题目内容
| 脱试计算.(能简算得要简算) 807×99+807 | (
| 3
| ||||||||||||
[
| 506÷(207×42-8692) | 2÷
|
考点:分数的四则混合运算
专题:运算顺序及法则
分析:(1)(2)运用乘法分配律简算;
(3)根据加法交换律、结合律以及减法的性质简算;
(4)先算小括号里面的加法,再算中括号内的减法,最后算除法;
(5)先算小括号里面的乘法、加法,再算括号外的除法;
(6)根据除法的性质简算.
(3)根据加法交换律、结合律以及减法的性质简算;
(4)先算小括号里面的加法,再算中括号内的减法,最后算除法;
(5)先算小括号里面的乘法、加法,再算括号外的除法;
(6)根据除法的性质简算.
解答:
解:(1)807×99+807
=807×(99+1)
=807×100
=80700;
(2)(
+
)×14×16
=
×14×16+
×14×16
=48+14
=62;
(3)3
-5.64+3
-2.36
=(3
+3
)-(5.64+2.36)
=7-8
=-1;
(4)[
-(
+
)]÷
=[
-
]÷
=
÷
=
;
(5)506÷(207×42-8692)
=506÷(8694-8692)
=506÷2
=253;
(6)2÷
÷
=2÷(
×
)
=2÷
=6.
=807×(99+1)
=807×100
=80700;
(2)(
| 3 |
| 14 |
| 1 |
| 16 |
=
| 3 |
| 14 |
| 1 |
| 16 |
=48+14
=62;
(3)3
| 1 |
| 7 |
| 6 |
| 7 |
=(3
| 1 |
| 7 |
| 6 |
| 7 |
=7-8
=-1;
(4)[
| 7 |
| 8 |
| 1 |
| 2 |
| 1 |
| 4 |
| 9 |
| 16 |
=[
| 7 |
| 8 |
| 3 |
| 4 |
| 9 |
| 16 |
=
| 1 |
| 8 |
| 9 |
| 16 |
=
| 2 |
| 9 |
(5)506÷(207×42-8692)
=506÷(8694-8692)
=506÷2
=253;
(6)2÷
| 4 |
| 25 |
| 25 |
| 12 |
=2÷(
| 4 |
| 25 |
| 25 |
| 12 |
=2÷
| 1 |
| 3 |
=6.
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
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