题目内容
比较大小:
×
×
×
×…×
.
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考点:分数的巧算
专题:计算问题(巧算速算)
分析:此题可以借助一个算式进行判断,假设A=
×
×
×
×…×
,B=
×
×
×…×
×
×
,C=
,先比较A和B中每项的大小,进而得出A和B的大小,进一步比较得出A小于
,问题即可得解.
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解答:
解:假设A=
×
×
×
×…×
,B=
×
×
×…×
×
×
,
且
<
,
<
,…
<
,
<
,
所以A<B;
又:A×B=
,
故:A×A<
,
所以,A<
,
即
×
×
×
×…×
<
;
故答案为:<.
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| 99 |
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且
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所以A<B;
又:A×B=
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故:A×A<
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| 101 |
所以,A<
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即
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| 100 |
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故答案为:<.
点评:解答此题的关键是:借助一个算式B=
×
×
×…×
×
,比较A和B中每项的大小,再根据分数乘法的规律解决问题.
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