题目内容
用递等式计算:
(1)1
×[21÷(4
-2.625)-4
]÷3
(2)(2
-1
)÷[(3
+4.375)÷19
]
(3)
÷2
-1.4×
+7+
×20%.
(1)1
| 1 |
| 3 |
| 1 |
| 12 |
| 1 |
| 2 |
| 3 |
| 5 |
(2)(2
| 5 |
| 8 |
| 4 |
| 7 |
| 1 |
| 12 |
| 8 |
| 9 |
(3)
| 10 |
| 13 |
| 19 |
| 22 |
| 11 |
| 13 |
| 22 |
| 63 |
(1)1
×[21÷(4
-2.625)-4
]÷3
,
=1
×[21÷
-4
]÷3
,
=1
×[
-4
]÷3
,
=1
×
×
,
=
;
(2)(2
-1
)÷[(3
+4.375)÷19
],
=1
÷[7
÷19
],
=
÷
,
=
;
(3)
÷2
-1.4×
+7+
×20%,
=
×
-
×
+7+
×
,
=7+(
+
)×
-
×
,
=7+
×
-
×
,
=7+
-
,
=7
-1
,
=6
.
| 1 |
| 3 |
| 1 |
| 12 |
| 1 |
| 2 |
| 3 |
| 5 |
=1
| 1 |
| 3 |
| 35 |
| 24 |
| 1 |
| 2 |
| 3 |
| 5 |
=1
| 1 |
| 3 |
| 72 |
| 5 |
| 1 |
| 2 |
| 3 |
| 5 |
=1
| 1 |
| 3 |
| 99 |
| 10 |
| 5 |
| 18 |
=
| 11 |
| 3 |
(2)(2
| 5 |
| 8 |
| 4 |
| 7 |
| 1 |
| 12 |
| 8 |
| 9 |
=1
| 3 |
| 56 |
| 11 |
| 24 |
| 8 |
| 9 |
=
| 59 |
| 56 |
| 3 |
| 8 |
=
| 59 |
| 21 |
(3)
| 10 |
| 13 |
| 19 |
| 22 |
| 11 |
| 13 |
| 22 |
| 63 |
=
| 10 |
| 13 |
| 22 |
| 63 |
| 7 |
| 5 |
| 11 |
| 13 |
| 22 |
| 63 |
| 1 |
| 5 |
=7+(
| 10 |
| 13 |
| 1 |
| 5 |
| 22 |
| 63 |
| 7 |
| 5 |
| 11 |
| 13 |
=7+
| 63 |
| 65 |
| 22 |
| 63 |
| 7 |
| 5 |
| 11 |
| 13 |
=7+
| 22 |
| 65 |
| 77 |
| 65 |
=7
| 22 |
| 65 |
| 12 |
| 65 |
=6
| 2 |
| 13 |
练习册系列答案
相关题目