题目内容
计算:1-
-
-
-
-
-…-
.
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 1024 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:通过观察把原式变为1-(
+
+
+
+
+…+
),再把每个分数拆成两个分数相减的形式,然后通过加减相互抵消,求得结果.
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 1024 |
解答:
解:1-
-
-
-
-
-…-
=1-(
+
+
+
+
+…+
)
=1-(1-
+
-
+
-
+…+
-
)
=1-(1-
)
=
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 1024 |
=1-(
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 1024 |
=1-(1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 512 |
| 1 |
| 1024 |
=1-(1-
| 1 |
| 1024 |
=
| 1 |
| 1024 |
点评:此题解答的关键在于分数的拆分,通过加减相互抵消,进行简算.
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