题目内容
求未知数x.
2x÷
=
×
x+
x=14.
2x÷
| 3 |
| 8 |
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 2 |
| 3 |
分析:(1)先化简方程,再根据等式的性质,两边同时乘
,再除以2求解即可;
(2)先化简方程,再根据等式的性质,两边同时除以
求解即可.
| 3 |
| 8 |
(2)先化简方程,再根据等式的性质,两边同时除以
| 7 |
| 6 |
解答:解:(1)2x÷
=
×
,
2x÷
=
,
2x÷
×
=
×
,
2x=
,
x=
;
(2)
x+
x=14,
x=14,
x÷
x=14÷
,
x=12.
| 3 |
| 8 |
| 2 |
| 3 |
| 1 |
| 4 |
2x÷
| 3 |
| 8 |
| 1 |
| 6 |
2x÷
| 3 |
| 8 |
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 8 |
2x=
| 1 |
| 16 |
x=
| 1 |
| 32 |
(2)
| 1 |
| 2 |
| 2 |
| 3 |
| 7 |
| 6 |
| 7 |
| 6 |
| 7 |
| 6 |
| 7 |
| 6 |
x=12.
点评:此题考查了在解方程时应根据等式的性质求解,同时注意“=”上下要对齐.
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