题目内容
脱式计算,能简算的要简算
(1)7
+3.52+2
+5.48
(2)64
×
+
×34
(3)(
-
÷4×
)÷
(4)(111+999)÷[56×(
-
)].
(1)7
| 4 |
| 7 |
| 3 |
| 7 |
(2)64
| 3 |
| 4 |
| 1 |
| 11 |
| 1 |
| 11 |
| 1 |
| 4 |
(3)(
| 1 |
| 8 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
(4)(111+999)÷[56×(
| 3 |
| 7 |
| 3 |
| 8 |
考点:整数、分数、小数、百分数四则混合运算,运算定律与简便运算
专题:运算顺序及法则,运算定律及简算
分析:(1)运用加法交换律和结合律解答,
(2)(4)运用乘法分配律解答,
(3)按照先算括号里面的除法,再算括号里面的乘法,然后算括号里面的减法,最后算括号外面的除法顺序计算解答.
(2)(4)运用乘法分配律解答,
(3)按照先算括号里面的除法,再算括号里面的乘法,然后算括号里面的减法,最后算括号外面的除法顺序计算解答.
解答:
解:(1)7
+3.52+2
+5.48
=(7
+2
)+(3.52+5.48)
=10+9
=19;
(2)64
×
+
×34
=(64
+34
)×
=99×
=9;
(3)(
-
÷4×
)÷
=(
-
×
)÷
=(
-
)÷
=
÷
=
;
(4)(111+999)÷[56×(
-
)]
=1110÷[56×
-56×
]
=1110÷[24-21]
=1110÷3
=370.
| 4 |
| 7 |
| 3 |
| 7 |
=(7
| 4 |
| 7 |
| 3 |
| 7 |
=10+9
=19;
(2)64
| 3 |
| 4 |
| 1 |
| 11 |
| 1 |
| 11 |
| 1 |
| 4 |
=(64
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 11 |
=99×
| 1 |
| 11 |
=9;
(3)(
| 1 |
| 8 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
=(
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 4 |
| 1 |
| 2 |
=(
| 1 |
| 8 |
| 1 |
| 64 |
| 1 |
| 2 |
=
| 7 |
| 64 |
| 1 |
| 2 |
=
| 7 |
| 32 |
(4)(111+999)÷[56×(
| 3 |
| 7 |
| 3 |
| 8 |
=1110÷[56×
| 3 |
| 7 |
| 3 |
| 8 |
=1110÷[24-21]
=1110÷3
=370.
点评:本题主要考查学生依据四则运算计算方法正确进行计算,以及正确运用简便方法解决问题的能力.
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