题目内容
(1)3318+312÷24×205
(2)47.1×9.4-47.1÷2-+47.1
(3)[(1-0.5)×20]÷[(1+0.25)÷4]
(4)
-
+
(5)100-99+98-97+96-…+4-3+2-1
(6)
+
+
+ ------+
.
(2)47.1×9.4-47.1÷2-+47.1
(3)[(1-0.5)×20]÷[(1+0.25)÷4]
(4)
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
(5)100-99+98-97+96-…+4-3+2-1
(6)
| 1 |
| 5×6 |
| 1 |
| 6×7 |
| 1 |
| 7×8 |
| 1 |
| 49×50 |
分析:(1)题应注意运算顺序,先算除法和乘法,再算加法;
(2)题利用乘法分配律的逆运算进行简算;
(3)题先算小括号再算中括号;
(4)题利用加法交换律计算;
(5)题有一定规律,一共有50个1相加;
(6)题通过把分数写成两个分数相减的形式,通过抵消很快得出答案.
(2)题利用乘法分配律的逆运算进行简算;
(3)题先算小括号再算中括号;
(4)题利用加法交换律计算;
(5)题有一定规律,一共有50个1相加;
(6)题通过把分数写成两个分数相减的形式,通过抵消很快得出答案.
解答:解:(1)3318+312÷24×205,
=3318+13×205,
=3318+2665,
=5983;
(2)47.1×9.4-47.1÷2-47.1,
=47.1×(9.4-0.5-1),
=47.1×7.9,
=372.09;
(3)[(1-0.5)×20]÷[(1+0.25)÷4],
=10÷0.3125,
=32;
(4)
-
+
,
=(
+
)-
,
=
-
,
=
;
(5)100-99+98-97+96-…+4-3+2-1,
=(100-99)+(98-97)+(96-95)+…+(4-3)+(2-1),
=1×50,
=50;
(6)
+
+
+… +
,
=(
-
)+(
-
) +(
-
)+…+(
-
),
=
-
,
=
.
=3318+13×205,
=3318+2665,
=5983;
(2)47.1×9.4-47.1÷2-47.1,
=47.1×(9.4-0.5-1),
=47.1×7.9,
=372.09;
(3)[(1-0.5)×20]÷[(1+0.25)÷4],
=10÷0.3125,
=32;
(4)
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
=(
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 3 |
=
| 3 |
| 4 |
| 1 |
| 3 |
=
| 5 |
| 12 |
(5)100-99+98-97+96-…+4-3+2-1,
=(100-99)+(98-97)+(96-95)+…+(4-3)+(2-1),
=1×50,
=50;
(6)
| 1 |
| 5×6 |
| 1 |
| 6×7 |
| 1 |
| 7×8 |
| 1 |
| 49×50 |
=(
| 1 |
| 5 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 8 |
| 1 |
| 49 |
| 1 |
| 50 |
=
| 1 |
| 5 |
| 1 |
| 50 |
=
| 9 |
| 50 |
点评:此题考查了整数、小数、分数的四则运算,以及灵活运用所学知识进行巧算的能力.
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