题目内容
根据运算定律填空.
(1)
×
×
=
×
×
(2)
×
×9=
×(
×
(3)(14+
)×
=
+
×
.
(1)
| 2 |
| 3 |
| 11 |
| 17 |
| 3 |
| 4 |
| 2 |
| 3 |
| 3 |
| 4 |
| 3 |
| 4 |
| 11 |
| 17 |
| 11 |
| 17 |
(2)
| 3 |
| 20 |
| 7 |
| 9 |
| 3 |
| 20 |
| 7 |
| 9 |
| 7 |
| 9 |
9
9
)(3)(14+
| 7 |
| 2 |
| 1 |
| 14 |
14
14
×| 1 |
| 14 |
| 1 |
| 14 |
| 7 |
| 2 |
| 7 |
| 2 |
| 1 |
| 14 |
| 1 |
| 14 |
分析:(1)根据乘法交换律进行简算;
(2)根据乘法结合律进行简算;
(3)根据乘法分配律进行简算.
(2)根据乘法结合律进行简算;
(3)根据乘法分配律进行简算.
解答:解:
(1)
×
×
,
=
×
×
,
=
×
,
=
;
(2)
×
×9,
=
×(
×9),
=
×7,
=
;
(3)(14+
)×
,
=14×
+
×
,
=1+
,
=1
.
故答案为:
,
,
,9,14,
,
,
.
(1)
| 2 |
| 3 |
| 11 |
| 17 |
| 3 |
| 4 |
=
| 2 |
| 3 |
| 3 |
| 4 |
| 11 |
| 17 |
=
| 1 |
| 2 |
| 11 |
| 17 |
=
| 11 |
| 34 |
(2)
| 3 |
| 20 |
| 7 |
| 9 |
=
| 3 |
| 20 |
| 7 |
| 9 |
=
| 3 |
| 20 |
=
| 21 |
| 20 |
(3)(14+
| 7 |
| 2 |
| 1 |
| 14 |
=14×
| 1 |
| 14 |
| 7 |
| 2 |
| 1 |
| 14 |
=1+
| 1 |
| 4 |
=1
| 1 |
| 4 |
故答案为:
| 3 |
| 4 |
| 11 |
| 17 |
| 7 |
| 9 |
| 1 |
| 14 |
| 7 |
| 2 |
| 1 |
| 14 |
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
练习册系列答案
相关题目