题目内容
| 解方程 x÷15%=
|
0.36×5-
|
91.4-5x+24=96
|
分析:(1)根据等式的性质,在方程两边同时乘0.15求解,
(2)先化简,再根据等式的性质,在方程两边同时加
x,再减去
,再乘上
求解,
(3)先化简,再根据等式的性质,在方程两边同时加5x,再减去96
,再除以5求解.
(2)先化简,再根据等式的性质,在方程两边同时加
| 3 |
| 4 |
| 3 |
| 5 |
| 4 |
| 3 |
(3)先化简,再根据等式的性质,在方程两边同时加5x,再减去96
| 1 |
| 2 |
解答:解:(1)x÷15%=
,
x÷0.15×0.15=
×0.15,
x=
;
(2)0.36×5-
x=
,
1.8-
x=
,
1.8-
x+
x=
+
x,
1.8-
=
+
x-
,
×
=
x×
,
x=
;
(3)91.4-5x+24=96
,
115.4-5x=96
,
115.4-5x+5x=96
+5x,
115.4-96
=96
+5x-96
,
18.9÷5=5x÷5,
x=3.78.
| 25 |
| 27 |
x÷0.15×0.15=
| 25 |
| 27 |
x=
| 5 |
| 36 |
(2)0.36×5-
| 3 |
| 4 |
| 3 |
| 5 |
1.8-
| 3 |
| 4 |
| 3 |
| 5 |
1.8-
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 5 |
| 3 |
| 4 |
1.8-
| 3 |
| 5 |
| 3 |
| 5 |
| 3 |
| 4 |
| 3 |
| 5 |
| 6 |
| 5 |
| 4 |
| 3 |
| 3 |
| 4 |
| 4 |
| 3 |
x=
| 8 |
| 5 |
(3)91.4-5x+24=96
| 1 |
| 2 |
115.4-5x=96
| 1 |
| 2 |
115.4-5x+5x=96
| 1 |
| 2 |
115.4-96
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
18.9÷5=5x÷5,
x=3.78.
点评:本题主要考查了学生根据等式的性质解方程的能力,注意等号对齐.
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