题目内容
| 1 |
| 13 |
| 1 |
| 52 |
| 1 |
| 273 |
| 1 |
| 429 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:通过观察,这几个分数都可以提出
,于是原式变为
×(1-
-
-
),括号内通分计算,据此解答.
| 1 |
| 13 |
| 1 |
| 13 |
| 1 |
| 4 |
| 1 |
| 21 |
| 1 |
| 33 |
解答:
解:
-
-
-
=
×(1-
-
-
)
=
×(
-
-
)
=
×
=
| 1 |
| 13 |
| 1 |
| 52 |
| 1 |
| 273 |
| 1 |
| 429 |
=
| 1 |
| 13 |
| 1 |
| 4 |
| 1 |
| 21 |
| 1 |
| 33 |
=
| 1 |
| 13 |
| 3 |
| 4 |
| 1 |
| 21 |
| 1 |
| 33 |
=
| 1 |
| 13 |
| 709 |
| 924 |
=
| 709 |
| 12012 |
点评:每个分数提出
,是解答此题的关键.
| 1 |
| 13 |
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