题目内容
递等式计算.
910÷35×59-1500; (3.24+1.02)÷2.13×0.25; (
+
)÷(
+
).
910÷35×59-1500; (3.24+1.02)÷2.13×0.25; (
| 3 |
| 4 |
| 1 |
| 6 |
| 5 |
| 36 |
| 2 |
| 9 |
考点:整数四则混合运算,分数的四则混合运算,小数四则混合运算
专题:运算顺序及法则
分析:(1)先算除法,再算乘法,最后算减法;
(2)先算小括号内的加法,再按照从左到右的顺序计算;
(3)先算小括号内的加法,再算除法.
(2)先算小括号内的加法,再按照从左到右的顺序计算;
(3)先算小括号内的加法,再算除法.
解答:
解:(1)910÷35×59-1500
=26×59-1500
=1534-1500
=34
(2)(3.24+1.02)÷2.13×0.25
=4.26÷2.13×0.25
=2×0.25
=0.5
(3)(
+
)÷(
+
)
=
÷
=
=26×59-1500
=1534-1500
=34
(2)(3.24+1.02)÷2.13×0.25
=4.26÷2.13×0.25
=2×0.25
=0.5
(3)(
| 3 |
| 4 |
| 1 |
| 6 |
| 5 |
| 36 |
| 2 |
| 9 |
=
| 11 |
| 12 |
| 13 |
| 36 |
=
| 33 |
| 13 |
点评:本题考查了简单的四则混合运算,计算时先理清楚运算顺序,根据运算顺序逐步求解即可.
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