题目内容
(4
| 51.6÷[(3
| ||||||||||||
(0.92+
| (5
|
(1)(4
-3
)÷(
+
),
=
÷
,
=
;
(2)51.6÷[(3
-1.25)×
],
=51.6÷[2.15×
],
=51.6÷1.72,
=30;
(3)(0.92+
)÷(4-2
),
=1÷
,
=
;
(4)(5
-1.8)÷[(1.15+
)×1
],
=3.6÷[1.8×
],
=3.6÷3,
=1.2.
| 5 |
| 6 |
| 3 |
| 4 |
| 3 |
| 14 |
| 2 |
| 7 |
=
| 13 |
| 12 |
| 1 |
| 2 |
=
| 13 |
| 6 |
(2)51.6÷[(3
| 2 |
| 5 |
| 4 |
| 5 |
=51.6÷[2.15×
| 4 |
| 5 |
=51.6÷1.72,
=30;
(3)(0.92+
| 2 |
| 25 |
| 7 |
| 9 |
=1÷
| 11 |
| 9 |
=
| 9 |
| 11 |
(4)(5
| 2 |
| 5 |
| 13 |
| 20 |
| 2 |
| 3 |
=3.6÷[1.8×
| 5 |
| 3 |
=3.6÷3,
=1.2.
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