题目内容

递等式计算.
(1)
5
6
×0.25+
1
4
×
1
6

(2)25×
1
3
×
2
5
×
3
10

(3)3÷
1
2
-
1
4
×
3
10

(4)
3
5
÷[(
1
5
+
1
3
)÷
8
9
].
(1)
5
6
×0.25+
1
4
×
1
6

=
5
6
×
1
4
+
1
4
×
1
6

=(
5
6
+
1
6
)×
1
4

=1×
1
4

=
1
4


(2)25×
1
3
×
2
5
×
3
10

=(25×
2
5
)×(
1
3
×
3
10
),
=10×
1
10

=1;

(3)3÷
1
2
-
1
4
×
3
10

=6-
1
4
×
3
10

=6-
3
40

=5
37
40


(4)
3
5
÷[(
1
5
+
1
3
)÷
8
9
],
=
3
5
÷[
8
15
÷
8
9
],
=
3
5
÷
3
5

=1.
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