题目内容
| 5 |
| 9 |
| 9 |
| 5 |
| 2 |
| 15 |
| 1 |
| 4 |
| 2 |
| 15 |
| 3 |
| 4 |
(
| 1 |
| 3 |
| 1 |
| 4 |
(
| 1 |
| 2 |
| 1 |
| 3 |
分析:(1)运用乘法交换律解答,
(2)(3)(4)运用乘法分配律解答.
(2)(3)(4)运用乘法分配律解答.
解答:解:(1)
×7×
=
×
×7
=1×7
=7;
(2)
×
+
×
=
×(
+
)
=
×1
=
;
(3)(
-
)×24
=
×24-
×24
=8-6
=2;
(4)(
+
)×6
=
×6+
×6
=3+2
=5.
| 5 |
| 9 |
| 9 |
| 5 |
=
| 5 |
| 9 |
| 9 |
| 5 |
=1×7
=7;
(2)
| 2 |
| 15 |
| 1 |
| 4 |
| 2 |
| 15 |
| 3 |
| 4 |
=
| 2 |
| 15 |
| 1 |
| 4 |
| 3 |
| 4 |
=
| 2 |
| 15 |
=
| 2 |
| 15 |
(3)(
| 1 |
| 3 |
| 1 |
| 4 |
=
| 1 |
| 3 |
| 1 |
| 4 |
=8-6
=2;
(4)(
| 1 |
| 2 |
| 1 |
| 3 |
=
| 1 |
| 2 |
| 1 |
| 3 |
=3+2
=5.
点评:正确运用简便方法解决问题,是本题考查知识点.
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