题目内容
(1)0.32×0.25×0.125
(2)1.2÷3
×
(3)
×5
÷1.2-
(4)3
÷[(1
+
)×2
]
(5)[4-(5
-3
)]×
(6)
×[
+(
-0.25÷
)].
(2)1.2÷3
| 3 |
| 4 |
| 3 |
| 8 |
(3)
| 3 |
| 8 |
| 1 |
| 3 |
| 1 |
| 2 |
(4)3
| 1 |
| 5 |
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 7 |
(5)[4-(5
| 3 |
| 4 |
| 3 |
| 8 |
| 4 |
| 39 |
(6)
| 4 |
| 25 |
| 7 |
| 16 |
| 13 |
| 16 |
| 1 |
| 2 |
分析:(1)把0.32看作0.4×0.8,运用乘法交换律与结合律简算;
(2)把除法改为乘法,约分计算;
(3)把小数化为分数,先算乘除,再算减法;
(4)(5)先算小括号内的,再算中括号内的,最后算括号外的;
(6)把小数化为分数,先算小括号内的除法,然后去掉小括号,中括号内的通分计算,最后算括号外的.
(2)把除法改为乘法,约分计算;
(3)把小数化为分数,先算乘除,再算减法;
(4)(5)先算小括号内的,再算中括号内的,最后算括号外的;
(6)把小数化为分数,先算小括号内的除法,然后去掉小括号,中括号内的通分计算,最后算括号外的.
解答:解:(1)0.32×0.25×0.125
=0.4×0.8×0.25×0.125
=(0.4×0.25)×(0.125×0.8)
=0.1×0.1
=0.01;
(2)1.2÷3
×
=
×
×
=
;
(3)
×5
÷1.2-
=
×
÷
-
=
×
×
-
=
-
=
;
(4)3
÷[(1
+
)×2
]
=3
÷[
×
]
=
÷4
=
;
(5)[4-(5
-3
)]×
=[4-2
]×
=
×
=
;
(6)
×[
+(
-0.25÷
)]
=
×[
+(
-
÷
)]
=
×[
+(
-
)]
=
×[
+
-
]
=
×
=
.
=0.4×0.8×0.25×0.125
=(0.4×0.25)×(0.125×0.8)
=0.1×0.1
=0.01;
(2)1.2÷3
| 3 |
| 4 |
| 3 |
| 8 |
=
| 7 |
| 5 |
| 4 |
| 15 |
| 3 |
| 8 |
=
| 7 |
| 50 |
(3)
| 3 |
| 8 |
| 1 |
| 3 |
| 1 |
| 2 |
=
| 3 |
| 8 |
| 16 |
| 3 |
| 6 |
| 5 |
| 1 |
| 2 |
=
| 3 |
| 8 |
| 16 |
| 3 |
| 5 |
| 6 |
| 1 |
| 2 |
=
| 5 |
| 3 |
| 1 |
| 2 |
=
| 7 |
| 6 |
(4)3
| 1 |
| 5 |
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 7 |
=3
| 1 |
| 5 |
| 28 |
| 15 |
| 15 |
| 7 |
=
| 16 |
| 5 |
=
| 4 |
| 5 |
(5)[4-(5
| 3 |
| 4 |
| 3 |
| 8 |
| 4 |
| 39 |
=[4-2
| 3 |
| 8 |
| 4 |
| 39 |
=
| 13 |
| 8 |
| 4 |
| 39 |
=
| 1 |
| 6 |
(6)
| 4 |
| 25 |
| 7 |
| 16 |
| 13 |
| 16 |
| 1 |
| 2 |
=
| 4 |
| 25 |
| 7 |
| 16 |
| 13 |
| 16 |
| 1 |
| 4 |
| 1 |
| 2 |
=
| 4 |
| 25 |
| 7 |
| 16 |
| 13 |
| 16 |
| 1 |
| 2 |
=
| 4 |
| 25 |
| 7 |
| 16 |
| 13 |
| 16 |
| 1 |
| 2 |
=
| 4 |
| 25 |
| 3 |
| 4 |
=
| 3 |
| 25 |
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
练习册系列答案
相关题目