题目内容
计算下面各题,能简算的要简算.
(
|
[1-(
|
999
| ||||||||||||||||||||
1998×
|
75÷4+25×25% | 32×1.25×2.5. |
考点:分数的四则混合运算
专题:运算顺序及法则
分析:(1)(4)(5)运用乘法分配律解答,
(2)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序就是即可解答,
(3)化带分数为整数加分数,再运用加法结合律即可解答,
(6)化32=4×8,再运用乘法结合律即可解答.
(2)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序就是即可解答,
(3)化带分数为整数加分数,再运用加法结合律即可解答,
(6)化32=4×8,再运用乘法结合律即可解答.
解答:
解:(1)(
-
)÷
=
×15-
×15
=10-9
=1;
(2)[1-(
+
)]×
=[1-
]×
=
×
=
;
(3)999
+99
+9
+
=999+99+9+
×4
=(999+1)+(99+1)+(9+1)
=1000+100+10
=1110;
(4)1998×
=1999×
-1×
=1998-
=1997
;
(5)75÷4+25×25%
=(75+25)×25%
=100×25%
=25;
(6)32×1.25×2.5
=(8×1.25)×(4×2.5)
=10×10
=100.
| 2 |
| 3 |
| 3 |
| 5 |
| 1 |
| 15 |
=
| 2 |
| 3 |
| 3 |
| 5 |
=10-9
=1;
(2)[1-(
| 1 |
| 8 |
| 3 |
| 4 |
| 1 |
| 7 |
=[1-
| 7 |
| 8 |
| 1 |
| 7 |
=
| 1 |
| 8 |
| 1 |
| 7 |
=
| 1 |
| 56 |
(3)999
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
=999+99+9+
| 3 |
| 4 |
=(999+1)+(99+1)+(9+1)
=1000+100+10
=1110;
(4)1998×
| 1998 |
| 1999 |
=1999×
| 1998 |
| 1999 |
| 1998 |
| 1999 |
=1998-
| 1998 |
| 1999 |
=1997
| 1 |
| 1999 |
(5)75÷4+25×25%
=(75+25)×25%
=100×25%
=25;
(6)32×1.25×2.5
=(8×1.25)×(4×2.5)
=10×10
=100.
点评:(1)正确运用简便方法解决问题,(2)依据四则运算计算方法正确进行计算,是本题考查知识点.
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