题目内容
(2001?汉阳区)如果8
-1.5÷[1
×(□+1
)]=8
,那么□里应填
.
..
| a |
| 3 |
| b |
| 5 |
| c |
| 7 |
| 1 |
| 3 |
| 315-2(a-1)(5+b)(7+c) |
| 14(a-1)(5+b) |
| 315-2(a-1)(5+b)(7+c) |
| 14(a-1)(5+b) |
分析:将□里的数看作一个未知数,根据等式的性质解方程用含有a、b、c、的式子表示出□里的数即可.
解答:解:
8
-1.5÷[1
×(□+1
)]=8
,
-
÷[
×(□+
)]=
,
÷(
-
)=
×(□+
),
(
÷
)÷
=□+
,
□=
-
,
□=
.
故答案为:
.
8
| a |
| 3 |
| b |
| 5 |
| c |
| 7 |
| 1 |
| 3 |
| 24+a |
| 3 |
| 3 |
| 2 |
| 5+b |
| 5 |
| 7+c |
| 7 |
| 25 |
| 3 |
| 3 |
| 2 |
| 24+a |
| 3 |
| 25 |
| 3 |
| 5+b |
| 5 |
| 7+c |
| 7 |
(
| 3 |
| 2 |
| a-1 |
| 3 |
| 5+b |
| 5 |
| 7+c |
| 7 |
□=
| 45 |
| 2(a-1)(5+b) |
| 7+c |
| 7 |
□=
| 315-2(a-1)(5+b)(7+c) |
| 14(a-1)(5+b) |
故答案为:
| 315-2(a-1)(5+b)(7+c) |
| 14(a-1)(5+b) |
点评:此题主要考查用根据解方程的方法将所求数解答出来.注意计算时要细心.
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