题目内容
解比例.
| 2.1:14=13.5:x |
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| x:3.5=2:14 | 12:x=2.4:1.6 | x:
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分析:先根据比例基本性质,两内项之积等于两外项之积,化简方程,再依据等式的性质,求解.
解答:解:(1)2.1:14=13.5:x,
2.1x=14×13.5,
2.1x÷2.1=189÷2.1,
x=90;
(2)
:x=
:
,
:x=
:
,
x=
×
,
x÷
=
÷
,
x=
;
(3)
:x=3:4,
3x=
×4,
3x÷3=5÷3,
x=
;
(4)x:3.5=2:14,
14x=3.5×2,
14x÷14=7÷14,
x=
;
(5)12:x=2.4:1.6,
2.4x=12×1.6,
2.4x÷2.4=19.2÷2.4,
x=8;
(6)x:
=15:
,
x=
×15,
x÷
=
÷
,
x=9;
(7)
=
,
4.5X=9×0.8,
4.5X÷4.5=7.2÷4.5,
X=1.6;
(8)
:
=x:10,
x=10×
,
x÷
=
÷
,
x=
;
(9)
=
,
5X=3.5×1.5,
5X÷5=5.25÷5,
X=1.05.
2.1x=14×13.5,
2.1x÷2.1=189÷2.1,
x=90;
(2)
| 1 |
| 16 |
| 3 |
| 8 |
| 1 |
| 6 |
| 1 |
| 16 |
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 8 |
| 1 |
| 16 |
| 1 |
| 6 |
| 3 |
| 8 |
| 3 |
| 8 |
| 1 |
| 96 |
| 3 |
| 8 |
x=
| 1 |
| 36 |
(3)
| 5 |
| 4 |
3x=
| 5 |
| 4 |
3x÷3=5÷3,
x=
| 5 |
| 3 |
(4)x:3.5=2:14,
14x=3.5×2,
14x÷14=7÷14,
x=
| 1 |
| 2 |
(5)12:x=2.4:1.6,
2.4x=12×1.6,
2.4x÷2.4=19.2÷2.4,
x=8;
(6)x:
| 1 |
| 2 |
| 5 |
| 6 |
| 5 |
| 6 |
| 1 |
| 2 |
| 5 |
| 6 |
| 5 |
| 6 |
| 15 |
| 2 |
| 5 |
| 6 |
x=9;
(7)
| X |
| 9 |
| 0.8 |
| 4.5 |
4.5X=9×0.8,
4.5X÷4.5=7.2÷4.5,
X=1.6;
(8)
| 1 |
| 15 |
| 15 |
| 40 |
| 15 |
| 40 |
| 1 |
| 15 |
| 15 |
| 40 |
| 15 |
| 40 |
| 2 |
| 3 |
| 15 |
| 40 |
x=
| 16 |
| 9 |
(9)
| 3.5 |
| X |
| 5 |
| 1.5 |
5X=3.5×1.5,
5X÷5=5.25÷5,
X=1.05.
点评:本题主要考查学生运用等式的性质,以及比例基本性质解方程的能力,注意等号对齐.
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