题目内容
解方程:
÷X=
;
36-
X=18;
4X÷
=
.
| 30 |
| 7 |
| 1 |
| 14 |
36-
| 2 |
| 3 |
4X÷
| 3 |
| 4 |
| 9 |
| 2 |
分析:(1)根据等式的性质,在方程两边同时乘上x,再乘上14来解.
(2)根据等式的性质,在方程两边同时加上
x,再减去18,最后乘上
来解.
(3)根据等式的性质,在方程两边同时乘上
,再除以4来解.
(2)根据等式的性质,在方程两边同时加上
| 2 |
| 3 |
| 3 |
| 2 |
(3)根据等式的性质,在方程两边同时乘上
| 3 |
| 4 |
解答:解:(1)
÷x=
,
÷ x×x=
×x,
x=
,
x×14=
×14,
x=60;
(2 )36-
x=18,
36-
x+
x=18+
x,
18+
x-18=36-18,
x×
=18×
,
x=27;
(3)4x÷
=
,
4x÷
×
=
×
,
4x÷4=
÷4,
x=
.
| 30 |
| 7 |
| 1 |
| 14 |
| 30 |
| 7 |
| 1 |
| 14 |
| 1 |
| 14 |
| 30 |
| 7 |
| 1 |
| 14 |
| 30 |
| 7 |
x=60;
(2 )36-
| 2 |
| 3 |
36-
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
18+
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 2 |
| 3 |
| 2 |
x=27;
(3)4x÷
| 3 |
| 4 |
| 9 |
| 2 |
4x÷
| 3 |
| 4 |
| 3 |
| 4 |
| 9 |
| 2 |
| 3 |
| 4 |
4x÷4=
| 27 |
| 8 |
x=
| 27 |
| 32 |
点评:本题考查了学生利用等式的性质解方程的能力,注意等号要对齐.
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