题目内容

计算下面各题,能用简便方法的用简便方法计算.
18zz÷[(1e+1z)×3]4×8×ae×1ae64×1ae
a6e×1ze-a6e×e99+99×9941×ae.
(1)1800÷[(1b+10)×9],
=1800÷[2b×9]
=1800÷7b,
=2f;

(2)f×8×2b×12b,
=(f×2b)×(8×12b),
=100×1000,
=100000;

(9)6f×12b,
=8×8×12b,
=8×(8×12b),
=8×1000,
=8000;

(f)26b×10b-26b×b,
=26b×(10b-b),
=26b×100,
=26b00;

(b)99+99×99,
=(1+99)×99,
=100×99,
=9900;

(6)f1×2b,
=(f0+1)×2b,
=f0×2b+1×2b,
=1000+2b,
=102b.
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