题目内容
解下列方程
| 2(x-4)=3(x-12) | x÷3+x÷2=6 | 0.4:x=(1+
|
(1)2(x-4)=3(x-12),
2x-8=3x-36,
2x-8+36=3x-36+36,
3x=2x+28,
3x-2x=2x+28-2x,
x=28;
(2)x÷3+x÷2=6,
(x÷3+x÷2)×6=6×6,
2x+3x=36,
5x=36,
5x÷5=36÷5,
x=7.2;
(3)0.4:x=(1+
| 1 |
| 7 |
(1+
| 1 |
| 7 |
| 8 |
| 7 |
| 8 |
| 7 |
| 8 |
| 7 |
| 8 |
| 7 |
x=
| 7 |
| 4 |
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