题目内容
用递等式计算.
(1)772-317+128-283
(2)5.2+0.8×0.55
(3)
+
×
(4)
÷(
-
)×
.
(1)772-317+128-283
(2)5.2+0.8×0.55
(3)
| 3 |
| 5 |
| 1 |
| 2 |
| 4 |
| 5 |
(4)
| 2 |
| 3 |
| 4 |
| 5 |
| 2 |
| 3 |
| 5 |
| 3 |
考点:整数四则混合运算,分数的四则混合运算
专题:运算顺序及法则
分析:(1)利用加法交换律与减法的性质简算;
(2)(3)先算乘法,再算加法;
(4)先算减法,再算除法,最后算乘法.
(2)(3)先算乘法,再算加法;
(4)先算减法,再算除法,最后算乘法.
解答:
解:(1)772-317+128-283
=772+128-(317+283)
=900-600
=300;
(2)5.2+0.8×0.55
=5.2+0.44
=5.64;
(3)
+
×
=
+
=1;
(4)
÷(
-
)×
=
×
×
=
.
=772+128-(317+283)
=900-600
=300;
(2)5.2+0.8×0.55
=5.2+0.44
=5.64;
(3)
| 3 |
| 5 |
| 1 |
| 2 |
| 4 |
| 5 |
=
| 3 |
| 5 |
| 2 |
| 5 |
=1;
(4)
| 2 |
| 3 |
| 4 |
| 5 |
| 2 |
| 3 |
| 5 |
| 3 |
=
| 2 |
| 3 |
| 15 |
| 2 |
| 5 |
| 3 |
=
| 25 |
| 3 |
点评:混合运算的关键是抓住运算顺序,正确按运算顺序计算,适当利用运算定律简算.
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