题目内容
已知162×[(4
-□×700)÷1
]=81,那么□=______.(第12届初赛题)
| 1 |
| 7 |
| 2 |
| 7 |
设□为x,于是此题转化为解关于x的方程,
162×[(4
-700x)÷1
]=81,
162×[(4
-700x)÷1
]÷162=81÷162,
(4
-700x)÷1
=
,
(4
-700x)÷1
×1
=
×1
,
4
-700x=
,
700x+
=4
,
700x+
-
=4
-
,
700x=
,
700x÷700=
÷700,
x=
.
162×[(4
| 1 |
| 7 |
| 2 |
| 7 |
162×[(4
| 1 |
| 7 |
| 2 |
| 7 |
(4
| 1 |
| 7 |
| 2 |
| 7 |
| 1 |
| 2 |
(4
| 1 |
| 7 |
| 2 |
| 7 |
| 2 |
| 7 |
| 1 |
| 2 |
| 2 |
| 7 |
4
| 1 |
| 7 |
| 9 |
| 14 |
700x+
| 9 |
| 14 |
| 1 |
| 7 |
700x+
| 9 |
| 14 |
| 9 |
| 14 |
| 1 |
| 7 |
| 9 |
| 14 |
700x=
| 7 |
| 2 |
700x÷700=
| 7 |
| 2 |
x=
| 1 |
| 200 |
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