题目内容
| 1 |
| 2 |
| 4 |
| 5 |
(1)当输入
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
(2)写出算式以及简单的计算过程.
(3)当输入
| 4 |
| 5 |
| 1 |
| 20 |
| 1 |
| 20 |
(4)写出算式以及简单的计算过程.
分析:(1)(2)
<
,应按照左边的运算进行求解,即
-
;
(3)(4)
>
,应按照右边的运算求解,即
-
.
| 1 |
| 2 |
| 3 |
| 4 |
| 3 |
| 4 |
| 1 |
| 2 |
(3)(4)
| 4 |
| 5 |
| 3 |
| 4 |
| 4 |
| 5 |
| 3 |
| 4 |
解答:解:(1)计算结果是
;
(2)
<
,计算过程:
-
=
-
=
=
;
(3)计算结果是
;
(4)
>
,计算过程:
-
=
-
=
.
故答案为:
;
.
| 1 |
| 4 |
(2)
| 1 |
| 2 |
| 3 |
| 4 |
| 3 |
| 4 |
| 1 |
| 2 |
| 3 |
| 4 |
| 2 |
| 4 |
| 3-2 |
| 4 |
| 1 |
| 4 |
(3)计算结果是
| 1 |
| 20 |
(4)
| 4 |
| 5 |
| 3 |
| 4 |
| 4 |
| 5 |
| 3 |
| 4 |
| 16 |
| 20 |
| 15 |
| 20 |
| 1 |
| 20 |
故答案为:
| 1 |
| 4 |
| 1 |
| 20 |
点评:本题主要考查了异分母分数加减法的计算方法:先通分,化成同分母的分数再相加减.
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