题目内容
(6
+3
)÷(
×2+
).
| 2 |
| 7 |
| 5 |
| 13 |
| 2 |
| 7 |
| 4 |
| 13 |
分析:先算小括号里面的乘法,再把带分数化成假分数,然后再根据乘法分配律以及乘法结合律进行计算.
解答:解:(6
+3
)÷(
×2+
),
=(6
+3
)÷(
+
),
=(
+
)÷(
+
),
=11×(
+
)÷(
+
),
=11×[(
+
)÷(
+
)],
=11×1,
=11.
| 2 |
| 7 |
| 5 |
| 13 |
| 2 |
| 7 |
| 4 |
| 13 |
=(6
| 2 |
| 7 |
| 5 |
| 13 |
| 4 |
| 7 |
| 4 |
| 13 |
=(
| 44 |
| 7 |
| 44 |
| 13 |
| 4 |
| 7 |
| 4 |
| 13 |
=11×(
| 4 |
| 7 |
| 4 |
| 13 |
| 4 |
| 7 |
| 4 |
| 13 |
=11×[(
| 4 |
| 7 |
| 4 |
| 13 |
| 4 |
| 7 |
| 4 |
| 13 |
=11×1,
=11.
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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