题目内容

用递等式计算.
(1)[15.5-(1.5×
5
7
+1
1
2
×
2
7
)]÷14%
(2)[1
1
10
+2
7
20
÷(3
1
12
-1.125
)]×
9
23
-
1
6
(1)[15.5-(1.5×
5
7
+1
1
2
×
2
7
)]÷14%
=[
31
2
-(
3
2
×
5
7
+
3
2
×
2
7
)]÷
7
50

=[
31
2
-
5
7
+
2
7
)×
3
2
50
7

=[
31
2
-
3
2
50
7

=14×
50
7

=100;
(2)[1
1
10
+2
7
20
÷(3
1
12
-1.125
)]×
9
23
-
1
6

=[
11
10
+
47
20
÷(
37
12
-
9
8
)]×
9
23
-
1
6

=[
11
10
+
47
20
×
24
47
9
23
-
1
6

=[
11
10
+
12
10
9
23
-
1
6

=
23
10
×
9
23
-
1
6

=
9
10
-
1
6

=
11
15
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