题目内容
脱式能简要简
|
|
|
5-
|
分析:算式(1)根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的;
算式(2)(3)可根据分数除法的运算法则将式中的除法算式变为乘法算式后,再根据乘法分配律计算;
算式(4)可根据一个数减两个数,等于减去这两个数的差的减法性质计算.
算式(2)(3)可根据分数除法的运算法则将式中的除法算式变为乘法算式后,再根据乘法分配律计算;
算式(4)可根据一个数减两个数,等于减去这两个数的差的减法性质计算.
解答:解:(1)
÷[1-(
+
)]
=
÷[1-
],
=
÷
,
=
×
,
=
;
(2)
-
×
+
÷2
=
-
×
+
×
,
=(1-
+
)×
,
=1×
,
=
;
(3)
÷2
+
×
+
×10
=
×
+
×
+
×10,
=(
+
+10)×
,
=(1+10)×
,
=11×
,
=5;
5-
÷
-
=5-
×
-
,
=5-
-
,
=5-(
+
),
=5-2,
=3.
| 3 |
| 5 |
| 1 |
| 3 |
| 2 |
| 5 |
=
| 3 |
| 5 |
| 11 |
| 15 |
=
| 3 |
| 5 |
| 4 |
| 15 |
=
| 3 |
| 5 |
| 15 |
| 4 |
=
| 9 |
| 4 |
(2)
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
=
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
=(1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
=1×
| 1 |
| 3 |
=
| 1 |
| 3 |
(3)
| 7 |
| 9 |
| 1 |
| 5 |
| 2 |
| 9 |
| 5 |
| 11 |
| 5 |
| 11 |
=
| 7 |
| 9 |
| 5 |
| 11 |
| 2 |
| 9 |
| 5 |
| 11 |
| 5 |
| 11 |
=(
| 7 |
| 9 |
| 2 |
| 9 |
| 5 |
| 11 |
=(1+10)×
| 5 |
| 11 |
=11×
| 5 |
| 11 |
=5;
5-
| 6 |
| 11 |
| 9 |
| 22 |
| 2 |
| 3 |
=5-
| 6 |
| 11 |
| 22 |
| 9 |
| 2 |
| 3 |
=5-
| 4 |
| 3 |
| 2 |
| 3 |
=5-(
| 4 |
| 3 |
| 2 |
| 3 |
=5-2,
=3.
点评:在完成脱式计算题目时要注意计算过程的完整性,中间不要有太大跳跃.
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