题目内容
解下列方程.
x=
x=
×
(2-
)x=
x÷
=
×
.
| 2 |
| 3 |
| 5 |
| 6 |
| 2 |
| 7 |
| 1 |
| 2 |
| 3 |
| 14 |
(2-
| 3 |
| 4 |
| 4 |
| 5 |
x÷
| 1 |
| 2 |
| 4 |
| 9 |
| 1 |
| 4 |
分析:(1)等式的两边同时除以
即可;
(2)等式的两边同时除以
即可;
(3)先计算2-
=1
,然后等式的两边同时除以1
即可;
(4)等式的两边同时乘
即可.
| 2 |
| 3 |
(2)等式的两边同时除以
| 2 |
| 7 |
(3)先计算2-
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
(4)等式的两边同时乘
| 1 |
| 2 |
解答:解:
(1)
x=
,
x÷
=
÷
,
x=
;
(2)
x=
×
,
x=
,
x÷
=
÷
,
x=
;
(3)(2-
)x=
,
1
x=
,
1
x÷1
=
÷1
,
x=
;
(4)x÷
=
×
,
x÷
=
,
x÷
×
=
×
,
x=
.
(1)
| 2 |
| 3 |
| 5 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
| 5 |
| 6 |
| 2 |
| 3 |
x=
| 5 |
| 4 |
(2)
| 2 |
| 7 |
| 1 |
| 2 |
| 3 |
| 14 |
| 2 |
| 7 |
| 3 |
| 28 |
| 2 |
| 7 |
| 2 |
| 7 |
| 3 |
| 28 |
| 2 |
| 7 |
x=
| 3 |
| 8 |
(3)(2-
| 3 |
| 4 |
| 4 |
| 5 |
1
| 1 |
| 4 |
| 4 |
| 5 |
1
| 1 |
| 4 |
| 1 |
| 4 |
| 4 |
| 5 |
| 1 |
| 4 |
x=
| 16 |
| 25 |
(4)x÷
| 1 |
| 2 |
| 4 |
| 9 |
| 1 |
| 4 |
x÷
| 1 |
| 2 |
| 1 |
| 9 |
x÷
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 9 |
| 1 |
| 2 |
x=
| 1 |
| 18 |
点评:本题主要考查解方程,根据等式的性质进行解答即可.
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