ÆøÅݲúÉú£¬Í¬Ê±µÃµ½³ÎÇåÈÜÒºA£¬Ôò¸ÃÆ·ÅÆÑÀ¸àÖÐÒ»¶¨º¬ÓÐ̼Ëá¸Æ£¬Ò»¶¨²»º¬ÓÐ
¶þÑõ»¯¹è
¶þÑõ»¯¹è
£®
£¨4£©½øÐвÂÏ룺Ħ²Á¼Á³É·Ö¿ÉÄÜÊÇ
a£®Ö»º¬Ì¼Ëá¸Æ    b£®
º¬ÓÐ̼Ëá¸ÆºÍÇâÑõ»¯ÂÁ
º¬ÓÐ̼Ëá¸ÆºÍÇâÑõ»¯ÂÁ

[Éè¼ÆʵÑé]
ʵÑé²½Öè ʵÑéÏÖÏó ½âÊÍÓë½áÂÛ
È¡³ÎÇåÈÜÒºAÖðµÎµÎÈëÒ»¶¨Á¿ÇâÑõ»¯ÄÆÈÜÒº ¿ªÊ¼ÎÞÃ÷ÏÔÏÖÏ󣬺ó²úÉú°×É«³Áµí Ô­ÒòÊÇ
HCl+NaOH=NaCl+H2O
HCl+NaOH=NaCl+H2O
£¬
AlCl3+3NaOH=Al£¨OH£©3¡ý+3NaCl
AlCl3+3NaOH=Al£¨OH£©3¡ý+3NaCl
£®
£¨Óû¯Ñ§·½³Ìʽ±íʾ£©
¼ÌÐøµÎÈëÇâÑõ»¯ÄÆÈÜÒºÖ±ÖÁ¹ýÁ¿
³ÁµíÈܽâ
³ÁµíÈܽâ
Ħ²Á¼ÁÖл¹º¬ÓÐ
ÇâÑõ»¯ÂÁ
ÇâÑõ»¯ÂÁ
[ʵÑé½áÂÛ]¸ÃÆ·ÅÆÑÀ¸àËùº¬Ä¦²Á¼ÁµÄ³É·ÖΪ
̼Ëá¸ÆºÍÇâÑõ»¯ÂÁ
̼Ëá¸ÆºÍÇâÑõ»¯ÂÁ
£®
£¨2013?ÒËÐËÊÐһģ£©ÑÀ¸àÊǺÍÑÀË¢Ò»ÆðÓÃÓÚÇå½àÑÀ³Ý£¬±£»¤¿ÚÇ»ÎÀÉú£¬¶ÔÈËÌ尲ȫµÄÒ»ÖÖÈÕÓñØÐèÆ·£®Ä³Ñо¿ÐÔѧϰС×é¶ÔijһƷÅÆÑÀ¸àÖÐËùº¬Ä¦²Á¼ÁµÄ³É·Ö¼°º¬Á¿½øÐÐÁËÈçÏÂ̽¾¿£®

¡¾²éÔÄ×ÊÁÏ¡¿
£¨1£©ÑÀ¸à³£ÓÃÇâÑõ»¯ÂÁ¡¢Ì¼Ëá¸Æ¡¢¶þÑõ»¯¹èµÈÎïÖÊ×÷Ħ²Á¼Á£¬ÑÀ¸àÖÐÆäËü³É·ÖÓöµ½ÑÎËáʱÎÞÆøÌåÉú³É£»
£¨2£©ÇâÑõ»¯ÂÁÊÇÁ½ÐÔÇâÑõ»¯ÎÔÚ³£ÎÂÏÂËü¼ÈÄÜÓëÇ¿ËᣬÓÖÄÜÓëÇ¿¼î·´Ó¦£®ÈçÓëÇâÑõ»¯ÄÆ¿É·¢ÉúÈçÏ·´Ó¦£ºAl£¨OH£©3+NaOH=NaAlO2+2H2O£®
¢ñ£®¶¨ÐÔ̽¾¿
¡¾Ìá³öÎÊÌâ¡¿¸ÃÆ·ÅÆÑÀ¸àÖк¬ÓÐʲôĦ²Á¼Á£¿
¡¾ÊµÑéÓë²ÂÏë¡¿
£¨1£©È¡ÉÙÁ¿ÑÀ¸à¸àÌ壬¼ÓÈë¹ýÁ¿µÄÏ¡ÑÎËᣬÑÀ¸àÈ«²¿ÈܽⲢÓдóÁ¿ÆøÅݲúÉú£¬Í¬Ê±µÃµ½³ÎÇåÈÜÒºA£¬Ôò¸ÃÆ·ÅÆÑÀ¸àÖÐÒ»¶¨º¬ÓÐ̼Ëá¸Æ£¬Ò»¶¨²»º¬ÓÐ
SiO2
SiO2
£®
£¨2£©½øÐвÂÏ룺Ħ²Á¼Á¿ÉÄÜ
a£®Ö»º¬Ì¼Ëá¸Æ    b£®
̼Ëá¸ÆºÍÇâÑõ»¯ÂÁ
̼Ëá¸ÆºÍÇâÑõ»¯ÂÁ

¡¾Éè¼ÆʵÑé¡¿
ʵÑé²½Öè ʵÑéÏÖÏó ½âÊÍÓë½áÂÛ
È¡³ÎÇåÈÜÒºAÖðµÎµÎÈëÒ»¶¨Á¿ÇâÑõ»¯ÄÆÈÜÒº ¿ªÊ¼ÎÞÃ÷ÏÔÏÖÏ󣬺ó²úÉú°×É«³Áµí Ô­ÒòÊÇ
NaOH+HCl¨TNaCl+H2O
NaOH+HCl¨TNaCl+H2O
£¬
AlCl3+3NaOH¨TAl£¨OH£©3¡ý+3NaCl
AlCl3+3NaOH¨TAl£¨OH£©3¡ý+3NaCl
£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£®
¼ÌÐøµÎÈëÇâÑõ»¯ÄÆÈÜÒºÖ±ÖÁ¹ýÁ¿
³ÁµíÈܽâ
³ÁµíÈܽâ
Ħ²Á¼ÁÖл¹º¬ÓÐ
ÇâÑõ»¯ÂÁ
ÇâÑõ»¯ÂÁ
¢ò£®¶¨Á¿Ì½¾¿
¡¾Ìá³öÎÊÌâ¡¿ÑÀ¸àÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýÊǶàÉÙÄØ£¿
¡¾Éè¼ÆʵÑé¡¿
СÃ÷ͬѧÓÃͼ1ËùʾװÖ㬽«Ò»¶¨Á¿µÄÑÀ¸àÓë¹ýÁ¿µÄÑÎËá·´Ó¦£¬²âÁ¿Ïà¹ØÊý¾Ý£¬ÍÆËã³ö¶þÑõ»¯Ì¼µÄÖÊÁ¿£¬È»ºó¸ù¾Ý»¯Ñ§·½³ÌʽÇó³ö̼Ëá¸ÆµÄÖÊÁ¿£¬ÔÙ¼ÆËã³ö̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£®
¡¾½»Á÷ÓëÌÖÂÛ¡¿
£¨1£©Ð¡Ç¿Í¬Ñ§Ìá³öСÃ÷ͬѧÉè¼ÆµÄ̽¾¿·½°¸²»¹»ÑÏÃÜ£¬²â¶¨½á¹ûÆ«´ó£®ËûµÄÀíÓÉÊÇ
ÑÎËá»á»Ó·¢³öÂÈ»¯ÇâÆøÌå
ÑÎËá»á»Ó·¢³öÂÈ»¯ÇâÆøÌå
£®
£¨2£©Í¨¹ýÌÖÂ۸ĽøÁËʵÑé·½°¸½øÐÐÊÔÑé²¢²âµÃÊý¾ÝÈçͼ2£º
ÇëÄãͨ¹ýÉÏÊöÊý¾Ý¼ÆËãÑÀ¸àÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£¨ÇëÁгö¼ÆËã¹ý³Ì£©£®

(5·Ö)άÉúËØC(¼ò³ÆVc£¬ÓÖÃû¿¹»µÑªËá)£¬Ò×ÈÜÓÚË®£¬Ò×±»Ñõ»¯¡£ÈËÌåȱ·¦Vc¿ÉÄÜÒý·¢¶àÖÖ¼²²¡¡£Ë®¹ûºÍÊß²ËÖк¬ÓзḻµÄVc¡£Ä³Ñо¿ÐÔѧϰС×é¶ÔËü̽¾¿ÈçÏ£º

̽¾¿Ò»£º²â¶¨ÐÂÂòµÄÒûÁÏÖÐVcµÄº¬Á¿¡£

¡¾²éÔÄ×ÊÁÏ¡¿VcÄܺ͸ßÃÌËá¼Ø·´Ó¦£¬Ê¹×ÏÉ«µÄ¸ßÃÌËá¼ØÈÜÒºÍÊÉ«¡£

¡¾Éè¼Æ·½°¸¡¿·Ö±ðÏòÊ¢ÓÐlmLµÈŨ¶È¸ßÃÌËá¼ØÏ¡ÈÜÒºµÄËÄÖ»ÊÔ¹ÜÖÐÖðµÎµÎ¼ÓÐÂÂòµÄ¹ûζÒûÁÏ¡¢Æ»¹ûÖ­¡¢ÀæÖ­ºÍÐÂÅäÖƵÄ0.04£¥µÄVcÈÜÒº£¬±ßµÎ±ßÕñµ´£¬Ö±ÖÁ¸ßÃÌËá¼ØÈÜÒºÍÊÉ«¡£

¡¾ÊµÑéÊý¾Ý¡¿

¡¾ÊµÑé½áÂÛ¡¿·ÖÎöÊý¾Ý¿ÉÖª£¬ÐÂÂòµÄÒûÁÏÖÐVcº¬Á¿×î¸ßµÄÊÇ           £¬º¬Á¿Îª      

      (¸÷ÒºÌåÃܶÈÉϵIJî±ðºöÂÔ²»¼Æ)¡£

̽¾¿¶þ£ºÊ߲˷ÅÖÃʱ¼äµÄ³¤¶Ì¶ÔÆäVcº¬Á¿ÊÇ·ñÓÐÓ°Ïì¡£

¡¾Éè¼Æ·½°¸¡¿ÇëÄãÓÃÐÂÏʵĻƹϡ¢·ÅÖÃÒ»ÖܵĻƹϡ¢¸ßÃÌËá¼ØÏ¡ÈÜÒººÍ±ØÒªµÄÒÇÆ÷Éè¼ÆʵÑé·½°¸£º                                                                    ¡£

¡¾ÊµÑé½áÂÛ¡¿°´ÉÏÊö·½°¸ÊµÑ飬¸ù¾Ý                                       ÕâһʵÑé½á¹û£¬·ÖÎöµÃ³öÊ߲˷ÅÖÃʱ¼äµÄ³¤¶Ì¶ÔÆäVcµÄº¬Á¿ÓÐÓ°Ïì¡£

¡¾ÊµÑ鷴˼¡¿¶Ô±ÈʵÑéÐèÒª¿ØÖƱäÁ¿¡£ÔÚ×ö̽¾¿¶þʱ£¬ÏÂÁÐÇé¿öÓ°Ïìµ½²â¶¨½á¹ûµÄÊÇ       ¡£

A£®Á¿È¡µÄ¸ßÃÌËá¼ØÈÜÒºµÄÌå»ý²»Í¬ 

B£®ÐÂÏʻƹÏÖ­ÊÇÆäËû°à¼¶ÓÃʣϵģ¬¶ø·ÅÖÃÒ»ÖܵĻƹÏÖ­Êǵ±Ê±Õ¥µÄ

C£®Ã»ÓÐÓÃͬһ¹æ¸ñ½ºÍ·µÎ¹ÜµÎ¼Ó

 

άÉúËØCÓÖÃû¿¹»µÑªËᣬÒ×ÈÜÓÚË®£¬Ò×±»Ñõ»¯£¬ÄÜÓëµâ·´Ó¦£®ÈËÌåȱ·¦Î¬ÉúËØC¿ÉÄÜÒý·¢¶àÖÖ¼²²¡£®Ä³Ñо¿ÐÔѧϰС×é¶ÔËüÑо¿ÈçÏ£º
£¨1£©²ÂÏ룺άÉúËØC¿ÉÄܾßÓÐËáÐÔ£¿
£¨2£©ÊµÑé·½°¸£º
ÌṩÊÔ¼Á£ºÎ¬ÉúËØCƬ¡¢ÕôÁóË®¡¢×ÏɫʯÈïÊÔÒº¡¢ÎÞÉ«·Ó̪ÊÔÒº¡¢Ï¡ÑÎËá¡¢ÇâÑõ»¯ÄÆÈÜÒº¡¢ÂÈ»¯±µÈÜÒº¡¢pHÊÔÖ½£®
¸ù¾ÝÒÔÉÏÊÔ¼Á£¬ÇëÄã°ïÖúËûÃÇÉè¼Æ³öÒ»ÖÖʵÑé·½°¸£¬²¢Ð´³öʵÑéÏÖÏ󣺣¨Éè¼Æ³öÁ½ÖÖ·½°¸½±Àø4·Ö£©

ʵÑéÄÚÈÝʵÑéÏÖÏó
·½°¸1£º____________
·½°¸2£º____________
£¨3£©½áÂÛ£ºÎ¬ÉúËØC¾ßÓÐËáÐÔ£®¸ù¾ÝάÉúËØCµÄÐÔÖÊ£¬ÅжÏÏÂÁÐÎïÖÊÖÐÄÜÓëάÉúËØC·´Ó¦µÄÊÇ£¨______ £©
A¡¢½ðÊôþ        B¡¢ÂÈ»¯¼Ø        C¡¢ÇâÑõ»¯ÄÆ        D¡¢ÁòËáÍ­
£¨4£©Ä³Í¬Ñ§ÁªÏëµ½Î÷ºìÊÁµÈÊ߲ˡ¢Ë®¹ûÖк¬ÓзḻµÄάÉúËØC£¬·ÅÖÃʱ¼ä³¤¶ÌÊÇ·ñ¶ÔάÉúËØCµÄº¬Á¿²úÉúÓ°Ï죮ËûÉè¼ÆÁËÈçÏÂʵÑé·½°¸£º
¢ñ°ÑÐÂÏÊÎ÷ºìÊÁºÍ·ÅÖÃÒ»ÖܵÄÎ÷ºìÊÁ·Ö±ðµ·Ë飬ÓÃÉ´²¼½«Ö­Òº¼·ÈëÁ½¸öÉÕ±­ÖУ»
¢òÈ¡Á½Ö§Ê¢ÓÐ2mlÀ¶É«µâµÄµí·ÛÈÜÒºµÄÊԹܣ¬·Ö±ðµÎ¼ÓÉÏÊöÁ½ÖÖÖ­Òº£¬±ß¼Ó±ßÕñµ´£¬Ö±µ½À¶É«¸ÕºÃÏûʧ£¬¼Ç¼µÎÊýÈçÏ£º
  Ö­Òº  ÐÂÏÊÎ÷ºìÊÁµÄÖ­Òº    ·ÅÖÃÒ»ÖܵÄÎ÷ºìÊÁµÄÖ­Òº
  µÎÊý    12    20
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙÔÚÉÏÊöÁ½ÖÖÎ÷ºìÊÁÖУ¬ÄãÈÏΪάÉúËØCº¬Á¿¸ßµÄÊÇ______£®
¢ÚÄã´ÓÖеõ½µÄÆôʾÊÇ______£®
£¨2005?Ϋ·»£©Î¬ÉúËØCÓÖÃû¿¹»µÑªËᣬÒ×ÈÜÓÚË®£¬Ò×±»Ñõ»¯£¬ÄÜÓëµâ·´Ó¦£®ÈËÌåȱ·¦Î¬ÉúËØC¿ÉÄÜÒý·¢¶àÖÖ¼²²¡£®Ä³Ñо¿ÐÔѧϰС×é¶ÔËüÑо¿ÈçÏ£º
£¨1£©²ÂÏ룺άÉúËØC¿ÉÄܾßÓÐËáÐÔ£¿
£¨2£©ÊµÑé·½°¸£º
ÌṩÊÔ¼Á£ºÎ¬ÉúËØCƬ¡¢ÕôÁóË®¡¢×ÏɫʯÈïÊÔÒº¡¢ÎÞÉ«·Ó̪ÊÔÒº¡¢Ï¡ÑÎËá¡¢ÇâÑõ»¯ÄÆÈÜÒº¡¢ÂÈ»¯±µÈÜÒº¡¢pHÊÔÖ½£®
¸ù¾ÝÒÔÉÏÊÔ¼Á£¬ÇëÄã°ïÖúËûÃÇÉè¼Æ³öÒ»ÖÖʵÑé·½°¸£¬²¢Ð´³öʵÑéÏÖÏ󣺣¨Éè¼Æ³öÁ½ÖÖ·½°¸½±Àø4·Ö£©

ʵÑéÄÚÈÝʵÑéÏÖÏó
·½°¸1£º____________
·½°¸2£º____________
£¨3£©½áÂÛ£ºÎ¬ÉúËØC¾ßÓÐËáÐÔ£®¸ù¾ÝάÉúËØCµÄÐÔÖÊ£¬ÅжÏÏÂÁÐÎïÖÊÖÐÄÜÓëάÉúËØC·´Ó¦µÄÊÇ£¨______ £©
A¡¢½ðÊôþ        B¡¢ÂÈ»¯¼Ø        C¡¢ÇâÑõ»¯ÄÆ        D¡¢ÁòËáÍ­
£¨4£©Ä³Í¬Ñ§ÁªÏëµ½Î÷ºìÊÁµÈÊ߲ˡ¢Ë®¹ûÖк¬ÓзḻµÄάÉúËØC£¬·ÅÖÃʱ¼ä³¤¶ÌÊÇ·ñ¶ÔάÉúËØCµÄº¬Á¿²úÉúÓ°Ï죮ËûÉè¼ÆÁËÈçÏÂʵÑé·½°¸£º
¢ñ°ÑÐÂÏÊÎ÷ºìÊÁºÍ·ÅÖÃÒ»ÖܵÄÎ÷ºìÊÁ·Ö±ðµ·Ë飬ÓÃÉ´²¼½«Ö­Òº¼·ÈëÁ½¸öÉÕ±­ÖУ»
¢òÈ¡Á½Ö§Ê¢ÓÐ2mlÀ¶É«µâµÄµí·ÛÈÜÒºµÄÊԹܣ¬·Ö±ðµÎ¼ÓÉÏÊöÁ½ÖÖÖ­Òº£¬±ß¼Ó±ßÕñµ´£¬Ö±µ½À¶É«¸ÕºÃÏûʧ£¬¼Ç¼µÎÊýÈçÏ£º
  Ö­Òº  ÐÂÏÊÎ÷ºìÊÁµÄÖ­Òº    ·ÅÖÃÒ»ÖܵÄÎ÷ºìÊÁµÄÖ­Òº
  µÎÊý    12    20
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙÔÚÉÏÊöÁ½ÖÖÎ÷ºìÊÁÖУ¬ÄãÈÏΪάÉúËØCº¬Á¿¸ßµÄÊÇ______£®
¢ÚÄã´ÓÖеõ½µÄÆôʾÊÇ______£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø