题目内容
27×
|
|
25
|
|
分析:第一题要运用乘法的分配律把27改写成28-1然后运用公式计算,第二、三个题目运用乘法的分配律计算,第四个题目运用乘法的交换律结合律进行计算.
解答:解:(1)27×
,
=(28-1)×
,
=28×
-
×1,
=26
;
(2)
×
+
×
,
=
×(
+
),
=
;
(3)25
×8,
=(25+
)×8
=25×8+8×
,
=200+3,
=203;
(4)
×(15×
)×
,
=(
×
)×(15×
),
=
×2,
=
.
| 27 |
| 28 |
=(28-1)×
| 27 |
| 28 |
=28×
| 27 |
| 28 |
| 27 |
| 28 |
=26
| 1 |
| 28 |
(2)
| 4 |
| 7 |
| 6 |
| 13 |
| 3 |
| 7 |
| 6 |
| 13 |
=
| 6 |
| 13 |
| 4 |
| 7 |
| 3 |
| 7 |
=
| 6 |
| 13 |
(3)25
| 3 |
| 8 |
=(25+
| 3 |
| 8 |
=25×8+8×
| 3 |
| 8 |
=200+3,
=203;
(4)
| 2 |
| 27 |
| 27 |
| 28 |
| 2 |
| 15 |
=(
| 2 |
| 27 |
| 27 |
| 28 |
| 2 |
| 15 |
=
| 1 |
| 14 |
=
| 1 |
| 7 |
点评:本题主要考查乘法分配律及乘法交换律结合律的运用.
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