题目内容
用递等式计算.
(1)[15.5-(1.5×
+1
×
)]÷14%
(2)[1
+2
÷(3
-1.125)]×
-
.
(1)[15.5-(1.5×
| 5 |
| 7 |
| 1 |
| 2 |
| 2 |
| 7 |
(2)[1
| 1 |
| 10 |
| 7 |
| 20 |
| 1 |
| 12 |
| 9 |
| 23 |
| 1 |
| 6 |
(1)[15.5-(1.5×
+1
×
)]÷14%
=[
-(
×
+
×
)]÷
,
=[
-(
+
)×
]×
,
=[
-
]×
,
=14×
,
=100;
(2)[1
+2
÷(3
-1.125)]×
-
=[
+
÷(
-
)]×
-
,
=[
+
×
]×
-
,
=[
+
]×
-
,
=
×
-
,
=
-
,
=
.
| 5 |
| 7 |
| 1 |
| 2 |
| 2 |
| 7 |
=[
| 31 |
| 2 |
| 3 |
| 2 |
| 5 |
| 7 |
| 3 |
| 2 |
| 2 |
| 7 |
| 7 |
| 50 |
=[
| 31 |
| 2 |
| 5 |
| 7 |
| 2 |
| 7 |
| 3 |
| 2 |
| 50 |
| 7 |
=[
| 31 |
| 2 |
| 3 |
| 2 |
| 50 |
| 7 |
=14×
| 50 |
| 7 |
=100;
(2)[1
| 1 |
| 10 |
| 7 |
| 20 |
| 1 |
| 12 |
| 9 |
| 23 |
| 1 |
| 6 |
=[
| 11 |
| 10 |
| 47 |
| 20 |
| 37 |
| 12 |
| 9 |
| 8 |
| 9 |
| 23 |
| 1 |
| 6 |
=[
| 11 |
| 10 |
| 47 |
| 20 |
| 24 |
| 47 |
| 9 |
| 23 |
| 1 |
| 6 |
=[
| 11 |
| 10 |
| 12 |
| 10 |
| 9 |
| 23 |
| 1 |
| 6 |
=
| 23 |
| 10 |
| 9 |
| 23 |
| 1 |
| 6 |
=
| 9 |
| 10 |
| 1 |
| 6 |
=
| 11 |
| 15 |
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