题目内容
解方程.
| x-12%x=2.816 |
|
分析:(1)原式变为(1-12%)x=2.816,即0.88x=2.816,根据等式的性质,两边同除以0.88即可;
(2)原式变为
-
x=
,根据等式的性质,两边同加上
x,得
x=
,两边同乘2即可.
(2)原式变为
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 20 |
| 1 |
| 2 |
| 1 |
| 2 |
| 3 |
| 20 |
解答:解:(1)x-12%x=2.816,
(1-12%)x=2.816,
0.88x=2.816,
0.88x÷0.88=2.816÷0.88,
x=3.2;
(2)
×
-
x=
,
-
x=
,
-
x+
x=
+
x,
+
x=
,
+
x-
=
-
,
x=
,
x×2=
×2,
x=
.
(1-12%)x=2.816,
0.88x=2.816,
0.88x÷0.88=2.816÷0.88,
x=3.2;
(2)
| 4 |
| 5 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 20 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 20 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 20 |
| 1 |
| 2 |
| 1 |
| 20 |
| 1 |
| 2 |
| 1 |
| 5 |
| 1 |
| 20 |
| 1 |
| 2 |
| 1 |
| 20 |
| 1 |
| 5 |
| 1 |
| 20 |
| 1 |
| 2 |
| 3 |
| 20 |
| 1 |
| 2 |
| 3 |
| 20 |
x=
| 3 |
| 10 |
点评:在解方程时应根据等式的性质,即等式两边同加上、同减去、同乘上或同除以某一个数(0除外),等式的两边仍相等,同时注意“=”上下要对齐.
练习册系列答案
相关题目