题目内容

解下列方程
2(x-4)=3(x-12)x÷3+x÷2=60.4:x=(1+
1
7
):5.

(1)2(x-4)=3(x-12),
2x-8=3x-36,
2x-8+36=3x-36+36,
3x=2x+28,
3x-2x=2x+28-2x,
x=28;

(2)x÷3+x÷2=6,
(x÷3+x÷2)×6=6×6,
2x+3x=36,
5x=36,
5x÷5=36÷5,
x=7.2;

(3)0.4:x=(1+
1
7
):5,
(1+
1
7
)x=0.4×5,
8
7
x=2,
8
7
8
7
=2÷
8
7

x=
7
4
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