题目内容
脱式计算
4.82-5.2÷0.8×0.6
0.8×[1÷(3.2-2.95)]
(
+
-
)÷
2013×(
-
)×2011.
4.82-5.2÷0.8×0.6
0.8×[1÷(3.2-2.95)]
(
| 3 |
| 4 |
| 5 |
| 8 |
| 1 |
| 2 |
| 1 |
| 16 |
2013×(
| 1 |
| 2011 |
| 1 |
| 2013 |
考点:小数四则混合运算,运算定律与简便运算,分数的四则混合运算
专题:运算顺序及法则,运算定律及简算
分析:(1)先算除法,再算乘法,最后算减法;
(2)先算小括号里的减法,再算中括号里的除法,最后算括号外的乘法;
(3)先算括号的加法,再算括号里的减法,最后算括号外的除法;
(4)先运用乘法交换律,交换(
-
)和2011的位置,然后把2013×2011看作一个整体,运用乘法分配律进行简算.
(2)先算小括号里的减法,再算中括号里的除法,最后算括号外的乘法;
(3)先算括号的加法,再算括号里的减法,最后算括号外的除法;
(4)先运用乘法交换律,交换(
| 1 |
| 2011 |
| 1 |
| 2013 |
解答:
解:(1)4.82-5.2÷0.8×0.6
=4.82-6.5×0.6
=4.82-3.9
=0.92;
(2)0.8×[1÷(3.2-2.95)]
=0.8×[1÷0.25]
=0.8×4
=3.2;
(3)(
+
-
)÷
=(
-
)÷
=
×16
=14;
(4)2013×(
-
)×2011
=2013×2011×(
-
)
=2013×2011×
-2013×2011×
=2013-2011
=2
=4.82-6.5×0.6
=4.82-3.9
=0.92;
(2)0.8×[1÷(3.2-2.95)]
=0.8×[1÷0.25]
=0.8×4
=3.2;
(3)(
| 3 |
| 4 |
| 5 |
| 8 |
| 1 |
| 2 |
| 1 |
| 16 |
=(
| 11 |
| 8 |
| 1 |
| 2 |
| 1 |
| 16 |
=
| 7 |
| 8 |
=14;
(4)2013×(
| 1 |
| 2011 |
| 1 |
| 2013 |
=2013×2011×(
| 1 |
| 2011 |
| 1 |
| 2013 |
=2013×2011×
| 1 |
| 2011 |
| 1 |
| 2013 |
=2013-2011
=2
点评:本题考查了简单的四则混合运算,关键是理清楚运算的顺序,根据运算顺序逐步求解即可.
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