题目内容
1+
+…+
+
= .
| 1 |
| 2 |
| 1 |
| 8 |
| 1 |
| 9 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:根据数据特点,可以分组计算,原式变为1+(
+
+
)+(
+
+
)+
,通分计算即可.
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 9 |
| 1 |
| 7 |
解答:
解:1+
+…+
+
=1+(
+
+
)+(
+
+
)+
=1+
+
+
=1+
+
+
=2
故答案为:2
.
| 1 |
| 2 |
| 1 |
| 8 |
| 1 |
| 9 |
=1+(
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 9 |
| 1 |
| 7 |
=1+
| 21 |
| 24 |
| 11 |
| 18 |
| 1 |
| 7 |
=1+
| 442 |
| 504 |
| 308 |
| 504 |
| 72 |
| 504 |
=2
| 53 |
| 84 |
故答案为:2
| 53 |
| 84 |
点评:解答此题,应注意合理分组,进行通分计算.
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