题目内容
计算,能简算的要简算
(1)13-1
-1
(2)1-6÷3×
(3)75×80%+24×
+0.8
(4)(
+
+
)×24
(5)42
÷7
(6)1
÷(
+2
+
)
(7)33333×66666+77778×99999
(8)
+
+
+
+
+
+
.
(1)13-1
| 2 |
| 5 |
| 3 |
| 5 |
(2)1-6÷3×
| 1 |
| 3 |
(3)75×80%+24×
| 4 |
| 5 |
(4)(
| 1 |
| 3 |
| 1 |
| 6 |
| 5 |
| 8 |
(5)42
| 14 |
| 15 |
(6)1
| 1 |
| 8 |
| 1 |
| 4 |
| 1 |
| 2 |
| 4 |
| 5 |
(7)33333×66666+77778×99999
(8)
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 4×5 |
| 1 |
| 5×6 |
| 1 |
| 6×7 |
| 1 |
| 7×8 |
分析:(1)运用减法的性质简算;
(2)先算除法和乘法,再算减法;
(3)把百分数和分数化为小数,运用乘法分配律简算;
(5)把42
拆成42+
,运用除法的性质简算;
(6)先算括号内的,再算括号外的;
(7)把33333×66666=33333×3×22222=99999×22222,运用乘法分配律简算;
(8)通过观察,每个分数的分母为两个连续自然数的乘积,可以分别把它们拆分成两个分数相减的形式,然后通过加减相抵消的方法,求得结果.
(2)先算除法和乘法,再算减法;
(3)把百分数和分数化为小数,运用乘法分配律简算;
(5)把42
| 14 |
| 15 |
| 14 |
| 15 |
(6)先算括号内的,再算括号外的;
(7)把33333×66666=33333×3×22222=99999×22222,运用乘法分配律简算;
(8)通过观察,每个分数的分母为两个连续自然数的乘积,可以分别把它们拆分成两个分数相减的形式,然后通过加减相抵消的方法,求得结果.
解答:解:(1)13-1
-1
,
=13-(1
+1
),
=13-3,
=10;
(2)1-6÷3×
,
=1-6×
×
,
=1-
,
=
;
(3)75×80%+24×
+0.8,
=75×0.8+24×0.8+0.8,
=(75+24+1)×0.8,
=100×0.8,
=80;
(4)(
+
+
)×24,
=
×24+
×24+
×24,
=8+4+15,
=27;
(5)42
÷7,
=(42+
)÷7,
=42÷7+
÷7,
=6+
×
,
=6+
,
=6
;
(6)1
÷(
+2
+
),
=1
÷
,
=
×
,
=
;
(7)33333×66666+77778×99999,
=33333×3×22222+77778×99999,
=99999×22222+77778×99999
=99999×(22222+77778),
=99999×100000,
=9999900000;
(8)
+
+
+
+
+
+
,
=
-
+
-
+
-
+
-
+
-
+
-
+
-
,
=1-
,
=
.
| 2 |
| 5 |
| 3 |
| 5 |
=13-(1
| 2 |
| 5 |
| 3 |
| 5 |
=13-3,
=10;
(2)1-6÷3×
| 1 |
| 3 |
=1-6×
| 1 |
| 3 |
| 1 |
| 3 |
=1-
| 2 |
| 3 |
=
| 1 |
| 3 |
(3)75×80%+24×
| 4 |
| 5 |
=75×0.8+24×0.8+0.8,
=(75+24+1)×0.8,
=100×0.8,
=80;
(4)(
| 1 |
| 3 |
| 1 |
| 6 |
| 5 |
| 8 |
=
| 1 |
| 3 |
| 1 |
| 6 |
| 5 |
| 8 |
=8+4+15,
=27;
(5)42
| 14 |
| 15 |
=(42+
| 14 |
| 15 |
=42÷7+
| 14 |
| 15 |
=6+
| 14 |
| 15 |
| 1 |
| 7 |
=6+
| 2 |
| 15 |
=6
| 2 |
| 15 |
(6)1
| 1 |
| 8 |
| 1 |
| 4 |
| 1 |
| 2 |
| 4 |
| 5 |
=1
| 1 |
| 8 |
| 71 |
| 20 |
=
| 9 |
| 8 |
| 20 |
| 71 |
=
| 45 |
| 142 |
(7)33333×66666+77778×99999,
=33333×3×22222+77778×99999,
=99999×22222+77778×99999
=99999×(22222+77778),
=99999×100000,
=9999900000;
(8)
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 4×5 |
| 1 |
| 5×6 |
| 1 |
| 6×7 |
| 1 |
| 7×8 |
=
| 1 |
| 1 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 8 |
=1-
| 1 |
| 8 |
=
| 7 |
| 8 |
点评:解答四则混合运算的题目,应仔细观察,根据题目的特点,灵活巧妙地解答.
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